Solution
$$\sin \theta$$ = 1/$$\surd 2$$
$$\sin\theta\ =\frac{P}{H}=\frac{1}{\sqrt{\ 2}}$$
$$B^2 =H^2-P^2$$
$$B^2=2\ -\ 1\ =1$$
B = 1
$$\tan\ =\frac{P}{B},\ \cos\ =\frac{B}{H}$$
$$(\tan \theta + \cos \theta)$$ = $$1+\frac{1}{\sqrt{\ 2}}=\frac{\sqrt{\ 2}+1}{\sqrt{\ 2}}$$.
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