Simplification Questions for SBI Clerk Set-2 PDF
Download SBI Clerk Simplification Questions & Answers PDF for SBI Clerk Prelims and Mains exam. Very Important SBI Clerk Maths Questions with solutions.
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Question 1: If 2x + 5y = 109 and 2x + 5 = y + 12 then y – x = ?
a) 7
b) 6
c) 8
d) 9
e) None of these
Question 2: $\frac{\sqrt{7744} \times 66}{203+149}=?$
a) 15
b) 18.5
c) 20
d) 16.5
e) None of these
Question 3: What is the value of (x) in the following equation?
$\frac{(x)^{0.7}}{36}=\frac{9}{(x)^{1.3}}$
a) 17
b) 19
c) 16
d) 14
e) None of these
Question 4: Which value of x does satisfy the inequality $2x^{2} + x – 3 < 0$?
a) -3/2<x<1
b) -1<x<2/3
c) x>1
d) x<-2/5
e) None of these
Question 5: $7^{2} + 3^{4} – 4^{3} = ? – 11^{2}$
a) 55
b) 196
c) 172
d) 187
e) None of these
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Question 6: 1/5 of 2/7 of 8/3 of 4095 ?
a) 642
b) 598
c) 648
d) 475
e) None of these
Question 7: $\sqrt{3969}$ $\div$ 1.4 = ? $\times$ 2.5
a) 18
b) 112.5
c) 16
d) 24
e) None of these
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Question 8: If 3y + 2x = 47 and 11x = 7y then what is value of y – x ?
a) 4
b) 6
c) 7
d) 5
e) None of these
Question 9: If 2x + 3y + z = 55, x+ z- y = 4 and y – x + z = 12, then what is the value of y ?
a) 7
b) 8
c) 12
d) 9
e) None of these
Instructions
In each of the questions a pair of equations is given. You have to find out the values of x and y and give answer.
Question 10: I. $2x^2 – 7x + 6 = 0$ II. $4y^2 = 9$
a) if $x < y$
b) if $x\leq y$
c) if $x = y$
d) if $x > y$
e) if $x\geq y$
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Answers & Solutions:
1) Answer (E)
$2x + 5y = 109$ —————Eqn(1)
$2x + 5 = y + 12$
=> $2x – y = 7$ —————-Eqn(2)
Subtracting eqn(2) from eqn(1), we get :
=> $6y = 102$
=> $y = 17$ and $x = 12$
$\therefore$ $y – x = 17 – 12 = 5$
2) Answer (D)
Expression : $\frac{\sqrt{7744} \times 66}{203+149}=?$
= $\frac{88 \times 66}{352}$
= $\frac{66}{4} = 16.5$
3) Answer (E)
Expression : $\frac{(x)^{0.7}}{36}=\frac{9}{(x)^{1.3}}$
=> $(x)^{0.7 + 1.3} = 9 \times 36$
=> $(x)^2 = 324$
=> $x = \sqrt{324} = 18$
4) Answer (A)
Inequality : $2x^{2} + x – 3 < 0$
=> $2x^2 – 2x + 3x – 3 < 0$
=> $2x (x – 1) + 3 (x – 1) < 0$
=> $(2x + 3) (x – 1) < 0$
=> $\frac{-3}{2} < x < 1$
5) Answer (D)
Let unknown quantity be ‘x’.
$7^{2} + 3^{4} – 4^{3} =x- 11^{2}$.
$49+81-64=x-121$.
$x=187$.
Hence, Option D is correct.
6) Answer (E)
1/5 of 2/7 of 8/3 of 4095.
=$\frac{1}{5}\times\frac{2}{7}\times\frac{8}{3}\times4095$.
=$624$.
Hence, Option E is correct.
7) Answer (A)
Let the unknown quantity be $’x’$.
$\sqrt{3969}\div1.4 = x\times2.5$.
$63\div1.4=x\times2.5$.
$x=45\div2.5$.
$x=18$.
Hence, Option A is correct.
8) Answer (A)
This is a system of two equations with two unknowns.
3y + 2x = 47 and
11x = 7y
Multiplying the first equation by 7, we get 21y + 14x = 329
And, multiplying the second equation by 3, we get 33x = 21y
So, 21y + 14x = 329 or 33x + 14x = 329
Hence, 47x = 329
So, x = 7 and y = 11
Therefore, y-x = 4 and the correct answer is option (a)
9) Answer (E)
We have a group of three equations in three unknowns.
2x + 3y + z = 55,
x+ z- y = 4
and y – x + z = 12
Adding the second and third equations together, we get 2z = 16 or z = 8
Adding the first equation and twice the third equation, we get (2x + 3y + z) + 2*(y-x+z) = 55 + 2*12 = 79
Hence, 5y + 3z = 79.
As z=8, it implies that 5y = 55 or y=11
As this is not given in any of the options, the correct answer is option (e)
10) Answer (E)
I. $2x^2 – 7x + 6 = 0$ II. $4y^2 = 9 $
1 implies $2x^2 – 4x – 3x + 6 = 0$
So, (2x – 3)(x-2) = 0
ie x = 3/2 or x = 2
2 implies y = $ \pm \frac{3}{2}$
So, $ x \geq y $
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