Question 25

The length of each side of a rhombus is 25 m and the length of one of its diagonals is 14 m. Find the area of the rhombus.

Solution

Let AC and BD be the two diagonals intersect at O

Let AC =14 Therefore AO=7

AOB is a right angled triangle

$BO=\sqrt(25^2-7^2)$

$$BO=24

BD=48 cm

$$Area = \frac{1}{2}\times(AC)\times(BD)$$

$$Area = \frac{1}{2}\times(14)\times(48)$$

$$Area = (7)\times(48)$$

$$Area = 336$$

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