Time and Work Questions for SSC CPO PDF
Download Top-15 SSC CPO Time and Work Questions and Answers PDF, based on asked questions in previous CPO & other SSC exam papers.
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Question 1: A can do a work in 15 days and B in 20 days. If they work on it together for 5 days, then what fraction of work is left?
a) 2/9
b) 3/10
c) 5/12
d) 1/4
Question 2: Manoj can do a piece of work in 42 hours. If he is joined by Jayashree who is 100% more efficient, in what time they will finish the work together?
a) 7 hours
b) 3.5 hours
c) 14 hours
d) 2.5 hours
Question 3: Prahlad has done 1/3rd of a job in 30 days, Sarfaraz completes the rest of the job in 90 days. In how many days can they together do the job?
a) 27 days
b) 18 days
c) 54 days
d) 36 days
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Question 4: Mahmood can do a piece of work in 40 hours. If he is joined by Janaki who is 50% more efficient, in what time will they together finish the work?
a) 2 hours
b) 6 hours
c) 16 hours
d) 3 hours
Question 5: Painter ‘A’ can paint a house in 10 days and ‘B’ can do it in 20 days. With help of ‘C’, they did the job in 5 days only. Then, ‘C’ alone can do the job in:
a) 20 days
b) 10 days
c) 40 days
d) 50 days
Question 6: Munni can bake 70 cakes in 7 hours, Munni and Guddi together can bake 90 cakes in 6 hours. How many cakes Guddi can bake in 10 hours?
a) 100
b) 50
c) 125
d) 25
Question 7: Amal is 5 times as good a workman as Bhairav and therefore is able to finish a job in 48 days less than Bhairav. Working together, they can do it in
a) 20 days
b) 5 days
c) 25 days
d) 10 days
Question 8: A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
a) 75 days
b) 37.5 days
c) 17.5 days
d) 35 days
Question 9: A can do a work in 15 days and B in 20 days. If they work on it together for 6 days, then what fraction of work is left?
a) 1/4
b) 2/9
c) 1/5
d) 3/10
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Question 10: Meghnad can do a piece of work in 45 hours. If he is joined by Jayshri, who is 50% more efficient, in what time will they together finish the work?
a) 9 hours
b) 6 hours
c) 12 hours
d) 18 hours
Question 11: Mother can bake 20 cakes in 4 hours, Mother and Dadima together can bake 60 cakes in 10 hours. How many cakes Dadima can bake in 30 hours?
a) 30
b) 75
c) 60
d) 25
Question 12: A mason can build a wall in 18 hours. After 9 hours he takes a break. What fraction of the wall is yet to be built?
a) 0.9
b) 0.25
c) 0.5
d) 0.2
Question 13: Praful has done 1/2 of a job in 30 days, Sarabjit completes the rest of the job in 10 days. In how many days can they together do the job?
a) 30 days
b) 45 days
c) 15 days
d) 60 days
Question 14: Pradeep has done 1/4th of a job in 14 days, Saquib completes the rest of the job in 56 days. In how many days can they together complete the job?
a) 64 days
b) 32 days
c) 16 days
d) 8 days
Question 15: Jaikishen can do a piece of work in 15 hours. If he is joined by Jhanvi who is 50% more efficient, in what time will they together finish the work?
a) 6 hours
b) 12 hours
c) 3 hours
d) 9 hours
Question 16: Which planet has the maximum number of satellites?
a) Jupiter
b) Earth
c) Neptune
d) Saturn
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Answers & Solutions:
1) Answer (C)
Let total work to be done = 60 units
A’s efficiency = $\frac{60}{15} = 4$ units/day
B’s efficiency = $\frac{60}{20} = 3$ units/day
(A + B)’s 1 day’s work together = 4 + 3 = 7 units/day
Now, work done by them together in 5 days = $5 \times 7 = 35$ units
=> Work left = 60 – 35 = 25 units
$\therefore$ Fraction of work that is left = $\frac{25}{60} = \frac{5}{12}$
=> Ans – (C)
2) Answer (C)
Let total work to be done = 42 units
Manoj’s efficiency = $\frac{42}{42} = 1$ unit/hr
Jayashree is 100% more efficient, => Jayashree’s efficiency = $1 + \frac{100}{100} \times 1 = 2$ units/hr
(Manoj + Jayashree)’s 1 day’s work together = 1 + 2 = 3 units/hr
$\therefore$ Time taken by Manoj and Jayashree together to finish the work = $\frac{42}{3} = 14$ hours
=> Ans – (C)
3) Answer (C)
Let total work to be done = 90 units
Work done by Prahlad in 30 days = $\frac{1}{3} \times 90 = 30$ units
Prahlad’s efficiency = $\frac{30}{30} = 1$ unit/day
Remaining work = 90 – 30 = 60 units
Sarfaraz completes 60 units in 90 days
=> Sarfaraz’s efficiency = $\frac{60}{90} = \frac{2}{3}$ units/day
(Prahlad + Sarfaraz)’s 1 day’s work = $1 + \frac{2}{3} = \frac{5}{3}$ units/day
$\therefore$ Time taken by them together to do the job = $\frac{90}{\frac{5}{3}}$
= $90 \times \frac{3}{5} = 54$ days
=> Ans – (C)
4) Answer (C)
Let total work to be done = 80 units
Mahmood’s efficiency = $\frac{80}{40} = 2$ units/hr
Janaki is 50% more efficient than Mahmood, => Janaki’s efficiency = $\frac{150}{100} \times 2 = 3$ units/hr
=> Mahmood and Janaki 1 day’s work = 2 + 3 = 5 units/hr
$\therefore$ Time taken by them to finish the work together = $\frac{80}{5} = 16$ hours
=> Ans – (C)
5) Answer (A)
Let total work to be done = 100 units
Painter ‘A’ can paint a house in 10 days and ‘B’ can do it in 20 days
=> A’s efficiency = $\frac{100}{10} = 10$ units/day
B’s efficiency = $\frac{100}{20} = 5$ units/day
Let C’s efficiency = $x$ units/day
According to ques, all of them complete the job in 5 days
=> $(10+5+x) \times 5 = 100$
=> $x+15=\frac{100}{5}=20$
=> $x=20-15=5$
$\therefore$ Time taken by C alone to do the job = $\frac{100}{5}=20$ days
=> Ans – (A)
6) Answer (B)
Cakes baked by Munni in 1 hour = $\frac{70}{7} = 10$
Cakes baked by Munni and Guddi together in 1 hour = $\frac{90}{6} = 15$
=> Cakes baked by Guddi in 1 hour = 15 – 10 = 5
$\therefore$ Cakes baked by Guddi in 10 hours = 10 $\times$ 5 = 50
=> Ans – (B)
7) Answer (D)
Ratio of times taken by Amal and Bhairav = 1 : 5
The time difference is (5 – 1) = 4 days while Bhairav takes 5 days and Amal takes 1 day.
