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# Time and Work Questions for RBI Grade B PDF

Download Very important RBI Grade-B Time and Work Questions with solutions PDF. This PDF covers Top-15 Time and Work questions and answers for RBI Grade-B exam based on previous year asked questions from RBI and other Banking exams.

Question 1: 12 men can finish a project in 20 days. 18 women can finish the same project in 16 days and 24 children can finish it in 18 days. 8 women and 16 children worked for 9 days and then left. In how many days will 10 men complete the remaining project ?

a) $10\frac{1}{2}$

b) 10

c) 9

d) $11\frac{1}{2}$

e) $9\frac{1}{2}$

Question 2: Sixteen men and twelve women can complete a work in 8 days, if 20 men can complete the same work in 16 days, in how many days 16 women can complete the same piece of work ?

a) 12

b) 8

c) 10

d) 15

e) 20

Question 3: A project requires 12 women to complete it in 16 days. 12 women started working and after a few days from the start of the project, 4 women left. If the remaining project was completed in 18 days, in how many days the whole project was completed?

a) $24{1 \over 2}$

b) 26

c) 22

d) $21{1 \over 2}$

e) 20

Question 4: B is ${4 \over 3}$ times as efficient as A. If A can complete ${5 \over 8}$th of a given task in 15 days, what fraction of the same task would remain incomplete if B works on it independently for 10 days only?

a) ${3 \over 4}$

b) ${2 \over 3}$

c) ${5 \over 8}$

d) ${4 \over 9}$

e) ${2 \over 7}$

Question 5: B is 1.5 times as efficient as A. If A can complete ${6 \over 7}$th of a given task in 12 days, what fraction of the same task would remain incomplete if B works on it independently for 6 days only?

a) ${2 \over 5}$

b) ${3 \over 5}$

c) ${4 \over {10}}$

d) ${5 \over {14}}$

e) ${3 \over 7}$

Question 6: A and B together can complete a particular task in 6 days. If A alone can complete the same task in 10 days, how many days will B take to complete the task if he works alone ?

a) 15

b) 16

c) 14

d) 12

e) None of these

Question 7: A and B together can complete a particular task in 8 days. If B alone can complete the same task in 10 days, how many days will A take to complete the task if he works alone?

a) 28

b) 36

c) 40

d) 32

e) None of these

Question 8: A work can be finished In 14 days by 36 workers. If the work were to be finished in 8 days, how many additional workers would be required ?

a) 29

b) 33

c) 23

d) 31

e) 27

Question 9: A and B together can complete a piece of work in 16 days. B alone can complete the same work in 24 days. In how many days can A alone complete the same work?

a) 34 days

b) 50 days

c) 48 days

d) 42 days

e) None &these;

Question 10: The part of work done by A in 1 day is 1/5th of the part of work done by B in 1 day. A’ s 1 day’s work is 3/4th of C’s 1 day’s work. C alone can complete the work in 24 days. In how many days will B alone do the same work ?

a) $8\frac{2}{5}days$

b) $6\frac{2}{5}days$

c) $4\frac{2}{5}days$

d) $3\frac{2}{5}days$

e) None of these

Question 11: A alone can finish a piece of work in 42 days. B is 20% more efficient than A and C is 40% more efficient than B. In how many days B and C working together can finish the same piece of work? (in days)

a) $11\frac{5}{12}$

b) $13\frac{5}{12}$

c) $15\frac{1}{12}$

d) $14\frac{7}{12}$

e) $12\frac{11}{12}$

Question 12: A 240-metre long train running at the speed of 60 kmph will take how much time to cross another 270-metre long train running in opposite direction at the speed of 48 kmph?

a) 17 seconds

b) 3 seconds

c) 12 seconds

d) 8 seconds

e) None of these

Question 13: A water tank has one inlet, A and one outlet, B. A takes 5 hours to fill the empty tank, when B is not open and B takes 8 hours to empty the full tank. If the tank is three fifth full, how much time will it take to fill the tank completely when both A and B are opened simultaneously ? (in hours)

a) $6\frac{1}{3}$

b) $4\frac{1}{3}$

c) $8\frac{1}{3}$

d) $5\frac{1}{3}$

e) $7\frac{1}{3}$

Question 14: A project manager hired 16 men to complete a project in 38 days. However, after 30 days, he realized that only 5/9th of the work is complete. How many more men does he need to hire to complete the project on time ?

