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# Quadratic Equation Questions For IBPS RRB Clerk

Download Top-20 IBPS RRB Clerk Quadratic Equation Questions PDF. Quadratic Equation questions based on asked questions in previous year exam papers very important for the IBPS RRB Assistant exam

Instructions

In each of these questions, two equations are given. You have to solve these equations and find out the values of x and y and give answer

Question 1: I: $x^2-2x-323=0$
II: $y^2-40y+399=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established

Question 2: I: $\sqrt{x-14}+\sqrt{1444}=\sqrt{2116}$
II: $\dfrac{\sqrt{y}}{\sqrt{3}{y}}=64^\frac{1}{18}$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established

Question 3: I: $x^2-170x+7221=0$
II: $3y^2+170y+2407=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established

Question 4: I: $x^2+12\sqrt{11}+143=0$
II: $y^2-22\sqrt{3}y+360=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Question 5: I: $x^3-128=1727872$
II: $\sqrt{3}{y^2} = \dfrac{\sqrt{2}{y^3}}{121^\frac{5}{6}}$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Instructions

In each of these questions, two equations are given. You have to solve these equations and find out the values of x and y and give answer

Question 6: I: $x^2-x-812=0$
II: $y^2+y-1332=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Question 7: I: $x^2+0.25x-60=0$
II: $y^2-0.33y-8=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Question 8: I: $\sqrt{x+14}+\sqrt{841} = \sqrt{1369}$
II: $y^2+0.5y-60=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Question 9: I: $x^2-16\sqrt{5}x+300=0$
II: $y^2-31\sqrt{5}y+750=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Question 10: I: $6\sqrt{x}+\dfrac{5}{\sqrt{x}} = \sqrt{x}$
II: $\dfrac{2^\frac{5}{9}}{\sqrt[3]{y}} = y^\frac{2}{9}$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Instructions

In each of these questions, two equations are given. You have to solve these equations and find out the values of x and y and give answer

Question 11: I: $x^2+15\sqrt{3}x-378=0$
II: $y^2-6\sqrt{2}y-224=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Question 12: I: $\dfrac{19}{\sqrt{x}}+\dfrac{18}{\sqrt{x}}=\sqrt{x}$
II: $\dfrac{1369}{\sqrt{y^{-1}}} = y^\frac{5}{2}$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Question 13: I: $3x^2-76x+481=0$
II: $y^2+6y-187=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Question 14: I: $x^2+3x-270=0$
II: $y^2+4y-285=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Question 15: I: $x = \sqrt{9604}$
II: $y^2 = 7569$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Instructions

In each of these questions, two equations are given. You have to solve these equations and find out the values of x and y and give answer

Question 16: I: $3x^2+5x-68=0$
II: $y^2-33y+272=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Question 17: I: $x^2+6x-1147=0$
II: $y^2-6x-667=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Question 18: I: $x^2=13456$
II: $y=\sqrt{15129}$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Question 19: I: $2x^2-3x-629=0$
II: $y^2-4y-252=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

Question 20: I: $x^2+x-306 = 0$
II: $y^2+5y-696=0$

a) x is greater than y

b) x is less than y

c) x is greater than or equal to y

d) x is less than or equal to y

e) x is equal to y (or) The relationship between x and y cannot be established.

I: $x^2-2x-323=0$
$x^2-19x+17x-323=0$
$x(x-19)+17(x-19)=0$
$(x-19)(x+17)=0$
$x=19$ or $x=-17$

II: $y^2-40y+399=0$
$y^2-19y-21y+399=0$
$y(y-19)-21(y-19)=0$
$(y-19)(y-21)=0$
$y=19$ or $y=21$

Comparing x and y,
$19 = 19$
$19 < 21$
$-17 < 19$
$-17 < 21$
Therefore, x is less than or equal to y.

I: $\sqrt{x-14}+\sqrt{1444}=\sqrt{2116}$
$\sqrt{x-14}+38=46$
$\sqrt{x-14}=8$
$x-14=64$
$x=78$

II: $\dfrac{\sqrt{y}}{\sqrt{3}{y}}=64^\frac{1}{18}$

$\dfrac{y^\frac{1}{2}}{y^\frac{1}{3}} = (64^\frac{1}{3})^\frac{1}{6}$

$y^\frac{1}{6} = 4^\frac{1}{6}$
$y=4$

Comparing x and y,
$78>4$
Therefore,x is greater than y.

I: $x^2-170x+7221=0$
$x^2-87x-83x+7221=0$
$x(x-87)-83(x-87)=0$
$(x-87)(x-83)=0$
$x=87$ or $x=83$

II: $3y^2+170y+2407=0$
$3y^2+87y+83y+2407=0$
$3y(y+29)+83(y+29)=0$
$(y+29)(3y+83)=0$
$y=-29$ or $y=-\dfrac{83}{3}$

Comparing x and y
$87>-29$
$87>-\dfrac{83}{3}$
$83>-29$
$83>-\dfrac{83}{3}$
Therefore, x is greater than y.

