Question 72

A train crossed a 140 m long platform in 15 seconds and a 180 m long platform in 17
seconds. The speed of the train was:

Solution

Difference in lengths of platforms

= 180 - 140 = 40m

Difference in time taken to cross them

= 17 - 15 = 2 s

=> Speed of train = $$\frac{distance}{time}$$

$$\frac{40}{2}$$ = 20 $$\frac{m}{s}$$

= $$20\times \frac{18}{5}$$= 72 kmph

Create a FREE account and get:

Download RRB Study Material PDF
45+ RRB previous papers with solutions PDF
300+ Online RRB Tests for Free

CAT Quant Questions | CAT Quantitative Ability

CAT Quadratic Equations Questions CAT Inequalities Questions CAT Averages Questions CAT Linear Equations Questions CAT Percentages Questions

CAT DILR Questions | LRDI Questions For CAT

CAT Quant Based DI Questions CAT Table with Missing values Questions CAT Selection With Condition Questions CAT Charts Questions CAT Routes And Networks Questions

CAT Verbal Ability Questions | VARC Questions For CAT

CAT Reading Comprehension Questions CAT Verbal Ability Questions CAT Critical Reasoning Questions CAT Odd One Out Questions CAT Vocabulary Questions

Follow us on

Boost your Prep!

Download App