Solution
Factorizing $$6(xy - y)$$ by taking the common factor '6y', we get
6y(x-1)
Factorizing $$ 8 (x^4y - xy)$$ by taking the common factor '8xy', we get $$ 8xy(x^3-1)$$
Therefore, the LCM of $$6(xy - y) and 8 (x^4y - xy)$$ is $$24 xy (x^3 - 1)$$
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