I: $x^2+12\sqrt{11}+143=0$
$x^2+13\sqrt{11}x+\sqrt{11}x+143=0$
$x(x+13\sqrt{11})+\sqrt{11}(x+13\sqrt{11})=0$
$(x+13\sqrt{11})(x+\sqrt{11})=0$
$x=-13\sqrt{11}$ or $x=-\sqrt{11}$
The approximate value of $\sqrt{11} = 3$
Then, $x=-39$ or $x=-3$

II: $y^2-22\sqrt{3}y+360=0$
$y^2-20\sqrt{3}y-12\sqrt{3}y+360=0$
$y(y-20\sqrt{3})-12\sqrt{3}(y-20\sqrt{3})=0$
$(y-20\sqrt{3})(y-12\sqrt{3})=0$
$y=20\sqrt{3}$ or $y=12\sqrt{3}$
The approximate value of $\sqrt{3}=1$
Then, $x=20$ or $x=12$

Comparing x and y,
Both the x values are negative and both the y values are positive.
Therefore, x is less than y.

I: $x^3-128=1727872$
$x^3 = 1728000$
$x=120$

II: $\sqrt{3}{y^2} = \dfrac{\sqrt{2}{y^3}}{121^\frac{5}{6}}$

$y^\frac{2}{3} = \dfrac{y^\frac{3}{2}}{121^\frac{5}{5}}$

$y^{\frac{3}{2}-\frac{2}{3}} = 121^\frac{5}{6}$
$y^\frac{5}{6}=121^\frac{5}{6}$
$y = 121$

Comparing x and y,
$120 < 121$.
Therefore, x is less than y.

I: $x^2-x-812=0$
$x^2-29x+28x-812=0$
$x(x-29)+28(x-29)=0$
$(x-29)(x+28)=0$
$x=29$ or $x=-28$

II: $y^2+y-1332=0$
$y^2+37y-36y-1332=0$
$y(y+37)-36(y+37)=0$
$(y+37)(y-36)=0$
$y=-37$ or $y=36$

Comparing x and y,
$29>-37$
$29<36$
$-28>-37$
$-29<36$

Therefore, The relationship between x and y cannot be established.

I: $x^2+0.25x-60=0$
$x^2+\dfrac{x}{4}-60=0$

$4x^2+x-240=0$
$4x^2+16x-15x-240=0$
$4x(x+16)-15(x+16)=0$
$(x+16)(4x-15)=0$
$x=-16$ or $x=\dfrac{15}{4}$

II: $y^2-0.33y-8=0$
$y^2-\dfrac{y}{3}-8=0$

$3y^2-y-24=0$
$3y^2-9y+8y-24=0$
$3y(y-3)+8(y-3)=0$
$(y-3)(3y+8)=0$
$y=3$ or $y=\dfrac{-8}{3}$

