Question 80

What is the LCM of $$6(xy - y), 8 (x^4y - xy)$$?

Solution

Factorizing $$6(xy - y)$$ by taking the common factor '6y', we get

6y(x-1)

Factorizing $$ 8 (x^4y - xy)$$ by taking the common factor '8xy', we get $$ 8xy(x^3-1)$$

Therefore, the LCM of $$6(xy - y) and 8 (x^4y - xy)$$ is $$24 xy (x^3 - 1)$$

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