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# Data Analysis and Comparision (DI) Questions for XAT

Download Data Analysis and Comparision Questions for XAT PDF â€“ XAT Data Analysis and Comparision questions pdf by Cracku. Practice XAT solved Data Analysis and Comparision Questions paper tests and These sample questions are to analyse the XAT exam pattern. Top 15 very Important Data Analysis and Comparision Questions for XAT based on asked questions in previous exam papers. Â The XAT question papers contain actual questions asked with answers, solutions.

Instructions

Production of three Different Types of Tyres by a Company over the Years (in lakhs)

Question 1:Â The total production of C type tyre in 1992 and 1993 together was what percentage of Production of B type tyres in 1994?

a)Â 50

b)Â 100

c)Â 150

d)Â 200

e)Â None of these

Solution:

Total production of C type tyre in 1992 and 1993 together (in lakhs) = 30 + 25 = 55

Production of B type tyres in 1994 (in lakhs) = 32.5

=> Required % = $\frac{55}{32.5} \times 100$

$\approx 170 \%$

Thus, answer is none of these.

Question 2:Â In which of the following years was percentage production of B type tyres to C type tyres the maximum?

a)Â 1994

b)Â 1992

c)Â 1996

d)Â 1993

e)Â 1995

Solution:

Percentage production of B type tyres to C type tyres = Ratio of B type tyres to C type tyres in :

1992 = $\frac{20}{30}$ = 0.67

1993 =Â $\frac{30}{25}$ =Â Â 1.2

1994 =Â $\frac{32}{22.5}$ =Â 1.4

1995 =Â $\frac{37.5}{22.5}$ = 1.67Â  Â [MAX]

1996 =Â $\frac{15}{32.5}$ =Â 0.4

=> Ans – (E)

Question 3:Â The total number of all the three tyres manufactured was the least in which of the following years?

a)Â 1995

b)Â 1996

c)Â 1992

d)Â 1994

e)Â 1993

Solution:

Total number of all the three tyres manufacturedÂ inÂ (in lakhs) :

1992 : 25 + 20 + 30 = 75

1993Â :Â 20 + 30 + 25 = 75

1994Â :Â 32.5 + 32.5 + 22.5 = 87.5

1995Â :Â 27.5 + 37.5 + 22.5 = 87.5

1996Â :Â 15 + 15 + 32.5 = 62.5Â  Â [MIN]

=> Ans – (B)

Question 4:Â What was the difference between the number of B type tyres manufactured in 1994 and 1995?

a)Â 5,00,000

b)Â 20,00,000

c)Â 10,00,000

d)Â 15,00,000

e)Â None of these

Solution:

Number of B type tyres manufactured in 1994Â = 32.5 lakhs

Number of B type tyres manufactured in 1995 = 37.5 lakhs

=> Required difference = (37.5 – 32.5) lakhs = 5,00,000

=> Ans – (A)

Question 5:Â What was the percentage drop in the number of C type tyres manufactured from 1993 to 1994?

a)Â 25

b)Â 10

c)Â 15

d)Â 2.5

e)Â None of these

Solution:

Number of C type tyres manufacturedÂ in 1993 (in lakhs) = 25

Number of C type tyres manufacturedÂ in 1994 (in lakhs) =Â 22.5

=> Required % drop = $\frac{(25 – 22.5)}{25} \times 100$

= $2.5 \times 4 = 10 \%$

=> Ans – (B)

Instructions

Question 6:Â In which of the following periodicals ,the student P obtained highest percentage of the marks?

a)Â I

b)Â II

c)Â III

d)Â IV

e)Â V

Solution:

Total marks obtained by student PÂ :

I = 40 + 30 + 35 + 45 + 24 = 174

II = 30 + 40 + 25 + 47 + 28 = 170

III = 45 + 25 + 15 + 32 + 36 = 153

IV = 20 + 30 + 30 + 39 + 39 = 158

V = 35 + 20 + 40 + 37 + 43 = 175 Â  Â  Â Â [MAXIMUM]

=> Ans – (E)

Question 7:Â In which of the following subjects was the average percentage of marks obtained by student S the highest?

a)Â Maths

b)Â Science

c)Â History

d)Â Geography

e)Â English

Solution:

Total marks obtained by student S in subjectÂ :

Maths = 25 + 35 + 40 + 45 + 30 = 175

Science = 31 + 34 + 38 + 27 + 30 = 160

History = 34 + 40 + 36 + 42 + 48 = 200 Â  Â Â [MAXIMUM]

Geography = 39 + 37 + 44 + 40 + 30 = 190

English = 31 + 34 + 35 + 45 + 40 = 185

=> Ans – (C)

Question 8:Â The average percentage of marks obtained by student P in Maths in five periodicals was exactly equal to the average percentage of marks obtained by Student R in the five periodicals in which of the following subjects ?

a)Â English

b)Â Geography

c)Â Science and Geography

d)Â Maths

e)Â None of these

Solution:

Total marks obtained by student P in Maths = 40 + 30 + 45 + 20 + 35 = 170

=> Average marks of P in Maths = $\frac{170}{5} = 34$

Marks scored by student R in subjectÂ :

Maths = 30 + 36 + 40 + 45 + 40 = 191

Science = 48 + 46 + 31 + 40 + 80 = 245

History = 35 + 45 + 40 + 30 + 35 = 185

Geography = 25 + 35 + 48 + 37 + 25 = 170

=> Average marks of R in Geography = $\frac{170}{5}=34$

=> Ans – (B)

Question 9:Â what was the total marks of the student’s T in the science in all the periodicals together?

a)Â 160

b)Â 180

c)Â 190

d)Â 140

e)Â None of these

Solution:

Total marks of the student’s T in the science in all the periodicals together

= 44 + 36 + 40 + 30 + 40

= 190

=> Ans – (C)

Question 10:Â What was the average marks of five Subjects of Q in the periodical I ?

a)Â 32

b)Â 34

c)Â 40

d)Â 30

e)Â None of these

Solution:

TotalÂ marks of five Subjects of Q in the periodical I

= 30 + 25 + 33 + 42 + 30 = 160

=> Required average = $\frac{160}{5}=32$

=> Ans – (A)

Instructions

Study the following graph carefully and answer the questions given below it.
Net Profit Percentage of the two Companies over the years?

