# Interest Questions for SSC CHSL

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Interest Questions for SSC CHSL:

Download Interest questions for SSC exams of SSC CHSL and SSC CGL

Question 1: A shopkeeper marks the price of an article at 80. What will be the selling price, if he allows two successive discounts at 5% each ?

a) 72.2
b) 72
c) 85
d) 7.2

Question 2: A sum of money placed at compound interest doubles itself in 4 years. In how many years will it amount to four times itself ?

a) 12 years
b) 13 years
c) 8 years
d) 16 years

Question 3: In what time will 8,000, at 3% per annum, produce the same interest as 6, 000 does in 5 years at 4 % simple interest ?

a) 5 years
b) 6 years
c) 3 years
d) 4 years

Question 4: The rate of simple interest at which a sum of money becomes three times in 25 years is :

a) 6%
b) 8%
c) 5%
d) 4%

Question 5: The simple interest on a sum for 5 years is one fourth of the sum. The rate of interest per annum is

a) 5%
b) 6%
c) 4%
d) 8%

Question 6: If the amount received at the end of 2nd and 3rd year as Compound Interest on a certain Principal is Rs 2100, and Rs 2268 respectively, what is the rate (in %) of interest?

a) 7
b) 8
c) 9
d) 10

Question 7: An amount fetched a total simple interest of Rs. 3200 at the rate of 6.25 %/yr in 4 years. What is the amount (in Rs)?

a) 13800
b) 11800
c) 12800
d) 14800

Question 8: The simple interest on Rs. 2000 for 2 years at 7.5% per annum will be

a) Rs.150
b) Rs.300
c) Rs.600
d) Rs.400

Question 9: The compound ratio of the inverse ratios of the ratios x : yz , y : zx , z : xy is:

a) 1 : xyz
b) xyz : 1
c) 1: 1
d) x : yz

Question 10: The amount of Rs. 10,000 after 2 years, compounded annually with the rate of interest being 10% per annum during the first year and 12% per annum during the second year, would be (in rupees)

a) 11,320
b) 12,000
c) 12,320
d) 12,500

Solutions for Interest Questions for SSC CHSL:

marked price of article = Rs 80
Now as it is given that two successive discounts of 5% are being provided it means after 1st discount price becomes = 0.95 x 80 = 76
Now after 2nd 5% discount price becomes = 0.95×76 =Rs 72.2
Hence selling price = Rs 72.2

it is given that A sum of money placed at compound interest doubles itself in 4 years
here we need to make the money 4 times
imagine that we invested Rs P
and hence ,
P becomes 2P in 4 years and so this 2P will become 4P in another 4 years and hence total 8 years are required to make Rs P –> Rs 4P

It is given that Rs 6000 with interest 4% per annum (SI) produces an interest in 5 years = $$\frac{P \times R \times T}{100}$$ = $$\frac{6000 \times 4 \times 5}{100}$$
= Rs 1200
Now the new principal amount is Rs 8000 and rate of interest is 3 % per annum. Let the time be T years in which same Rs 1200 will be generated as interest.
$$\frac{8000 \times 3 \times T}{100}$$ = 1200
T = 5 years

Let the rate of interest be r%
as the money is becoming 3 times the investment in 25 years it means we are generating an interest of 2times the principal amount in 25 years
2p = $$\frac{p \times r \times t}{100}$$
t = 25 years is given
r = 8%

it is given that simple interest on a sum for 5 years is one fourth of the sum
let the sum be Rs P
and rate of interest be R%
so SI = $$\frac{PRT}{100}$$
T= 5 years
$$\frac{P}{4}$$ = $$\frac{PR5}{100}$$
R = 5%

Compound interest at the end of 2nd year = Rs. 2100
Compound interest at the end of 3rd year = Rs. 2268
=> Difference = 2268 – 2100 = Rs. 168
This is the interest obtained on the amount of 2nd year.
$$\therefore$$ Rate of interest, $$r = \frac{168}{2100} \times 100 = 8 \%$$
=> Ans – (B)

$$I=\frac{PTR}{100}$$
$$3200=\frac{P*4*6.25}{100}$$
$$3200=\frac{25*P}{100}$$
$$P=12800$$
So the answer is option C.

Principal sum = P = Rs. 2000
Rate of interest = 7.5% and time period = 2 years
Simple interest = $$\frac{P \times r \times t}{100}$$
= $$\frac{2000 \times 7.5 \times 2}{100}$$
= $$20 \times 15=Rs.$$ $$300$$
=> Ans – (B)

Compound ratio is the ratio of product of first terms in every ratio to that of product of second term in every ratio.
Thus, inverse ratios of the ratios of x : yz , y : zx , z : xy
= $$\frac{yz}{x}$$ , $$\frac{zx}{y}$$ , $$\frac{xy}{z}$$
Product of ratios = $$\frac{x^2y^2z^2}{xyz}$$
= $$\frac{xyz}{1}$$
Thus, compound ratio = xyz : 1
=> Ans – (B)

=> Amount after interest = $$10,000 \times \frac{110}{100} \times \frac{112}{100}$$
= $$110 \times 112=Rs.$$ $$12,320$$