Simplification Questions for Bank CLERK PDF
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Instructions
What should come in place of question mark (?) in the following question ?
Question 1: $[(144)^{2}\div48\times18]\div36=\sqrt{?}$
a) 23328
b) 36
c) 216
d) 46656
e) None of these
Question 2: $(27)^{18}\div(27)^{3}=?$
a) $(27)^{54}$
b) $(27)^{21}$
c) $(27)^{15}$
d) $(27)^{6}$
e) None of these
Question 3: $5\frac{1}{4}+6\frac{2}{3}+7\frac{1}{6}=?$
a) 19.5
b) $19\frac{11}{12}$
c) $19\frac{1}{12}$
d) 19
e) None of these
Question 4: $4895+364\times0.75-49=?$
a) 5119
b) 3895
c) 3907
d) 5210
e) None of these
Instructions
What should come in place of the question mark (?) in the following number series?
Question 5: $\frac{1}{4}, \frac{1}{2}, \frac{3}{4}, 1, 1\frac{1}{4}, 1\frac{1}{2}, 1\frac{3}{4}, ?$
a) 2
b) 4
c) 61
d) 41
e) 21
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Question 6: What will come in place of both the question marks (?) in the following question ?$\frac{(?)^{0.6}}{104}=\frac{26}{(?)^{1.4}}$
a) 58
b) -48
c) -56
d) 42
e) -52
Question 7: Out of the fractions $\frac{1}{2}, \frac{7}{8}, \frac{3}{4}, \frac{5}{6}$, and $\frac{6}{7}$ what is the difference between the largest and smallest fractions ?
a) $\frac{7}{13}$
b) $\frac{3}{8}$
c) $\frac{4}{7}$
d) $\frac{1}{6}$
e) None of these
Question 8: If $(11)^{3}$ is subtracted from $(46)^{2}$ . what will be the remainder ?
a) 787
b) 785
c) 781
d) 783
e) None of these
Question 9: 90.05 + 281 ÷ 4 -151.06 = $\sqrt[3]{?}$
a) 27
b) 343
c) 216
d) 729
e) 176
Question 10: $17.98^{2} + 4.05 \times 90.11 \div 4.98 = ?$
a) 396
b) 336
c) 242
d) 423
e) 816
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Answers & Solutions:
1) Answer (D)
Lets assume the unknown number to be x.
Now, we will solve in a stepwise manner going by BODMAS rule.
144^2=20736,
20736/48=432
432*18=7776
7776/36=216
Now x=216^2 = 46656 which is option D.
2) Answer (C)
We know that, by the rule of indices,
ab $\div$ ac = a(b-c)
Hence, $(27)^{18}\div(27)^{3}=(27)^{(18-3)}$ = $(27)^{15}$
Hence, Option C is correct option.
3) Answer (C)
First, we convert mixed fractions into proper fractions:
$5\frac{1}{4}=\frac{21}{4}$
$6\frac{2}{3}=\frac{20}{3}$
$7\frac{1}{6}=\frac{43}{6}$
Now, $5\frac{1}{4}+6\frac{2}{3}+7\frac{1}{6}=\frac{21}{4}+\frac{20}{3}+\frac{43}{6}$
= $\frac{229}{12}$
In mixed fraction form 229/12 = $19\frac{1}{12}$
Option C is correct.
4) Answer (A)
The problem can be solved by applying BODMAS rule in a stepwise manner.
$364\times0.75$ = 273
Now, 4895+273= 5168
5168 – 49 = 5119 which is option A.
5) Answer (A)
$\frac{1}{4}$ is added to each number
$\frac{1}{4}$ + $\frac{1}{4}$ = $\frac{1}{2}$
$\frac{1}{2}$ + $\frac{1}{4}$ = $\frac{3}{4}$
$\frac{3}{4}$ + $\frac{1}{4}$ = 1
1 + $\frac{1}{4}$ = $1\frac{1}{4}$
$1\frac{1}{4}$ + $\frac{1}{4}$ = $1\frac{1}{2}$
$1\frac{1}{2}$ + $\frac{1}{4}$ = $1\frac{3}{4}$
$1\frac{3}{4}$ + $\frac{1}{4}$ = 2
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6) Answer (E)
$\frac{(x)^{0.6}}{104}=\frac{26}{(x)^{1.4}}$
${(x)^{0.6}} * {(x)^{01.4}}$ = 104*26
${(x)^{2}}$ = 104*26
x = ±52
7) Answer (B)
Given values are ,
$\frac{1}{2}$ = 0.5
$\frac{7}{8}$ = 0.87
$\frac{3}{4}$ = 0.75
$\frac{5}{6}$ = 0.83
$\frac{6}{7}$ = 0.86
∴ Required difference = $\frac{7}{8}$ – $\frac{1}{2}$ = (7-4)/8 = 3/8
8) Answer (B)
Here
$(46)^2$ = 2116
$(11)^3$ = 1331
So, 2116 – 1331 = 785
9) Answer (D)
The given statement can be written as $90 + 60 – 151 = \sqrt[3]{?}$
$9 =\sqrt[3]{?}$
=> ? = 729
Option D is the answer.
10) Answer (A)
The given equation can be written as $18^{2} + \frac{4*90}{5}$
= $324 + 4*18$
= $396$
Option A is the right answer.
