Find the greatest number that will divide 115, 149 and 183 leaving remainders 3, 5, 7 respectively.
115, 149 and 183 leaving remainders 3, 5, 7
HCF of (115 - 3, 149 - 5, 183 - 7)
⇒ HCF of (112, 144, 176)
112 = $$2\times 2\times 2\times 2\times 7 $$
144= $$2\times 2\times 2\times 2\times 3\times 3$$
176 = $$2\times 2\times 2\times 2\times 11$$
16 is hcf that will divide 115, 149 and 183 leaving reminder 3, 5, 7 respectively
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