If $$x^2 + ax + b$$, when divided by $$x - 3$$, leaves a remainder of 22 and $$x^2 + bx + a$$, when divided by $$x - 3$$, leaves a remainder of 24, then $$a + b = ?$$
The correct option is C.
let p($$x$$)= $$x^{2}+ax+b$$ And f($$x$$) = $$x^{2}+bx+a$$
Now, p(3)= 22
$$\implies$$ $$3^{2}+3a+b$$ = 22
$$\implies$$ 3a+b = 13Â Â ....... (1)
and, f(3) = 24
$$\implies$$ $$3^{2}+3a+b$$ = 24
$$\implies$$ 3a+b =15Â ......(2)
Adding (1) and (2) we get, a+b = 7
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