Assuming that the charge of an electron is $$1.6 \times 10^{-19}$$ C, the number of electrons passing through a section of wire per second when the wire carries a current of 1 A is:
So according to the definition, the formula for the current is:
$$I = \frac{Q}{t}$$
I = 1 A and t = 1 sec
Therefore,
$$Q = I\times{t}$$
$$Q = 1\times{1}$$
Q =Â 1 C
One electon consists of a charge of $$1.6 \times 10^{-19}$$ C. Then the number of electrons passing would be:
$$Q = n\times(e)$$
$$n = \frac{Q}{e}$$
$$n = \frac{1}{1.6 \times 10^{-19}}= 6.25\times10^{18}$$ electrons
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