Out of the total number of students who have enrolled for course Linux, 42% are females. If out of the total number of female students, who have enrolled for course Linux, 20% are from college Q, how many male students from college Q have enrolled for the same course?
Solution
Total number of students enrolled for Linux = 1500
Total number of females = $$\frac{42}{100} \times 1500 = 630$$
=> Number of females from college Q = $$\frac{20}{100} \times 630 = 126$$
Total students from college Q who enrolled for Linux = $$\frac{20}{100} \times 1500 = 300$$
$$\therefore$$ Number of male students from college Q who enrolled for Linux = $$300 - 126 = 174$$
