Coding and Decoding Questions For SSC Stenographer PDF
SSC Stenographer Constable Coding and Decoding Question and Answers download PDF based on previous year question paper of SSC Stenographer exam. 20 Very important Coding and Decoding questions for Stenographer Constable.
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Question 1:Â If ‘TRAVEL’ is coded as ‘WFMUSB’ and ‘PUZZLE’ is coded as ‘AMFQVA’, then how is ‘LETTER’ coded?
a)Â UFSMFU
b)Â MFUUFS
c)Â UFSMGV
d)Â VGTMFT
Question 2: If ‘+’ means ‘-’, ‘-’ means ‘$\div$’, ‘$\times$’ means ‘+’, ‘$\div$’ means ‘$\times$’. Then find the value of 49 – 7 $\times$ 13 + 14
a)Â 8
b)Â 6
c)Â 2
d)Â 14
Question 3:Â If 132 ^ 12 # 15 = 26 and 156 ^ 13 # 11 = 23, then find the value of 143 ^ 11 # 12
a)Â 126
b)Â 84
c)Â 25
d)Â 36
Question 4:Â If 25 @ 5 % 25 = 100 and 24 @ 10 % 40 = 200, then 36 @ 7 % 52 = ?
a)Â 150
b)Â 200
c)Â 136
d)Â 124
Question 5:Â If 49 $ 7 # 21 = 35 and 29 $ 8 # 14 = 23, then find the value of 17 $ 4 # 13
a)Â 11
b)Â 5
c)Â 8
d)Â 12
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Question 6:Â If 14 P 9 Q 3 = 42 and 21 P 9 Q 7 = 27, then find the value of 16 P 8 Q 4
a)Â 15
b)Â 19
c)Â 32
d)Â 20
Question 7:Â If 7 $ 8 ^ 4 = 39 and 15 $ 3 ^ 9 = 42, then find the value of 19 $ 7 ^ 2
a)Â 12
b)Â 33
c)Â 11
d)Â 9
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Question 8:Â If 14 % 7 # 68 = 30 and 13 % 8 # 42 = 62, then find the value of 9 % 6 # 14
a)Â 24
b)Â 40
c)Â 16
d)Â 62
Question 9:Â If 5 % 6 ^ 2 = 8 and 3 % 9 ^ 3 =6. Find the value of 4 % 12 ^ 4
a)Â 21
b)Â 7
c)Â 12
d)Â 2
Question 10:Â If 17 $ 9 # 5 = 62 and 13 $ 8 # 4 = 45, then find the value of 15 $ 4 # 3
a)Â 14
b)Â 27
c)Â 39
d)Â 19
Question 11: If ‘L’ represents ‘+’, ‘M’ represents ‘ – , ‘N’ represents ‘$\times$’, ‘P’ represents ‘$\div$’, then 16 L 19 N 4 M 21 N 4 = ?
a)Â 26
b)Â 18
c)Â 8
d)Â 2
Question 12: If ‘L’ represents ‘+’, ‘M’ represents ‘ – , ‘N’ represents ‘$\times$’, ‘P’ represents ‘$\div$’, then 13 M 3 N 15 P 5 L 9 = ?
a)Â 17
b)Â 23
c)Â 13
d)Â 19
Question 13: If ‘L’ represents ‘+’, ‘M’ represents ‘ – , ‘N’ represents ‘$\times$’, ‘P’ represents ‘$\div$’, then 15 L 24 N 7 M 13 N 9 = ?
a)Â 24
b)Â 66
c)Â 18
d)Â 36
Question 14: If ‘+’ means ‘-’, ‘-’ means ‘$\times$’, ‘$\times$’ means ‘$\div$’ and ‘$\div$’ means +. Then find the value of 108 $\times$ 19 – 57 $\times$ 9 $\div$ 14
a)Â 74
b)Â 25
c)Â 50
d)Â 42
Question 15: If ‘+’ means ‘-’, ‘-’ means ‘$\times$’, ‘$\times$’ means ‘$\div$’ and ‘$\div$’ means +. Then find the value of 17 $\div$ 23 – 5 + 38
a)Â 78
b)Â 94
c)Â 86
d)Â 28
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Question 16: If ‘+’ means ‘-’, ‘-’ means ‘$\times$’, ‘$\times$’ means ‘$\div$’ and ‘$\div$’ means +. Then find the value of 54 + 117 $\times$ 8 – 32 $\times$ 9
a)Â 16
b)Â 28
c)Â 8
d)Â 2
Question 17:Â If 24 # 112 ^ 7 = 40 and 57 # 216 ^ 24 = 66, then find the value of 49 # 114 ^ 19
a)Â 37
b)Â 63
c)Â 55
d)Â 29
Question 18:Â If 39 @ 4 $ 3 = 27 and 67 @ 7 $ 2 = 53, then 27 @ 5 $ 4 = ?
