**Time Speed and Distance Questions for ****SSC CPO PDF**

Download Top-15 SSC CPO Time Speed and Distance Questions and Answers PDF, based on asked questions in previous CPO & other SSC exam papers.

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**Question 1: **A man travels 420 kilometres in, partly by rail and partly by steamer. He spends 8 hours more time on steamer. If the velocity of the steamer is 35 km/hr and the velocity of rail is 65 km/hr, how much distance does he cover by steamer?

a) 395 km

b) 329 km

c) 494 km

d) 592 km

**Question 2: **Manoj can do a piece of work in 42 hours. If he is joined by Jayashree who is 100% more efficient, in what time they will finish the work together?

a) 7 hours

b) 3.5 hours

c) 14 hours

d) 2.5 hours

**Question 3: **A man travels 404 kilometres in partly by rail and steamer. He spends 10 hours more time on steamer. If the speed of the steamer is 30 km/hr and the velocity of rail is 50 km/hr, how much distance does he cover by steamer?

a) 407 km

b) 509 km

c) 610 km

d) 339 km

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**Question 4: **What should be the average speed of a car to cover a distance of 189 km in 3.5 hours?

a) 15 m/s

b) 54 m/s

c) 27 m/s

d) 30 m/s

**Question 5: **To cover a distance of 252 km in 2.5 hours what should be the average speed of the car in meters/second?

a) 100.8 m/s

b) 50.4 m/s

c) 28 m/s

d) 56 m/s

**Question 6: **A thief is stopped by a policeman from a distance of 350 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 7 km/h and that of police man as 12 km/h, how far the thief would have run, before he is overtaken?

a) 490 metres

b) 392 metres

c) 588 metres

d) 294 metres

**Question 7: **A thief is stopped by a policeman from a distance of 200 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 8 km/hr and that of police man as 10 km/hr. How far the thief would have run, before he is overtaken?

a) 640 metres

b) 800 metres

c) 960 metres

d) 480 metres

**Question 8: **4 hrs after a goods train passed a station, another train travelling at a speed of 60 km/hr following that goods train passed through that station. If after passing the station the train overtakes the goods train in 8 hours. What is the speed of the goods train?

a) 40 km/hr

b) 48 km/hr

c) 60 km/hr

d) 32 km/hr

**Question 9: **To travel 648 km, an Express train takes 12 hours more than Rajdhani. If however, the speed of the Express train is doubled, it takes 6 hours less than Rajdhani. The speed of Rajdhani is _____.

a) 36 km/hr

b) 18 km/hr

c) 45 km/hr

d) 27 km/hr

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**Question 10: **9 hrs after a goods train passed a station, another train travelling at a speed of 72 km/hr following that goods train passed through that station. If after passing the station the train overtakes the goods train in 3 hours. What is the speed of the goods train?

a) 21.6 km/hr

b) 27 km/hr

c) 18 km/hr

d) 14.4 km/hr

**Question 11: **A car travels a certain distance at 34 km/h and comes back at 66 km/h. What is the average speed for total journey?

a) 50 km/hr

b) 39.76 km/hr

c) 55.12 km/hr

d) 44.88 km/hr

**Question 12: **Rizvan walks at 15 km/hr and Ruchitha cycles at 20 km/hr towards each other. What was the distance between them when they started if they meet after 42 minutes?

a) 36.8 kms

b) 30.6 kms

c) 24.5 kms

d) 18.4 kms

**Question 13: **To cover a distance of 315 km in 2.8 hours what should be the average speed of the car in meters/second?

a) 112.5 m/s

b) 56.25 m/s

c) 62.5 m/s

d) 31.25 m/s

**Question 14: **To travel 612 km, an Express train takes 9 hours more than Rajdhani. If the speed of the Express train is doubled, it takes 3 hours less than Rajdhani. The speed (in km/hr) of Rajdhani is

a) 40.8

b) 51

c) 30.6

d) 61

**Question 15: **To travel 732 km, an Express train takes 6 hours more than Rajdhani. If the speed of the Express train is doubled, it takes 3 hours less than Rajdhani. The speed of Rajdhani is

a) 81.3 km/hr

b) 61 km/hr

c) 40.7 km/hr

d) 101.7 km/hr

**Question 16: **Ruchir walks at 20 km/hr and Rukma cycles at 25 km/hr towards each other. What was the distance between them when they started if they meet after 48 minutes?

a) 54 km

b) 45 km

c) 36 km

d) 27 km

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**Answers & Solutions:**

**1) Answer (B)**

Let distance covered by steamer = $d$ km

=> Distance covered by rail = $(420 – d)$ km

Let time taken on rail = $t$ hours and time taken on steamer = $(t + 8)$ hours

Speed of rail = 65 km/hr and speed of steamer = 35 km/hr

Using, speed = distance/time

For steamer, $\frac{d}{t + 8} = 35$

=> $d = 35t + 280$ ————–(i)

