Question 85

Two students appeared for an examination. One of them got 9 marks more than the other. His marks was also equal to 56% of the sum of their marks. What are their marks?

Solution

let their marks be (x+9) and x.
ATQ, x+9 = $$\frac{56}{100}(x + 9 +x)$$
= $$25\times(x+9)$$

= $$14\times(2x+9)$$
= 3x = 99
= x = 33.

So, their marks are (x+9) and x which is 42 and 33

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