Question 11:Â In which of the following years was the total income more than double the total expenditure in that year for Company B?

a)Â 1995

b)Â 1993

c)Â 1996

d)Â 1992

e)Â None of these

Solution:

For income to be more than double the total expenditure, the profit % = $\frac{2I – I}{I} \times 100$ = $100 \%$

=> Profit % must be more than 100%

But, as clearly seen from the line graph, for company B, the profit percent is not more than 100% for any year

=> Ans – (E)

Question 12:Â If the total expenditure of company B in 1994 was Rs.200 crore ,what was the total income ?

a)Â 160 crores

b)Â 240 crores

c)Â 260 crore

e)Â None of these

Solution:

Total expenditure of company B in 1994 = Rs.200 crore

Profit % of company B in 1994 = 40%

Let total income = $Rs. x$ crore

=>Â Profit % =Â $\frac{IncomeÂ –Â Expenditure}{Expenditure} \times 100$

=> $\frac{x – 200}{200} \times 100 = 40$

=> $\frac{x – 200}{2} = 40$

=> $x – 200 = 40 \times 2 = 80$

=> $x = 80 + 200 = 280$ crore

=> Ans – (E)

Question 13:Â In how many of the given years the percentage of expenditure to the income of company A was less than fifty?

a)Â One

b)Â Two

c)Â Three

d)Â Four

e)Â None of these

Solution:

ForÂ percentage of expenditure to the income of company A to be less than fifty, => $\frac{E}{I} \leq \frac{1}{2}$

=> $2E \leq I$, => $I – E \geqÂ E$

It can be written as,

=> $\frac{I – E}{E} \times 100 \geq 100$

Thus, profit % should be more than 100% and clearly, for none of the years, profit percent for company A is more than 100%.

=> Ans – (E)

Question 14:Â If the total Expenditure of 1993 and 1994 together of company B was Rs 270 crore,What was the total income of the in these companies?

a)Â 121.5 crore

b)Â 135 crore

c)Â 140 crore

e)Â None of these

Solution:

Total Expenditure of 1993 and 1994 together of company B = Rs 270 crore

Also, profit % in 1993 = 50% and in 1994 = 40% for company B

But, no relation is given between the expenditures of both years or income of both years.

Thus, we cannot determine the total income for both years.

=> Ans – (D)

Instructions

Study the following table carefully and answer the given questions

Question 15:Â The total number of candidates qualified from Rural in 1993 and the semi urban in 1990 was exactly equal to the total no of candidates qualified from state -capitals in which of the following years?

a)Â 1990

b)Â 1993

c)Â 1994

d)Â 1992

e)Â None of these

Solution:

Number of candidates qualified from Rural in 1993 = 1798

Number of candidates qualified from Semi-Urban in 1990 = 2513

Total = 1798 + 2513 = 4311

Clearly, in none of the year, total number of qualified candidates from state-capitals (Metropolises) is equal to 4311

=> Ans – (E)

Question 16:Â In 1993 the percentage of candidates qualified to the appeared was 35 from which location?

a)Â Rural

b)Â Rural and Metropolises

c)Â Semi-urban and metropolises

d)Â Rural and semi urban

e)Â None of these

Solution:

Percentage of qualified candidates to appeared candidates in 1993 in :

Rural = $\frac{1798}{5032} \times 100 =35.73 \%$

Semi-UrbanÂ = $\frac{3528}{9432} \times 100 = 37.40\%$

MetropolisesÂ = $\frac{5158}{11247} \times 100 = 45.86\%$

Thus, from rural locationÂ the percentage of candidates qualified to the appeared was approximately 35 in 1993

=> Ans – (A)

Question 17:Â what was the percentage drop in the Number of semi urban candidates qualified to the appeared from 1991 to 1992?

a)Â 5

b)Â 10

c)Â 15

d)Â 8

e)Â 12

Solution:

Percentage of qualified candidates to appeared candidates in Semi-Urban in 1991

= $\frac{2933}{8562} \times 100 = 34.25 \approx 34\%$

Percentage of qualified candidates to appeared candidates in Semi-Urban in 1992

= $\frac{2468}{8139} \times 100 = 30.32 \approx 30\%$

$\therefore$ Percentage drop = 34 – 30 = 4Â $\approx$ 5%

=> Ans – (A)

Question 18:Â In which of the following years was the percentage of candidates qualified to the appeared from the semi-urban area least?

a)Â 1991

b)Â 1993

c)Â 1990

d)Â 1992

e)Â None of these

Solution:

Percentage of candidates qualified to the appeared from the semi-urban area inÂ :

(A) : 1991 = $\frac{2933}{8562} \times 100= 34.25\%$

(B) : 1993 =Â $\frac{3528}{9432} \times 100= 37.40\%$

(C) : 1990 =Â $\frac{2513}{7894} \times 100= 31.83\%$

(D) : 1992 =Â $\frac{2468}{8139} \times 100= 30.32\%$ Â  Â Â [MINIMUM]

=> Ans – (D)

Question 19:Â For the candidates from which of the following locations was there continuous increase both in the appeared and the passed?

a)Â Semi urban

b)Â State Capitals

c)Â State capitals and rural

d)Â Metropolis

e)Â None of these