Question 2
Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train is 120 m, in what time will they cross each other traveling in the opposite direction?
Solution
Speed of the first train = $$\frac{120}{10}$$ = 12 m/s
Speed of the second train = $$\frac{120}{15}$$ = 8 m/s
Relative speed = (12 + 8) = 20m/s
So, required time = $$\frac{(120+120)}{20}$$ = 12 sec
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