Arithmetic Questions for MAH-CET

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Question 1:Â 5 1/8 of 208 + 786 = 2000 – ?

a)Â 112

b)Â 148

c)Â 184

d)Â 124

e)Â None of these

Solution:

ExpressionÂ :Â 5 1/8 of 208 + 786 = 2000 – ?

=> $\frac{41}{8} * 208 + 786 = 2000 – ?$

=> $1066 + 786 = 2000 – ?$

=> $? = 2000 – 1852 = 148$

Question 2:Â $546 + 222 \times 9 \div 6 = ?$

a)Â 982

b)Â 997

c)Â 879

d)Â 839

e)Â None of these

Solution:

ExpressionÂ :Â $546 + 222 \times 9 \div 6 = ?$

= $546 + \frac{222 \times 9}{6}$

= $546 + 37 \times 9$

= $546 + 333 = 879$

Question 3:Â The difference between 56% of a number and 41% of the same number is 660. What is 8% of that number ?

a)Â 321

b)Â 336

c)Â 345

d)Â 358

e)Â None of these

Solution:

Let the number be $100x$

Acc to ques,

=> $(\frac{56}{100} * 100x) – (\frac{41}{100} * 100x) = 660$

=> $56x – 41x = 660$

=> $x = \frac{660}{15} = 44$

$\therefore$ 8% of the number = $\frac{8}{100} * 100x = 8 * x$

= 8 * 44 = 352

Question 4:Â What approximate value should come in place of the question mark (?) in the following question ?
$45.709 \div 11.342 \times 6.667 = ?$

a)Â 88

b)Â 46

c)Â 112

d)Â 56

e)Â 27

Solution:

ExpressionÂ :Â $45.709 \div 11.342 \times 6.667 = ?$

= $\frac{44}{11} \times 7$

= $4 \times 7 = 28$

$\approx$ 27

Question 5:Â If $(58)^{2}$ is added to the square of a number, the answer so obtained is 5668. What is the number ?

a)Â 56

b)Â 33

c)Â 47

d)Â 51

e)Â None of these

Solution:

Let the number be $x$

Acc to ques,

=> $58^2 + x^2 = 5668$

=> $x^2 = 5668 – 3364$

=> $x = \sqrt{2304} = 48$

Thus, Ans – (E)

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Question 6:Â which number should replace both the question marks (?) in the following equation ?
$\frac{?}{188}=\frac{47}{?}$

a)Â 88

b)Â 124

c)Â 66

d)Â 94

e)Â None of these

Solution:

ExpressionÂ :Â $\frac{?}{188}=\frac{47}{?}$

=> $?^2 = 188 \times 47$

=> $? = \sqrt{4 \times 47 \times 47}$

=> $? = 2 \times 47 = 94$

Question 7:Â if $9^{3}$ is subtracted from the square of a number ,the answer so obtained is 567 .What is the number?

a)Â 36

b)Â 28

c)Â 42

d)Â 48

e)Â none of these

Solution:

Let the number be $x$

According to ques,

=> $x^2-9^3=567$

=> $x^2=567+729=1296$

=> $x=\sqrt{1296}=36$

=> Ans – (A)

Question 8:Â What is the 333 times 131

a)Â 46323

b)Â 43623

c)Â 43290

d)Â 42597

e)Â None of these

Solution:

Expression : $333 \times 131$

= $3 \times 111 \times 131$

= $3 \times 14541 = 43623$

=> Ans – (B)

Question 9:Â The product of two successive natural numbers is 8556 .What is the smaller number?

a)Â 89

b)Â 94

c)Â 90

d)Â 92

e)Â none of these

Solution:

Let the successive natural numbers be $(x),(x+1)$

Product = $x(x+1)=8556$

=> $x^2+x-8556=0$

=> $x^2+93x-92x-8556=0$

=> $x(x+93)-92(x+93)=0$

=> $(x+93)(x-92)=0$

=> $x=-93,92$

$\because$ The numbers are natural, thus $x \neq -93$

$\therefore$ Smaller number =Â $x=92$

=> Ans – (D)

Question 10:Â What is the least number to be added to 4321 to make it a perfect square?

a)Â 32

b)Â 34

c)Â 36

d)Â 38

e)Â none of these

Solution:

We need to find the approximate value of $\sqrt{4321} \approx$ 65.73

We find that $65^2=4225$ < $4321$ and $66^2=4356$ > $4321$

So the least number to be added = 4356 – 4321 = 35

$\therefore$ 35 can be added to 4321 to make it a perfect square.

=> Ans – (E)

Question 11:Â if $78^{2}$Â is subtracted from the square of a number, the obtained answer is 6460. What is that number?

a)Â 109

b)Â 111

c)Â 113

d)Â 115

e)Â none of these

Solution:

Let the number be $x$

According to ques,

=> $x^2-78^2=6460$

=> $x^2=6460+6084$

=> $x=\sqrt{12544}=112$

=> Ans – (E)

Question 12:Â What value should come in the question mark
$4275\div496\times(21^{2})$=?

a)Â 3795

b)Â 3800

c)Â 3810

d)Â 3875

e)Â 3995

Solution:

Expression =Â $4275\div496\times(21^{2})$=?

= $\frac{4275}{496} \times 441$

= $8.62 \times 441 = 3801.42$

$\approx 3800$

Question 13:Â What will be come in the place of question mark?
$0.001+9.909\times1.01\div0.1$

a)Â 99.0819

b)Â 100.0819

c)Â 100.091

d)Â 100.0919

e)Â None of these

Solution:

ExpressionÂ :Â $0.001+9.909\times1.01\div0.1$

= $0.001 + \frac{9.909 \times 1.01}{0.1}$

= $0.001 + (10.00809 \times 10)$

= $0.001 + 100.0809 = 100.0819$

Question 14:Â The sum of three consecutive number is given .What is difference between first and third number?

a)Â 1

b)Â 3

c)Â Either 1 or 2

d)Â 2

e)Â None of these

Solution:

Let the 3 consecutive numbers be $(x-1),(x),(x+1)$

Difference between first and third number = $(x+1)-(x-1)$

= $(x-x)+(1+1)=2$

=> Ans – (D)

Question 15:Â $(299.99999)^{3}$ =?

a)Â 270,00,000

b)Â 9,000,000,000

c)Â 180,000

d)Â $2.7\times10^{7}$

e)Â 270,00,00

ExpressionÂ : $(299.99999)^{3}$ =?
$\approx (300)^3$
= $2,70,00,000$