Travelling at $$\frac{4}{5}$$ th of his usual speed, a man is 15 minutes late. What is his usual time to cover the same distance?
Since, the man now walks at $$\frac{4}{5}$$ of usual speed, so he will take $$\frac{5}{4}$$ of his usual time.
⇒ Extra time = ($$\frac{5}{4}$$ - 1) x Usual time = 15 min
⇒ $$\frac{1}{4}$$ x Usual time = 15
∴ Usual time = 60 min
Create a FREE account and get:
