The length of each side of a rhombus is 25 m and the length of one of its diagonals is 14 m. Find the area of the rhombus.
Let AC and BD be the two diagonals intersect at O
Let AC =14 Therefore AO=7
AOB is a right angled triangle
$$BO=\sqrt(25^2-7^2)$$
$$BO=24
BD=48 cm
$$Area = \frac{1}{2}\times(AC)\times(BD)$$
$$Area = \frac{1}{2}\times(14)\times(48)$$
$$Area = (7)\times(48)$$
$$Area = 336$$
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