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Profit and Loss, Discount Questions for SSC CGL Set-3 PDF

Download SSC CGL Profit and Loss, Discount questions with answers set-3 PDF based on previous papers very useful for SSC CGL exams. Very important Profit and Loss, Discount questions for SSC exams.

Question 1: Marked price of an item is Rs 900. On purchase of 2 items discount is 16%, on purchase of 5 items discount is 44%. Raksha buys 7 items, what is the effective discount?

a) 10 percent

b) 16 percent

c) 36 percent

d) 9.6 percent

Question 2: When a discount of 20% is given on a pizza, the profit is 32%. If the discount is 18%, then the profit is

a) 50 percent

b) 64.7 percent

c) 35.3 percent

d) 20.6 percent

Question 3: Marked price of an item is Rs 100. On purchase of 2 items discount is 25%, on purchase of 4 items discount is 43%. Rajasi buys 6 items, what is the effective discount?

a) 37 percent

b) 26.25 percent

c) 9.6 percent

d) 24.6 percent

Question 4: A dishonest milkman buys milk at Rs 25 per litre and adds 1/5 of water to it and sells the mixture at Rs 29 per litre. His gain is

a) 16 percent

b) 39.2 percent

c) 24 percent

d) 32 percent

Question 5: Raghuram sells a machine for Rs 43 lakhs at a loss. Had he sold it for Rs 53 lakh, his gain would have been 7 times the former loss. Find the cost price of the machine.

a) Rs 51.75 lakhs

b) Rs 59.14 lakhs

c) Rs 36.75 lakhs

d) Rs 44.25 lakhs

Question 6: Marked price of an item is Rs 200. On purchase of 1 item discount is 5%, on purchase of 2 items discount is 14%. Rajeshri buys 3 items, what is the effective discount?

a) 37 percent

b) 26.25 percent

c) 11 percent

d) 30.2 percent

Question 7: A rice trader buys 8 quintals of rice for Rs 3,600. 10% rice is lost in transportation. At what rate should he sell to earn 15% profit?

a) Rs 352.1 per quintal

b) Rs 517.5 per quintal

c) Rs 575 per quintal

d) Rs 582.3 per quintal

Question 8: A wholesaler sells a watch to a retailer at a profit of 33% and the retailer sells it to a customer at a loss of 20%. If the customer pays Rs 2,181.2, what had it cost the wholesaler?

a) Rs 2050

b) Rs 2320

c) Rs 2712

d) Rs 1780

Question 9: A shopkeeper by selling 21 Nike shoes, earns a profit equal to the selling price of 5 Nike shoes. His profit percentage is

a) 31.25 percent

b) 23.8 percent

c) 47.6 percent

d) 16.35 percent

Question 10: Ramesh purchases 75 articles for ₹ 10800 and sells them at a loss equal to the selling price of 5 articles. What will be the selling price of one article?

a) ₹156

b) ₹135

c) ₹144

d) ₹132

Marked price of item = Rs. 900

=> Marked price of 2 items = $2 \times 900$ = Rs. 1800

Amount saved on buying 2 items = $\frac{16}{100} \times 1800 = Rs. 288$

Marked price of 5 items = $5 \times 900$ = Rs. 4500

Amount saved on buying 5 items = $\frac{44}{100} \times 4500 = Rs. 1980$

Thus, on buying 7 items, total amount saved = 288 + 1980 = Rs. 2268

Total marked price of 7 items = $7 \times 900$ = Rs. 6300

$\therefore$ Effective discount = $\frac{2268}{6300} \times 100$

= $\frac{2268}{63} = 36 \%$

=> Ans – (C)

Let Marked Price = $Rs. 100x$

When discount is 20%, Selling price = $\frac{100-20}{100} \times 100x = Rs. 80x$

Let Cost price = $Rs. y$

Profit % = $\frac{80x – y}{y} \times 100 = 32$

=> $\frac{80x – y}{y} = \frac{32}{100} = \frac{8}{25}$

=> $2000x – 25y = 8y$

=> $25y + 8y = 2000x$

=> $y = \frac{2000 x}{33} = 60.6x$

When discount is 18%, Selling price = $\frac{100-18}{100} \times 100x = Rs. 82x$

$\therefore$ Profit % = $\frac{82x – 60.6x}{60.6x} \times 100$

$\approx 35.3\%$

=> Ans – (C)