If difference of time is 4 days, Bhairav takes 5 days.
If difference of time is 48 days, Bhairav takes = $\frac{5}{4} \times 48 = 60$ days
=> Amal takes 12 days
Amal’s 1 day’s work = $\frac{1}{12}$
Bhairav’s 1 day’s work = $\frac{1}{60}$
=> (Amal + Bhairav)’s 1 day’s work = $\frac{1}{12} + \frac{1}{60} = \frac{6}{60} = \frac{1}{10}$
$\therefore$ Amal and Bhairav together can do the work in 10 days.
8) Answer (B)
Work done by A in 20 days = $\frac{80}{100} = \frac{4}{5}$
Work done by A in 1 day = $\frac{\frac{4}{5}}{20} = \frac{4}{100} = \frac{1}{25}$
Work done by A and B in 3 days = $\frac{20}{100} = \frac{1}{5}$ (Because remaining 20% is done in 3 days by A and B)
Work done by A and B in 1 day = $\frac{1}{15}$
Work done by B in 1 day = $\frac{1}{15} – \frac{1}{25} = \frac{2}{75}$
=> B can complete the work in $\frac{75}{2}$ days = 37.5 days
9) Answer (D)
Let total work to be done = 60 units
A’s efficiency = $\frac{60}{15} = 4$ units/day
B’s efficiency = $\frac{60}{20} = 3$ units/day
=> (A + B)’s 1 day’s work = 4 + 3 = 7 units/day
Work done by A and B together in 6 days = $6 \times 7 = 42$ units
=> Work left = 60 – 42 = 18 units
$\therefore$ Fraction of work that is left = $\frac{18}{60} = \frac{3}{10}$
10) Answer (D)
Let total work to be done = 90 units
Meghnad’s efficiency = $\frac{90}{45} = 2$ units/hr
Jayshri is 50% more efficient than Meghnad, => Jayshri’s efficiency = $\frac{150}{100} \times 2 = 3$ units/hr
=> Meghnad and Jayshri 1 day’s work = 2 + 3 = 5 units/hr
$\therefore$ Time taken by them to finish the work together = $\frac{90}{5} = 18$ hours
11) Answer (A)
Cakes baked by Mother in 1 hour = $\frac{20}{4} = 5$
Cakes baked by Mother and Dadima together in 1 hour = $\frac{60}{10} = 6$
=> Cakes baked by Dadima in 1 hour = 6 – 5 = 1
$\therefore$ Cakes baked by Dadima in 30 hours = 30 $\times$ 1 = 30
12) Answer (C)
Let total work to be done = 18 units
Mason’s efficiency = $\frac{18}{18} = 1$ unit/hr
Work done by the mason in 9 hours = $9 \times 1 = 9$ units
=> Work left = 18 – 9 = 9 units
$\therefore$ Fraction of work that is left = $\frac{9}{18} = \frac{1}{2}$
= 0.5
13) Answer (C)
Let total work to be done = 60 units
Praful has done 1/2 of a job i.e. $\frac{60}{2} = 30$ units in 30 days
=> Praful’s efficiency = $\frac{30}{30} = 1$ unit/day
Work left = 60 – 30 = 30 units which is done by Sarabjit in 10 days
=> Sarabjit’s efficiency = $\frac{30}{10} = 3$ units/day
Praful and Sarabjit 1 day’s work = 1 + 3 = 4 units/day
$\therefore$ Time taken by them together to complete the work = $\frac{60}{4} = 15$ days
14) Answer (B)
Let total work to be done = 56 units
Pradeep has done 1/4 of a job i.e. $\frac{56}{4} = 14$ units in 14 days
=> Pradeep’s efficiency = $\frac{14}{14} = 1$ unit/day
Work left = 56 – 14 = 42 units which is done by Saquib in 56 days
=> Saqub’s efficiency = $\frac{42}{56} = 0.75$ units/day
Pradeep and Saquib 1 day’s work = 1 + 0.75 = 1.75 units/day
$\therefore$ Time taken by them together to complete the work = $\frac{56}{1.75} = 32$ days
15) Answer (A)
Let total work to be done = 30 units
Jaikishen’s efficiency = $\frac{30}{15} = 2$ units/hr
Jhanvi is 50% more efficient, => Jhanvi’s efficiency = $\frac{150}{100} \times 2 = 3$ units/hr
Jaikishen and Jhanvi 1 hour’s work = 2 + 3 = 5 units/hr
=> Time taken by them to finish the work together = $\frac{30}{5} = 6$ hours
16) Answer (A)
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