Speed,Time & Distance Questions for SSC CPO Set-2 PDF
Download SSC CPO Speed, Time & Distance Questions with answers set-2 PDF based on previous papers very useful for SSC CPO exams. Very important Speed, Time & Distance Questions for SSC exams.
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Question 1:Â Mohit starts moving from place A and reaches the place B in 12 hours. He covers $\frac{1}{5^{th}}$ part of the total distance at the speed of 6 km/hr and covers the remaining distance at the speed of 8 km/hr. What is the distance between A and B?
a)Â 90 km
b)Â 95 km
c)Â 60 km
d)Â 75 km
Question 2:Â A car covers a certain distance at a speed of 48 km/hr in 14 hours. How much time it will take to cover the same distance at the speed of 84 km/hr?
a)Â 6 hr
b)Â 8 hr
c)Â 9 hr
d)Â 12 hr
Question 3:Â Two stations P and Q are 570 km apart on a straight line. One train starts from P at 5 a.m. and travels towards Q at 90 km/h. Another train starts from Q at 6 a.m. and travels towards P at a speed of 70 km/h. At what time will they meet?
a)Â 11 a.m.
b)Â 9 a.m.
c)Â 1 p.m.
d)Â 3 p.m.
Question 4:Â The ratio between the speeds of two cars is 6 : 5. If the second car runs 600 km in 6 hours, then the speed of the first car is:
a)Â 100 km/hr
b)Â 120 km/hr
c)Â 110 km/hr
d)Â 90 km/hr
Question 5:Â Excluding stoppages, the speed of a bus is 70 kmph and including stoppages, it is 56 kmph. For how many minutes does the bus stop per hour?
a)Â 10 min
b)Â 8 min
c)Â 15 min
d)Â 12 min
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Question 6:Â A train 400 m long passes a pole in 20 seconds. What is the speed of the train?
a)Â 70 km/hr
b)Â 72 km/hr
c)Â 68 km/hr
d)Â 64 km/hr
Question 7:Â A train passes a platform in 42 seconds and a man standing on the platform in 25 seconds. If the speed of the train is 72 km/hr, what is the length of the platform?
a)Â 300 m
b)Â 270 m
c)Â 340 m
d)Â 370 m
Question 8:Â Two trains 85 m and 155 m long, run at the speeds of 62 km/h and 82 km/h respectively, in opposite directions on parallel tracks. The time which they take to cross each other is:
a)Â 4 seconds
b)Â 5 seconds
c)Â 6 seconds
d)Â 8 seconds
Question 9:Â The speed of a ship in still water is 5 km/hr and the speedof the stream is 2km/hr. Rohan rows to place at a distance of 21 km and comes back to the starting point. The total time taken by him is:
a)Â 7.2 hours
b)Â 10 hours
c)Â 3.6 hours
d)Â 6 hours
Question 10:Â The speed of a boat in still water is 9 km/hr and the speed of stream is 3 km/hr. The difference between the upstream speed and downstream speed will be:
a)Â 6 km/hr
b)Â 5 km/hr
c)Â 3.5 km/hr
d)Â 7.5 km/hr
Answers & Solutions:
1) Answer (A)
Let the total distance be x km
Given, Total time taken to reach x km = 12 hours
Speed for $\dfrac{x}{5}$ km = 6 km/hr
Time taken to travel $\dfrac{x}{5}$ km = $\dfrac{x}{5\times6} = \dfrac{x}{30}$ hours
Speed for remaining $\dfrac{4x}{5}$ km = 8 km/hr
Time taken to travel $\dfrac{4x}{5}$ km = $\dfrac{4x}{5\times8} = \dfrac{x}{10}$ hours
Total time = $\dfrac{x}{30}+\dfrac{x}{10} = \dfrac{4x}{30}$ hours
Given, $\dfrac{4x}{30} = 12$ => x = 90
Therefore, Total distance = 90 km
2) Answer (B)
Given, Speed = 48 km/hr
Time = 14 hours
Then, Distance = $48 \times 14 = 672 km$
New speed = 84 km/hr
Then, Time taken = 672/84 = 8 hours
3) Answer (B)
Distance between P and Q = 570 km
Speed of first train = 90 km/hr
Speed of second train = 70 km/hr
Second train starts after 1 hour of start of first train.
Then, First train travels 90 km in that 1 hour.
Remaining distance = 570 km – 90 km = 480 km
Relative speed = 90+70 = 160 km/hr
Time taken to meet = 480/160 = 3 hours.
Hence, They will meet 3 hours after 6am = 9am
4) Answer (B)
Let the speeds of the two cars be 6x km/hr and 5x km/hr.
Given, Speed of second car = 600km/6 hours = 100 km/hr
5x = 100 => x = 20
Therefore, Speed of the first car = 6x = 6*20 = 120 km/hr
5) Answer (D)
Due to stoppages, bus travelled 14 km less in one hour.
Time taken to travel 14 km without stoppages = $\dfrac{14}{70}\times60 = 12$ min
6) Answer (B)
Length of the train = 400 m
Time taken by the train to cross a pole is the time taken by the train to cross its length
Speed of the train = $\dfrac{400}{20} = 20 m/sec = 20 \times \dfrac{18}{5} = 72 km/hr$
7) Answer (C)
Given, Speed of the train = 72 km/hr = $72\times\dfrac{5}{18} = 20 m/sec$
Time taken to cross a man on the platform = 25 seconds
Let the length of the train be T m and length of the platform be P m.
Given, $\dfrac{T}{25} = 20 => T = 500$
Hence, The length of the train = 500 m
Given, $\dfrac{500+P}{42} = 20 => 500+P = 840 => P = 340$
Therefore, The length of the platform = 340 m
8) Answer (C)
As both are travelling in opposite directions relative velocity=62+82=144 km/hr
144*5/18 =40 m/s
Total distance=155+95
=240 m
Time taken=240/40
=6 sec
9) Answer (B)
Speed of upstream =5-2=3 km/hr
Speed of downstream=5+2=7 km/hr
Total time of journey=(21/3)+(21/7)
=7+3
=10 hours
10) Answer (A)
Speed in upstream=9-3 =6 km/hr
Speed in downstream=9+3=12 km/hr
Difference=6 km/hr
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