Given, $$a + \frac{1}{a} = 1$$
Cubing on both sides we get,
$$a^{3} +Â \frac{1}{a^{3}} + 3(a +Â \frac{1}{a}) = 1$$Â
$$ a^{3} + \frac{1}{a^{3}} = -2$$ (Â as we know $$a + \frac{1}{a} = 1$$)
Hence, option B is the correct answer.Â
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