a) 48

b) 24

c) 32

d) 16

e) 36

Question 15: Two stations, A and B are 850 km apart from each other. One train starts from station A at 5 am and travels towards station at 62 kmph. Another train starts from station B at 7 am and travels towards station A at 59 kmph. At what time will they meet

a) 1 pm

b) 11 : 45 am

c) 12 : 30 pm

d) 1 : 30 pm

e) None of these

12 men can finish the project in 20 days.

=> 1 day work of 1 man = $\frac{1}{12 \times 20} = \frac{1}{240}$

Similarly, => 1 day work of 1 woman = $\frac{1}{18 \times 16} = \frac{1}{288}$

=> 1 day work of 1 children = $\frac{1}{24 \times 18} = \frac{1}{432}$

8 women and 16 children worked for 9 days

=> Work done in 9 days = $9 \times (8 \times \frac{1}{288}) + (16 \times \frac{1}{432})$

= $9 \times (\frac{1}{36} + \frac{1}{27}) = 9 \times \frac{7}{108}$

= $\frac{7}{12}$

=> Work left = $1 – \frac{7}{12} = \frac{5}{12}$

$\therefore$ Number of days taken by 10 men to complete the remaining work

= $\frac{\frac{10}{240}}{\frac{5}{12}} = \frac{1}{24} \times \frac{12}{5} = \frac{1}{10}$

Thus, 10 men will complete the remaining the work in 10 days.

Let work done by 1 man be $x$ and 1 woman be $y$

Now, 16 men and 12 women complete work in 8 days.

=> $16x + 12y = \frac{1}{8}$ ———Eqn(i)

Also, $20x = \frac{1}{16}$

=> $16x = \frac{1}{20}$

Putting it in eqn(i), we get :

=> $\frac{1}{20} + 12y = \frac{1}{8}$

=> $12y = \frac{1}{8} – \frac{1}{20} = \frac{3}{40}$

=> $y = \frac{3}{40 \times 12} = \frac{1}{160}$

Thus, 16 women can complete the work in = $16 \times \frac{1}{160} = \frac{1}{10}$

$\therefore$ 16 women can complete the work in 10 days.

Let the work done by 8 women in 18 days = $W_2$

=> $\frac{M_1 \times D_1}{W_1} = \frac{M_2 \times D_2}{W_2}$

=> $\frac{12 \times 16}{1} = \frac{8 \times 18}{W_2}$

=> $W_2 = \frac{18}{12 \times 2} = \frac{3}{4}$

Thus, remaining work = $1 – \frac{3}{4} = \frac{1}{4}$

This part of work was done by 12 women.