a)Â 18
b)Â 7
c)Â 26
d)Â 14
Question 19:Â If 43 & 4 % 8 = 75 and 36 & 3 % 9 = 63, then 29 & 6 % 7 = ?
a)Â 69
b)Â 51
c)Â 87
d)Â 71
Question 20: If ‘A’ means ‘+’, ‘B’ means ‘-’, ‘C’ means ‘$\times$’, ‘D’ means ‘$\div$’. Then find the value of 322 D 46 B 473 D 43 + 392 D 28
a)Â 16
b)Â 24
c)Â 10
d)Â 45
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Answers & Solutions:
1) Answer (A)
Interchanging first half and second half of the words
VELTRA:
V+1 = W
E+1 = F
L+1 = M
T+1 = U
R+1 = S
A+1 = B
ZLEPUZ:
Z+1 = A
L+1 = M
E+1 = F
P+1 = Q
U+1 = V
Z+1 = A
Similarly,
TERLET:
T+1 = U
E+1 = F
R+1 = S
L+1 = M
E+1 = F
T+1 = U
Hence, UFSMFU is correct answer.
2) Answer (B)
49 – 7 $\times$ 13 + 14 = $\frac{49}{7}$ + 13 – 14 = 6
3) Answer (C)
$\frac{132}{12}$ + 15 = 26
$\frac{156}{13}$ + 11 = 23
$\therefore$ $\frac{143}{11}$ + 12 = 25
4) Answer (B)
25 $\times$ 5 – 25 = 100
24 $\times$ 10 – 40 = 200
$\therefore$ 36 $\times$ 7 – 52 = 200
5) Answer (C)
49 + 7 – 21 = 35
29 + 8 – 14 = 23
$\therefore$ 17 + 4 – 13 = 8
6) Answer (C)
$14$ $\times$ $\frac{9}{3}$ $=$ $42$
$21$ $\times$ $\frac{9}{7}$ $=$ $27$
$\therefore$ $16$ $\times$ $\frac{8}{4}$ $=$ $32$
7) Answer (B)
7 + 8 $\times$ 4 = 39
15 + 3 $\times$ 9 = 42
$\therefore$ 19 + 7 $\times$ 2 = 33
8) Answer (B)
14 $\times$ 7 – 68 = 30
13 $\times$ 8 – 42 = 62
$\therefore$ 9 $\times$ 6 – 14 = 54 – 14 = 40
9) Answer (B)
5 + $\frac{6}{2}$ = 8
3 + $\frac{9}{3}$ = 6
$\therefore$ 4 + $\frac{12}{4}$ = 7
10) Answer (B)
17 + 9 $\times$ 5 = 62
13 + 8 $\times$ 4 = 45
$\therefore$ 15 + 4 $\times$ 3 = 27
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11) Answer (C)
16 L 19 N 4 M 21 N 4 = 16 + 19 $\times$ 4 -21 $\times$ 4 = 16 + 76 – 84 = 8
12) Answer (C)
13 M 3 N 15 P 5 L 9 = 13 – 3 $\times$ $\frac{15}{5}$ + 9 = 13
13) Answer (B)
15 L 24 N 7 M 13 N 9 = 15 + 24 $\times$ 7 – 13 $\times$ 9 = 15 + 168 – 117 = 66
14) Answer (C)
108 $\times$ 19 – 57 $\times$ 9 $\div$ 14 = $\Large\frac{108}{19}$ $\times$ $\Large\frac{57}{9}$ $+$ $14$ = 36 + 14 = 50
15) Answer (B)
17 $\div$ 23 – 5 + 38 = 17 + 23 $\times$ 5 – 38 = 17 + 115 – 38 = 94
16) Answer (D)
54 + 117 $\times$ 8 – 32 $\times$ 9 equals 54 – 117 $\div$ 9 $\times$ 32 $\div$ = 54 – 52 = 2
17) Answer (C)
24 + $\frac{112}{7}$ = 24 + 16 = 40
57 + $\frac{216}{24}$ = 57 + 9 = 66
$\therefore$ 49 + $\frac{114}{19}$ = 49 + 6 = 55
18) Answer (B)
39 – 4 $\times$ 3 = 27
67 – 7 $\times$ 2 = 53
$\therefore$ 27 – 5 $\times$ 4 = 27 – 20 = 7
19) Answer (D)
46 + 4 $\times$ 8 = 75
36 + 3 $\times$ 9 = 63
$\therefore$ 29 + 6 $\times$ 7 = 71
20) Answer (C)
322 D 46 B 473 D 43 + 392 D 28 = $\Large\frac{322}{46}$ $-$ $\Large\frac{473}{43}$ $+$ $\Large\frac{392}{28}$ $=$ $7$ $-$ $11$ $+$ $14$ $=$ $10$
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