Samu needs 40% to pass. If he scores 190 marks: but still falls short by 10 marks, then what is the maximum number of marks he could have scored?
40% $$\longrightarrow\ $$ (190+10)=200
1% $$\longrightarrow\ $$ $$\ \frac{\ 200}{40\%}$$
100%$$\ \longrightarrow\ \frac{\ 200}{40\%}\times\ 100\%$$= 500
so maxm marks is 500,
Hence option 'B' is correct.
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