**Time Speed and Distance Questions for IBPS PO PDF**

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**Question 1:Â **A 260 meter long train crosses a 120 meter long wall in 19 seconds .What is the speed of the train?

a)Â 27 km/hr

b)Â 49 km/hr

c)Â 72 km/hr

d)Â 70 km/hr

e)Â None of these

**Question 2:Â **A train running at speed of 120 kmph crosses a signal in 15 seconds .What is the length of the train in meters?

a)Â 300

b)Â 200

c)Â 500

d)Â Cannot determined

e)Â None of these

**Question 3:Â **A boat takes a total time of eight hours to travel 63 kms upstream and the same distance downstream. The speed of the current is ${1 \over 8}$th of the speed of the boat in still water. What is the speed of the boat in still water? (in km/hr)

a)Â 32

b)Â 24

c)Â 16

d)Â 8

e)Â 38

**Question 4:Â **Yesterday Priti type an essay of 5000 words at the speed of 60 words per minute: Today she type the same essay faster and her speed was 15% more than yesterday. What is the **approximate **difference in the time she took to type yesterday and the time she took to type today?

a)Â 20 minutes

b)Â 30 minutes

c)Â 10 minutes

d)Â 40 minutes

e)Â 1 hour

**Question 5:Â **A boat goes downstream at the rate of 9 kmph and upstream at the rate of 6 kmph. Find the speed of current.

a)Â 1.5 kmph

b)Â 2 kmph

c)Â 7.5 kmph

d)Â 4.5 kmph

e)Â None of these

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**Question 6:Â **A train running at the speed of 108 kmph, crosses a 365 metre long platform in 21 seconds. What is the length of the train ?

a)Â 260 metres

b)Â 275 metres

c)Â 265 metres

d)Â 285 metres

e)Â None of these

**Question 7:Â **The distance between Shauryaâ€™s house and Pratyushaâ€™s house is 18 km. Shauryaâ€™s speed is 3/7th of that Pratyusha. Shaurya takes one hour in going to Pratyushaâ€™s house. What is the speed of Pratyusha ?

a)Â 18 kmph

b)Â 24 kmph

c)Â 30 kmph

d)Â 32 kmph

e)Â None of these

**Question 8:Â **A man can row threeÂquarters of a kilometre against the stream in 45/4 min and return in 15/2 min. The speed of the man in still water is :

a)Â 2 km/h

b)Â 3 km/h

c)Â 4 km/h

d)Â 5 km/h

e)Â 6 km/h

**Question 9:Â **Three typists P, Q and R have to type 368 pages. P types one page in 8 minutes, Q in 18 minutes and R in 24 minutes. In what time will these pages be typed if they work together?

a)Â 25 hours

b)Â 27.6 hours

c)Â 27 hours

d)Â 28 hours

e)Â None of these

**Question 10:Â **A train crossed a platform in 25 seconds. The length of the platform is 240 metres. What is the length of train ?

a)Â 140 metres

b)Â 200 metres

c)Â 180 metres

d)Â Cannot be determined

e)Â None of these

**Answers & Solutions:**

**1)Â AnswerÂ (C)**

Length of the train is 260 metres

Length of the wall is 120 metres

total is 260+120 = 380 metres

Time taken is 19 seconds.

Hence, the speed is 380/19 = 20 m/s = 72 Km/hr

Answer is option C

**2)Â AnswerÂ (C)**

Speed of train = 120 kmph

= $(120 \times \frac{5}{18})$ m/s = $\frac{100}{3}$ m/s

Let length of the train = $l$ meters

Using, speed = distance/time

=> $\frac{100}{3} = \frac{l}{15}$

=> $l=\frac{100}{3} \times 15$

=> $l=100 \times 5=500$ meters

=> Ans – (C)

**3)Â AnswerÂ (C)**

Let speed of current = $x$ km/hr

=> Speed of boat in still water = $8x$ km/hr

Acc. to ques, => $\frac{63}{9x} + \frac{63}{7x} = 8$

=> $\frac{7}{x} + \frac{9}{x} = 8$

=> $\frac{16}{x} = 8$

=> $x = \frac{16}{8} = 2$

$\therefore$ Speed of boat in still water = $8 \times 2 = 16$ km/hr

**4)Â AnswerÂ (C)**

Priti’s second day typing speed = $\frac{115}{100} \times 60$ = 69 wpm

Required difference in time

= $(\frac{5000}{60} – \frac{5000}{69})$

= $5000(\frac{69 – 60}{60 \times 69})$

$\approx$ 10 minutes

**5)Â AnswerÂ (A)**

Speed of current = $\frac{1}{2}$ (downstream – upstream)

= $\frac{1}{2} (9 – 6)$

= $\frac{3}{2} = 1.5$ kmph

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**6)Â AnswerÂ (C)**

Speed of train = 108 kmph

= $108 \times \frac{5}{18}$ = 30 m/s

Let the length of the train = $l$ metre

=> $\frac{l + 365}{21} = 30$

=> $l + 365 = 21 \times 30 = 630$

=> $l = 630 – 365 = 265$ metre

**7)Â AnswerÂ (E)**

Shaurya’s speed = $\frac{18}{1}$ = 18 kmph

=> Speed of Pratyusha = $18 \times \frac{7}{3}$

= 42 kmph

**8)Â AnswerÂ (D)**

$speed = \frac{distance}{time}$

=> Upstream speed = $\frac{\frac{3}{4}}{\frac{45}{4} \times \frac{1}{60}}$

= $\frac{3 \times 60}{45} = 4$ km/h

Downstream speed =Â $\frac{\frac{3}{4}}{\frac{15}{2} \times \frac{1}{60}}$

= $\frac{3 \times 2 \times 60}{15 \times 4} = 6$ km/h

$\therefore$ Speed of man in still water = $\frac{1}{2}$ (downstream + upstream)

= $\frac{1}{2} (6 + 4)$

= $\frac{10}{2} = 5$ km/h

**9)Â AnswerÂ (B)**

Pages printed by P, Q and R in one minute

= $\frac{1}{8} + \frac{1}{18} + \frac{1}{24}$

= $\frac{9 + 4 + 3}{72} = \frac{16}{72}$

= $\frac{2}{9}$

Number of pages to be printed = 368

$\therefore$ Time taken = $\frac{9}{2} \times 368$

= $1656$ minutes

= $\frac{1656}{60} = 27.6$ hours

**10)Â AnswerÂ (D)**

Since the speed of train is not mentioned So we cannot determine the distance covered by train in 25 seconds and hence we cannot determine the length of the train.

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