**Interest Questions for SSC CHSL:**

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**Question 1:** A shopkeeper marks the price of an article at 80. What will be the selling price, if he allows two successive discounts at 5% each ?

a) 72.2

b) 72

c) 85

d) 7.2

**Question 2:** A sum of money placed at compound interest doubles itself in 4 years. In how many years will it amount to four times itself ?

a) 12 years

b) 13 years

c) 8 years

d) 16 years

**Question 3:** In what time will 8,000, at 3% per annum, produce the same interest as 6, 000 does in 5 years at 4 % simple interest ?

a) 5 years

b) 6 years

c) 3 years

d) 4 years

**Question 4:** The rate of simple interest at which a sum of money becomes three times in 25 years is :

a) 6%

b) 8%

c) 5%

d) 4%

**Question 5:** The simple interest on a sum for 5 years is one fourth of the sum. The rate of interest per annum is

a) 5%

b) 6%

c) 4%

d) 8%

**Question 6:** If the amount received at the end of 2nd and 3rd year as Compound Interest on a certain Principal is Rs 2100, and Rs 2268 respectively, what is the rate (in %) of interest?

a) 7

b) 8

c) 9

d) 10

**Question 7:** An amount fetched a total simple interest of Rs. 3200 at the rate of 6.25 %/yr in 4 years. What is the amount (in Rs)?

a) 13800

b) 11800

c) 12800

d) 14800

**Question 8:** The simple interest on Rs. 2000 for 2 years at 7.5% per annum will be

a) Rs.150

b) Rs.300

c) Rs.600

d) Rs.400

**Question 9:** The compound ratio of the inverse ratios of the ratios x : yz , y : zx , z : xy is:

a) 1 : xyz

b) xyz : 1

c) 1: 1

d) x : yz

**Question 10:** The amount of Rs. 10,000 after 2 years, compounded annually with the rate of interest being 10% per annum during the first year and 12% per annum during the second year, would be (in rupees)

a) 11,320

b) 12,000

c) 12,320

d) 12,500

**Solutions for Interest Questions for SSC CHSL:**

**1) Answer (A)**

marked price of article = Rs 80

Now as it is given that two successive discounts of 5% are being provided it means after 1st discount price becomes = 0.95 x 80 = 76

Now after 2nd 5% discount price becomes = 0.95×76 =Rs 72.2

Hence selling price = Rs 72.2

**2) Answer (C)**

it is given that A sum of money placed at compound interest doubles itself in 4 years

here we need to make the money 4 times

imagine that we invested Rs P

and hence ,

P becomes 2P in 4 years and so this 2P will become 4P in another 4 years and hence total 8 years are required to make Rs P –> Rs 4P

**3) Answer (A)**

It is given that Rs 6000 with interest 4% per annum (SI) produces an interest in 5 years = $$\frac{P \times R \times T}{100}$$ = $$\frac{6000 \times 4 \times 5}{100}$$

= Rs 1200

Now the new principal amount is Rs 8000 and rate of interest is 3 % per annum. Let the time be T years in which same Rs 1200 will be generated as interest.

$$\frac{8000 \times 3 \times T}{100}$$ = 1200

T = 5 years

**4) Answer (B)**

Let the rate of interest be r%

as the money is becoming 3 times the investment in 25 years it means we are generating an interest of 2times the principal amount in 25 years

2p = $$\frac{p \times r \times t}{100}$$

t = 25 years is given

r = 8%

**5) Answer (A)**

it is given that simple interest on a sum for 5 years is one fourth of the sum

let the sum be Rs P

and rate of interest be R%

so SI = $$\frac{PRT}{100}$$

T= 5 years

$$\frac{P}{4}$$ = $$\frac{PR5}{100}$$

R = 5%

**6) Answer (B)**

Compound interest at the end of 2nd year = Rs. 2100

Compound interest at the end of 3rd year = Rs. 2268

=> Difference = 2268 – 2100 = Rs. 168

This is the interest obtained on the amount of 2nd year.

$$\therefore$$ Rate of interest, $$r = \frac{168}{2100} \times 100 = 8 \%$$

=> Ans – (B)

**7) Answer (C)**

$$I=\frac{PTR}{100}$$

$$3200=\frac{P*4*6.25}{100}$$

$$3200=\frac{25*P}{100}$$

$$P=12800$$

So the answer is option C.

**8) Answer (B)**

Principal sum =Â P = Rs. 2000

Rate of interest = 7.5% and time period = 2 years

Simple interest = $$\frac{P \times r \times t}{100}$$

= $$\frac{2000 \times 7.5 \times 2}{100}$$

= $$20 \times 15=Rs.$$ $$300$$

=> Ans – (B)

**9) Answer (B)**

Compound ratioÂ is the ratio of product of first terms in every ratio to that of product of second term in every ratio.

Thus, inverse ratios of the ratios of x : yz , y : zx , z : xy

= $$\frac{yz}{x}$$ , $$\frac{zx}{y}$$ , $$\frac{xy}{z}$$

Product of ratios = $$\frac{x^2y^2z^2}{xyz}$$

= $$\frac{xyz}{1}$$

Thus, compound ratio = xyzÂ : 1

=> Ans – (B)

**10) Answer (C)**

Principal amount = Rs. 10,000

Rate of interest = 10% for first year and 12% for second year

=> Amount after interest = $$10,000 \times \frac{110}{100} \times \frac{112}{100}$$

= $$110 \times 112=Rs.$$ $$12,320$$

=> Ans – (C)

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