**Ratio and Proportions Questions for RRB NTPC Set-4 PDF**

Download RRB NTPC Ratio and Proportions Questions Set-4 PDF. Top 10 RRB NTPC questions based on asked questions in previous exam papers very important for the Railway NTPC exam.

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**Question 1: **If the ratio of cost price and selling price of an article be as 10:11, the percentage of profit is

a) 8

b) 10

c) 11

d) 15

**Question 2: **A shopkeeper earns a profit of 12% on selling a book at 10% discount on the printed price. The ratio of the cost price and the printed price of the book is

a) 45:56

b) 45:51

c) 47:56

d) 47:51

**Question 3: **Two natural numbers are in the ratio 3:5 and their product is 2160. The smaller of the numbers is

a) 36

b) 24

c) 18

d) 12

**Question 4: **If Rs. 1000 is divided between A and B in the ratio 3:2, then A will receive

a) Rs. 400

b) Rs. 500

c) Rs. 600

d) Rs. 800

**Question 5: **What must be added to each term of the ratio 7:11, so as to make it equal to 3:4 ?

a) 8

b) 7.5

c) 6.5

d) 5

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**Question 6: **Two number are in the ratio 7:1 1. If 7 is added to each of the numbers, the ratio becomes 2:3. The smaller number is

a) 39

b) 49

c) 66

d) 77

**Question 7: **If an article is sold at 200% profit, then the ratio of its cost price to its selling price will be:

a) 1:2

b) 2:1

c) 1:3

d) 3:1

**Question 8: **The ratio of milk and water in mixtures of four containers are 5:3, 2:1, 3:2 and 7:4 respectively. In which container is the quantity of milk, relative to water, minimum?

a) First

b) Second

c) Third

d) Fourth

**Question 9: **Two numbers are in the ratio 1:3. If their sum is 240, then their difference is:

a) 120

b) 108

c) 100

d) 96

**Question 10: **The ratio of income and expenditure of a person is 11:10. If he saves IRS. 9,000 per annum. his monthly income is:

a) Rs. 8,000

b) Rs. 8,800

c) Rs. 8,500

d) Rs. 8,250

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**Answers & Solutions:**

**1) Answer (B)**

Let the cost price be 10*x* and selling price be 11*x*

Percentage Profit = $\frac{11x – 10x}{10x}$ x 100 = 10

**2) Answer (A)**

Given: Profit = 12%

Discount on printed price = 10%

Let’s say cost price is $x$ and printed price is $y$

hence sold price will be $x$ + $\frac{12x}{100}$ and $y$ – $\frac{10y}{100}$

Both should be equal:

hence $x$ + $\frac{12x}{100}$ = $y$ – $\frac{10y}{100}$

$\frac{x}{y}$ = $\frac{45}{56}$

**3) Answer (A)**

Given:

Ratio of two numbers = 3:5

Hence we can say first number is $3x$ and second number is $5x$

Product of two numbers is = 2160

or $15x^{2}$ = 2160

or $x$ = 12

hence numbers will be 30 and 60

**4) Answer (C)**

Given: ratio of A and B is 3:2 and total money to be divided 1000

let’s say A received $3x$ and B received $2x$

hence $3x$ + $2x$ = 1000

or $x$ = 200

hence A will receive 600

**5) Answer (D)**

Given: Terms are in ratio 7:11

let’s say first term $7x$ and second term $11x$

adding $y$ to each term, it will be $7x+y$ and $11x+y$

and its ratio will be 3:4

hence $7x+y$ : $11x+y$ = 3:4

on solving above equation we get $5x$ = $y$

hence adding number should be a multiple of 5.

answer will be (D)

**6) Answer (B)**

Let’s say numbers are $7x$ and $11x$

adding 7 to each of them

hence $\frac{7x+7}{11x+7}$ = $\frac{2}{3}$

or $x$ = 7

smaller digit will be 49

**7) Answer (C)**

As we know cost price + profit = selling price

let’s say cost price is $x$

as profit is 200% on cost price it will be $2x$

hence selling price will be 3x and ratio of cost price to selling price will be 1:3

**8) Answer (C)**

In first container quantity of milk relative to water is $\frac{5}{3} \times100$ = 166.65%

In second container quantity of milk relative to water is $\frac{2}{1} \times100$ = 200%

In third container quantity of milk relative to water is $\frac{2}{1} \times100$ = 150%

In fourth container quantity of milk relative to water is $\frac{7}{4} \times100$ = 175%

hence third container has least ratio

**9) Answer (A)**

let’s say one number is $x$ and another is $3x$

summation will be $4x$ = 240

$x$ = 60

hence number will be 60 and 180

and difference will be 120.

**10) Answer (D)**

let’s say income is $11x$ and expenditure is $10x$ hence saving will be $x$

so when saving is $x$, annual income is $11x$

now when saving is 9000 , annual income will be 99000

and monthly income will be 8,250

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