$\therefore$ Time taken by them = 4 days

=> Required time = 18 + 4 = 22 days

Let efficiency of A = $3x$ units/day

=> Efficiency of B = $\frac{4}{3} \times 3x = 4x$ units/day

Let Work to be done = 8 units

=> Work done by A in 15 days = $15 \times 3x = \frac{5}{8} \times 8$

=> $45x = 5$

=> $x = \frac{5}{45} = \frac{1}{9}$

Thus, B’s 1 day work = $4 \times \frac{1}{9} = \frac{4}{9}$ units

Work done by B in 10 days = $\frac{4}{9} \times 10 = \frac{40}{9}$ units

=> Work left = $8 – \frac{40}{9} = \frac{32}{9}$

$\therefore$ Fraction of work left = $\frac{\frac{32}{9}}{8}$

= $\frac{4}{9}$

Let efficiency of A = $2x$ units/day

=> Efficiency of B = $1.5 \times 2x = 3x$ units/day

Let Work to be done = 7 units

=> Work done by A in 12 days = $12 \times 2x = \frac{6}{7} \times 7$

=> $24x = 6$

=> $x = \frac{6}{24} = \frac{1}{4}$

Thus, B’s 1 day work = $3 \times \frac{1}{4} = \frac{3}{4}$ units

Work done by B in 6 days = $\frac{3}{4} \times 6 = \frac{9}{2}$ units

=> Work left = $7 – \frac{9}{2} = \frac{5}{2}$

$\therefore$ Fraction of work left = $\frac{\frac{5}{2}}{7}$

= $\frac{5}{14}$

Let the total work to be done = 30 units

Rate at which A alone finishes the task = $\frac{30}{10}$ = 3 units/day

Rate at which A & B together finishes the work = $\frac{30}{6}$ = 5 units/day

=> Rate at which B alone finishes the work = 5 – 3 = 2 units/day

$\therefore$ Time taken by B to complete the task = $\frac{30}{2}$ = 15 days

Let the total work to be done = 40 units

Rate at which B alone finishes the task = $\frac{40}{10}$ = 4 units/day

Rate at which A & B together finishes the work = $\frac{40}{8}$ = 5 units/day

=> Rate at which A alone finishes the work = 5 – 4 = 1 units/day

$\therefore$ Time taken by A to complete the task = $\frac{40}{1}$ = 40 days

Using the formula, $M_1 D_1 = M_2 D_2$

=> $36 \times 14 = M_2 \times 8$

=> $M_2 = \frac{36 \times 14}{8} = 63$

$\therefore$ Additional workers = 63 – 36 = 27

A’s 1 day’s work = $\frac{1}{16} – \frac{1}{24}$

= $\frac{3 – 2}{48} = \frac{1}{48}$

Hence, A alone will complete the work in 48 days.

C’s 1 day’s work = $\frac{1}{24}$

=> A’s 1 day’s work = $\frac{3}{4}$ * $\frac{1}{24}$

= $\frac{1}{32}$

=> B’s 1 day’s work = 5 * $\frac{1}{32}$ = $\frac{5}{32}$

$\therefore$ B alone will finish the work in = $\frac{32}{5}$ days

= 6$\frac{2}{5}$ days

Let rate at which A finishes the work = $100x$ units/day

=> Rate at which B finishes the work = $\frac{120}{100} \times 100x = 120x$ units/day

Rate at which C finishes the work = $\frac{140}{100} \times 120x = 168x$ units/day

Work done by A in 42 days = $42 \times 100x = 4200x$ units/day

Rate at which B and C finishes the work = $120x + 168x = 288x$ units/day

$\therefore$ Time taken by B and C together to finish the same work = $\frac{4200x}{288x}$

= $\frac{175}{12} = 14\frac{7}{12}$ days

Length of first train = 240 m and second train = 270 m

Total length of the two trains = 240 + 270 = 510 m

Speed of first train = 60 kmph and second train = 48 kmph

Since, the trains are moving in opposite direction, thus relative speed = 60 + 48 = 108 kmph

= $(108 \times \frac{5}{18})$ m/s = $30$ m/s

Let time taken = $t$ seconds

Using, time = distance/speed

=> $t=\frac{510}{30}=17$ seconds

=> Ans – (A)

Part of tank filled by A and B in 1 hour

= $\frac{1}{5} – \frac{1}{8} = \frac{3}{40}$

=> Time taken to fill the tank completely = $\frac{40}{3}$ hrs

$\therefore$ Time taken to fill two-fifth part of tank

= $\frac{2}{5} \times \frac{40}{3}$

= $\frac{16}{3} = 5\frac{1}{3}$ hrs

It is clear from the question,
16 men do 5/9th of work in 30 days.
Let ‘n’ no. of more men are required to complete the remaining work.
Hence, (n+16) men do 4/9th of work in 8 days.
We know that,
$\frac{Amount of work}{No. of men\times{No. of days}}=Constant$.
Hence,
$\frac{5/9}{16\times30}=\frac{4/9}{(n+16)\times8}$.
$n=32$.
Hence, Option C is correct.