For rail, $\frac{420 – d}{t} = 65$

Substituting value of $d$ from equation (i), we get :

=> $420 – (35t + 280) = 65t$

=> $420 – 280 = 65t + 35t = 100t$

=> $t = \frac{140}{100} = 1.4$ hours

Substituting value of $t$ in equation (i), => $d = (35 \times 1.4) + 280$

= $49 + 280 = 329$ km

**2) Answer (C)**

Let total work to be done = 42 units

Manoj’s efficiency = $\frac{42}{42} = 1$ unit/hr

Jayashree is 100% more efficient, => Jayashree’s efficiency = $1 + \frac{100}{100} \times 1 = 2$ units/hr

(Manoj + Jayashree)’s 1 day’s work together = 1 + 2 = 3 units/hr

$\therefore$ Time taken by Manoj and Jayashree together to finish the work = $\frac{42}{3} = 14$ hours

=> Ans – (C)

**3) Answer (D)**

Let distance covered by steamer = $d$ km

=> Distance covered by rail = $(404 – d)$ km

Let time taken on rail = $t$ hours and time taken on steamer = $(t + 10)$ hours

Speed of rail = 50 km/hr and speed of steamer = 30 km/hr

Using, speed = distance/time

For steamer, $\frac{d}{t + 10} = 30$

=> $d = 30t + 300$ ————–(i)

For rail, $\frac{404 – d}{t} = 50$

Substituting value of $d$ from equation (i), we get :

=> $404 – (30t + 300) = 50t$

=> $404 – 300 = 50t + 30t = 80t$

=> $t = \frac{104}{80} = 1.3$ hours

Substituting value of $t$ in equation (i), => $d = (30 \times 1.3) + 300$

= $39 + 300 = 339$ km

**4) Answer (A)**

The car covers 189 km in 3.5 hours

Speed of car (in km/h) = $\frac{189}{3.5} = 54$ km/hr

=> Speed of car (in m/s) = $54 \times \frac{5}{18}$

= $3 \times 5 = 15$ m/s

=> Ans – (A)

**5) Answer (C)**

The car covers 252 km in 2.5 hours

Speed of car (in km/h) = $\frac{252}{2.5} = 100.8$ km/hr

=> Speed of car (in m/s) = $100.8 \times \frac{5}{18}$

= $5.6 \times 5 = 28$ m/s

=> Ans – (C)

**6) Answer (A)**

Since the thief is escaping from the police man, thus they both are running in same direction.

Speed of thief = 7 km/hr and speed of policeman = 12 km/hr

=> Relative speed = 12 – 7 = 5 km/hr

Distance between them = 350 metres = 0.35 km

=> Time taken = $\frac{distance}{speed}$

= $\frac{0.35}{5} = \frac{7}{100}$ hr

$\therefore$ Distance covered by thief before he was caught = $7 \times \frac{7}{100}$

= 0.49 km = 490 metres

=> Ans – (A)

**7) Answer (B)**

Since the thief is escaping from the police man, thus they both are running in same direction.

Speed of thief = 8 km/hr and speed of policeman = 10 km/hr

=> Relative speed = 10 – 8 = 2 km/hr

Distance between them = 200 metres = 0.2 km

=> Time taken = $\frac{distance}{speed}$

= $\frac{0.2}{2} = \frac{1}{10}$ hr

$\therefore$ Distance covered by thief before he was caught = $8 \times \frac{1}{10}$

= 0.8 km = 800 metres

**8) Answer (A)**

Let the speed of goods train = $x$ km/hr

Speed of another train = 60 km/hr

Distance between the two trains = $60 \times 4 = 240$ km

The trains are moving in same direction, => Relative speed = $(60 – x)$ km/hr

Time = 4 + 8 = 12 hours

=> speed = distance/time

=> $60 – x = \frac{240}{12} = 20$

=> $x = 60 – 20 = 40$ km/hr

=> Ans – (A)

**9) Answer (D)**

Let speed of Rajdhani train = $x$ km/hr and Express train = $y$ km/hr

Using, time = distance/speed

Acc. to ques, => $\frac{648}{y} – \frac{648}{x} = 12$

=> $\frac{1}{y} – \frac{1}{x} = \frac{12}{648} = \frac{1}{54}$ —————-(i)

If speed of express train is doubled = $2y$ km/hr

=> $\frac{648}{x} – \frac{648}{2y} = 6$

=> $\frac{1}{x} – \frac{1}{2y} = \frac{6}{648} = \frac{1}{108}$ —————-(ii)

Adding equations (i) and (ii), we get :

