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RRB ALP 13th Aug 2018 Shift-1 Question 1

Question 1

The value of g on the moon is $$\frac{1}{6^{th}}$$ of the value of g on the earth. If a man can jump 1.5 m high on the earth, on the moon, he can jump up to a height of:

Solution

We have

g moon=$$\frac{1}{6}$$ of g earth

g moon=$$\frac{10}{6}$$

On the earth

g=10$$\frac{m}{s^2}$$ . H=1.5 m

We know that.

v=$$2\sqrt{g}{h}$$

v=$$2\sqrt{10}{1.5}$$

v=$$30\sqrt$$

And v=u. 

So u= $$30\sqrt\frac{m}{sec}$$

And on the moon

h= $$\frac{u^2}{gh}$$

h= $$\frac{30\times 6}{20}$$

h=9m



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