Question 54

The base of a triangle is half the base of a parallelogram having the same area as that of the triangle. The ratio of the corresponding heights of the triangle to the parallelogram will be:

Solution

area of triangle=$$\frac{1}{2}\times\ b\times\ h$$

area of parallelogram=B$$\times$$H

Given that the base of triangle is half of the base of parallelogram

($$\bf \frac{1}{2}\times \frac {B}{2}\times h $$ = B$$\times$$H)

($$\bf \frac {h} {H} = \frac {4}{1}$$)

Hence the ratio is 4:1.

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