Question 69

A box contains coins (equal no. of every one) of rupee and half rupee, coins of 25 paise, 10 paise, 5 paise value, 2 paise value and one paise value. The total value of coins in the box is Rs. 1158. Find the number of coins of each value.

Solution

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Let the number of each coin be x

Total value of the box = x * 1 + x * .5 + x * .25 + x * .1 + x * .05 + x * .02 + x * .01 = x * (1.93)

But 1.93x = 1158

So, x = 1158/1.93 = 600 coins

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