Comparing x and y
$-16<3$
$-16$\dfrac{15}{4}>3\dfrac{15}{4}>\dfrac{-8}{3}$Therefore, The relationship between x and y cannot be established. 8) Answer (A) I:$\sqrt{x+14}+\sqrt{841} = \sqrt{1369}\sqrt{x+14}+29=37\sqrt{x+14}=8x+14=64x=40$II:$y^2+0.5y-60=02y^2+y-120=02y^2+16y-15y-120=02y(y+8)-15(y+8)=0(y+8)(2y-15)=0y=-8$or$y=\dfrac{15}{2}=7.5$Comparing x and y$40 > -840 > 7.5$Therefore, x is greater than y. 9) Answer (E) I:$x^2-16\sqrt{5}x+300=0x^2-10\sqrt{5}x-6\sqrt{5}x+300=0x(x-10\sqrt{5})-6\sqrt{5}(x-10\sqrt{5})=0(x-10\sqrt{5})(x-6\sqrt{5})=0x=10\sqrt{5}$or$x=6\sqrt{5}$II:$y^2-31\sqrt{5}y+750=0y^2-25\sqrt{5}y-6\sqrt{5}y+750=0y(y-25\sqrt{5})-6\sqrt{5}(y-25\sqrt{5})=0(y-25\sqrt{5})(y-6\sqrt{5})=0y=25\sqrt{5}$or$y=6\sqrt{5}$Comparing x and y,$10\sqrt{5} < 25\sqrt{5}10\sqrt{5} > 6\sqrt{5}6\sqrt{5} < 25\sqrt{5}6\sqrt{5}=6\sqrt{5}$Therefore, The relationship between x and y cannot be determined. 10) Answer (B) I:$6\sqrt{x}+\dfrac{5}{\sqrt{x}} = \sqrt{x}\dfrac{6x+5}{\sqrt{x}} = \sqrt{x}6x+5=x5x=-5x=-1$II:$\dfrac{2^\frac{5}{9}}{\sqrt[3]{y}} = y^\frac{2}{9}2^\frac{5}{9} = y^\frac{2}{9} \times y^\frac{1}{3}2^\frac{5}{9} = y^\frac{5}{9}y=2$By comparing x and y,$-1<2$Therefore, x is less than y. 11) Answer (E) I:$x^2+15\sqrt{3}x-378=0x^2+21\sqrt{3}x-6\sqrt{3}x-378=0x(x+21\sqrt{3})-6\sqrt{3}(x+21\sqrt{3})=0(x+21\sqrt{3})(x-6\sqrt{3})=0x=-21\sqrt{3}$or$x=6\sqrt{3}$Approximate value of$\sqrt{3}=2$. Then,$x = -21\times2 = -42$or$x = 6\times2 = 12$II:$y^2-6\sqrt{2}y-224=0y^2-14\sqrt{2}y+8\sqrt{2}y-224=0y(y-14\sqrt{2})+8\sqrt{2}(y-14\sqrt{2})=0(y-14\sqrt{2})(y+8\sqrt{2})=0y=14\sqrt{2}$or$y=-8\sqrt{2}$Approximate value of$\sqrt{2} = 1$Then,$y = 14$or$y = -8$By comparing x and y,$-42 < 14-42 < -812 < 1412 > -8$Therefore, The relationship between x and y cannot be determined. 12) Answer (C) I:$\dfrac{19}{\sqrt{x}}+\dfrac{18}{\sqrt{x}}=\sqrt{x}\dfrac{19+18}{\sqrt{x}} = \sqrt{x}x=37$II:$\dfrac{1369}{\sqrt{y^{-1}}} = y^\frac{5}{2}\dfrac{1369}{y^\frac{-1}{2}} = y^\frac{5}{2}y^\frac{5-1}{2} = 1369y^2 = 1369y = -37$or$y = +37$By comparing x and y,$37 > -3737 = 37$Therefore, x is greater than or equal to y. 13) Answer (A) I:$3x^2-76x+481=03x^2-39x-37x+481=03x(x-13)-37(x-13)=0(x-13)(3x-37)=0x=13$or$x=\dfrac{37}{3}$II:$y^2+6y-187=0y^2+17y-11y-187=0y(y+17)-11(y+17)=0(y+17)(y-11)=0y=-17$or$y=11$By comparing x and y,$13>-1713>11\dfrac{37}{3}>-17\dfrac{37}{3}>11$Therefore, x is greater than y. 14) Answer (E) I:$x^2+3x-270=0x^2+18x-15x-270=0x(x+18)-15(x+18)=0(x-15)(x+18)=0x=15$or$x=-18$II:$y^2+4y-285=0y^2+19y-15y-285=0y(y+19)-15(y+19)=0(y-15)(y+19)=0y=15$or$y=-19$By comparing x and y,$15=1515>-19-18<15-18>-19$Therefore, The relationship between x and y cannot be established. 15) Answer (A) I:$x = \sqrt{9604}x = 98$II:$y^2 = 7569y = \pm 87y = -87$or$y=87$By comparing x and y,$98 > -8798 > 87$Therefore, x is greater than y. 16) Answer (B) I:$3x^2+5x-68=03x^2-12x+17x-68=03x(x-4)+17(x-4)=0(x-4)(3x+17)=0x=4$or$x=\dfrac{-17}{3}$II:$y^2-33y+272=0y^2-16y-17y+272=0y(y-16)-17(y-16)=0(y-16)(y-17)=0y=16$or$y=17$By comparing x and y values,$4 < 164 <17\dfrac{-17}{3}<16\dfrac{-17}{3}<17$Therefore, x is less than y. 17) Answer (E) I:$x^2+6x-1147=0x^2+37x-31x-1147=0x(x+37)-31(x+37)=0(x+37)(x-31)=0x=-37$or$x=31$II:$y^2-6x-667=0y^2-29y+23y-667=0y(y-29)+23(y-29)=0(y-29)(y+23)=0y=29$or$y=-23$By comparing x and y,$-37 < 29-37 < -2331 > 2931 > -23$Therefore, The relationship between x and y cannot be established. 18) Answer (B) I:$x^2 = 13456x = \pm 116x = -116$or$x=116$II:$y = \sqrt{15129}y = 123$By comparing x and y values,$-116 < 123116 < 123$Therefore, x is less than y. 19) Answer (E) I:$2x^2-3x-629=02x^2+34x-37x-629=02x(x+17)-37(x+17)=0(x+17)(2x-37)=0x=-17$or$x=\dfrac{37}{2}$II:$y^2-4y-252=0y^2-18y+14y-252=0y(y-18)+14(y-18)=0(y-18)(y+14)=0y=18$or$y=-14$By comparing x and y values,$-17 < 18-17 < -14\dfrac{37}{2}>18\dfrac{37}{2}>-14$Therefore, The relationship between x and y cannot be determined. 20) Answer (E) I:$x^2+x-306 = 0x^2+18x-17x-306=0x(x+18)-17(x+18)=0(x+18)(x-17)=0x=-18$or$x=17$II:$y^2+5y-696=0y^2+29y-24y-696=0y(y+29)-24(y+29)=0(y+29)(y-24)=0y = -29$or$y = 24\$

By comparing x and y values,
-18 > -29
18 < 24
17 > -29
17 < 24
Therefore, The relationship between x and y cannot be established.