=> $\frac{1}{y} – \frac{1}{2y} = \frac{1}{54} + \frac{1}{108}$

=> $\frac{1}{2y} = \frac{3}{108}$

=> $y = \frac{108}{6} = 18$ km/hr

$\therefore$ Speed of Rajdhani = $\frac{1}{x} = \frac{1}{18} – \frac{1}{54}$

=> $\frac{1}{x} = \frac{2}{54} = \frac{1}{27}$

=> $x = 27$ km/hr

**10) Answer (C)**

Let the speed of goods train = $x$ km/hr

Speed of another train = 72 km/hr

Distance between the two trains = $72 \times 9 = 648$ km

The trains are moving in same direction, => Relative speed = $(72 – x)$ km/hr

Time = 9 + 3 = 12 hours

=> speed = distance/time

=> $72 – x = \frac{648}{12} = 54$

=> $x = 72 – 54 = 18$ km/hr

**11) Answer (D)**

Average speed of the journey is the harmonic mean of the speeds 34 and 66 km/hr

Harmonic mean of two numbers ‘x’ and ‘y’ = $\frac{2}{\frac{1}{x} + \frac{1}{y}}$

Average speed = $\frac{2}{\frac{1}{34} + \frac{1}{66}}$

= $2 \div {\frac{66 + 34}{66 \times 34}} = \frac{2 \times 66 \times 34}{100}$

= $\frac{4488}{100} = 44.88$ km/hr

=> Ans – (D)

**12) Answer (C)**

Speed of Rizvan = 15 km/hr and Ruchitha = 20 km/hr

Since they are moving in opposite direction, => Relative speed = 20 + 15 = 35 km/hr

Let distance between them = $d$ km and time = $\frac{42}{60}$ hr

=> time = distance/speed

=> $\frac{d}{35} = \frac{42}{60}$

=> $d = \frac{42}{60} \times 35 = \frac{7 \times 7}{2}$

=> $d = \frac{49}{2} = 24.5$ km

**13) Answer (D)**

Distance = 315 km and time = 2.8 hours

Speed = distance/time

=> Speed = $\frac{315}{2.8} = \frac{45}{0.4}$ km/hr

$\therefore$ Speed in meters/second = $\frac{45}{0.4} \times \frac{5}{18}$

= $\frac{25}{0.8} = 31.25$ m/s

**14) Answer (A)**

Let speed of Rajdhani train = $x$ km/hr and Express train = $y$ km/hr

Using, time = distance/speed

Acc. to ques, => $\frac{612}{y} – \frac{612}{x} = 9$

=> $\frac{1}{y} – \frac{1}{x} = \frac{9}{612} = \frac{1}{68}$ —————-(i)

If speed of express train is doubled = $2y$ km/hr

=> $\frac{612}{x} – \frac{612}{2y} = 3$

=> $\frac{1}{x} – \frac{1}{2y} = \frac{3}{612} = \frac{1}{204}$ —————-(ii)

Adding equations (i) and (ii), we get :

=> $\frac{1}{y} – \frac{1}{2y} = \frac{1}{68} + \frac{1}{204}$

=> $\frac{1}{2y} = \frac{4}{204}$

=> $y = \frac{102}{4} = \frac{51}{2}$ km/hr

$\therefore$ Speed of Rajdhani = $\frac{1}{x} = \frac{2}{51} – \frac{1}{68}$

=> $\frac{1}{x} = \frac{1}{17} \times \frac{5}{12}$

=> $x = \frac{204}{5} = 40.8$ km/hr

**15) Answer (B)**

Let speed of Rajdhani train = $x$ km/hr and Express train = $y$ km/hr

Using, time = distance/speed

Acc. to ques, => $\frac{732}{y} – \frac{732}{x} = 6$

=> $\frac{1}{y} – \frac{1}{x} = \frac{6}{732} = \frac{1}{122}$ —————-(i)

If speed of express train is doubled = $2y$ km/hr

=> $\frac{732}{x} – \frac{732}{2y} = 3$

=> $\frac{1}{x} – \frac{1}{2y} = \frac{3}{732} = \frac{1}{244}$ —————-(ii)

Adding equations (i) and (ii), we get :

=> $\frac{1}{y} – \frac{1}{2y} = \frac{1}{122} + \frac{1}{244}$

=> $\frac{1}{2y} = \frac{3}{244}$

=> $y = \frac{122}{3}$ km/hr

$\therefore$ Speed of Rajdhani = $\frac{1}{x} = \frac{3}{122} – \frac{1}{122}$

=> $\frac{1}{x} = \frac{2}{122} = \frac{1}{61}$

=> $x = 61$ km/hr

**16) Answer (C)**

Speed of Rizvan = 20 km/hr and Ruchitha = 25 km/hr

Since they are moving in opposite direction, => Relative speed = 20 + 25 = 45 km/hr

Let distance between them = $d$ km and time = $\frac{48}{60} = \frac{4}{5}$ hr

=> time = distance/speed

=> $\frac{d}{45} = \frac{4}{5}$

=> $d = \frac{4}{5} \times 45 = 4 \times 9$

=> $d = 36$ km

We hope this Time Speed and Distance Questions PDF for SSC CPO Exam will be highly useful for your preparation.