Marked price of item = Rs. 100

=> Marked price of 2 items = $2 \times 100$ = Rs. 200

Amount saved on buying 2 items = $\frac{25}{100} \times 200 = Rs. 50$

Marked price of 4 items = $4 \times 100$ = Rs. 400

Amount saved on buying 4 items = $\frac{43}{100} \times 400 = Rs. 172$

Thus, on buying 6 items, total amount saved = 50 + 172 = Rs. 222

Total marked price of 6 items = $6 \times 100$ = Rs. 600

$\therefore$ Effective discount = $\frac{222}{600} \times 100$

= $\frac{222}{6} = 37 \%$

=> Ans – (A)

The milkman adds $(\frac{1}{5})^{th}$ of water, thus total mixture = $1+\frac{1}{5} = \frac{6}{5}$

Cost price per litre of the mixture = $\frac{25}{\frac{6}{5}} = 25 \times \frac{5}{6} = Rs$ $20.83$

Selling price per litre = Rs. 29

$\therefore$ Profit % = $\frac{29-20.83}{20.83} \times 100$

= $\frac{817}{20.83} \approx 39.2\%$

=> Ans – (B)

Let cost price of the machine = Rs. $x$ lakhs

When selling price = Rs. 43 lakhs

=> Loss = Rs. $(x – 43)$ lakhs

If selling price = Rs. 53 lakhs

=> Profit = Rs. $(53 – x)$ lakhs

According to ques, Profit = 7 $\times$ loss

=> $(53 – x) = 7 \times (x – 43)$

=> $53 – x = 7x – 301$

=> $7x + x = 301 + 53 = 354$

=> $x = \frac{354}{8} =$ Rs. $44.25$ lakhs

=> Ans – (D)

Marked price of item = Rs. 200

Amount saved on buying 1 item = $\frac{5}{100} \times 200 = Rs. 10$

Marked price of 2 items = $2 \times 200$ = Rs. 400

Amount saved on buying 2 items = $\frac{14}{100} \times 400 = Rs. 56$

Thus, on buying 3 items, total amount saved = 10 + 56 = Rs. 66

Total marked price of 3 items = $3 \times 200$ = Rs. 600

$\therefore$ Effective discount = $\frac{66}{600} \times 100$

= $\frac{66}{6} = 11 \%$

=> Ans – (C)

Cost price = Rs. 3600 for 8 quintals

Quantity of rice with the trader after transportation lost = $\frac{100 – 10}{100} \times 8$

= $\frac{36}{5}$ = 7.2 quintals

To have 15% profit, total selling price of the trader should be = $\frac{115}{100} \times 3600$

= Rs. 4140

$\therefore$ Selling price per quintal = $\frac{4140}{7.2} = Rs$ $575$

=> Ans – (C)

For the wholesaler,

Let the cost price = Rs. $100x$

With profit of 33%, Selling price = $\frac{133}{100} \times 100x = Rs. 133x$

For the retailer,

Cost price = Rs. $133x$

With a loss of 20%, Selling price = $\frac{80}{100} \times 133x = Rs. 106.4x$

For the customer,

Cost price = $106.4x = 2181.2$

=> $x = \frac{2181.2}{106.4} = 20.5$

$\therefore$ Cost price for retailer = $100 \times 20.5 = Rs. 2050$

=> Ans – (A)

Let cost price of a shoe = $Rs. x$

Selling price of a shoe = $Rs. y$

=> Selling price of 5 shoes = $Rs. 5y$

According to ques, => $21(y – x) = 5y$

=> $21y – 21x = 5y$

=> $16y = 21x$

=> $\frac{x}{y} = \frac{16}{21}$

Let Cost price, $x = 16$ and selling price, $y = 21$

$\therefore$ Profit % = $\frac{y – x}{x} \times 100$

= $\frac{21 – 16}{16} \times 100$

= $\frac{125}{4} = 31.25\%$

=> Ans – (A)