**SSC Questions on Clock:**

Download SSC Questions on Clock PDF based on previous papers very useful for SSC CGL exams. Clock Questions for SSC exams.

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**Question 1: **At what time between 11 O’Clock and 12 O’Clock, will the minute hand and hour hand of the clock coincide with each other?

a) $11:54\dfrac{9}{11}$

b) $11:01\dfrac{6}{11}$

c) $11:56$

d) None of these

**Question 2: **What is the obtuse angle formed by the hands of a clock when the time in the clock is 2:30?

a) $95^\circ$

b) $120^\circ$

c) $105^\circ$

d) $165^\circ$

**Question 3: **A watch loses 5 minutes every hour and was set right at 6 a.m. on a Monday. When will it

show the correct time again?

a) 6 a.m. on next Sunday

b) 3 a.m. on next Monday

c) 3 a.m. on next Sunday

d) 6 a.m. on next Monday

**Question 4: **An alarm was set at 11 AM on Monday on a clock that was set correctly at 1 AM on Sunday, but the clock started gaining 20 seconds every 24 hours. What was the actual time when the alarm went off?

a) 10:31:40 AM

b) 10:51:20 AM

c) 10:30:00 AM

d) 11:30:00 AM

**Question 5: **What is the angle between the two hands of a clock when the time shown by the clock is 8 p.m.?(in degrees)

a) 240

b) 120

c) 60

d) 50

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**Question 6: **How many times in a week does both the hands of the clock will coincide with each other?

a) 84

b) 160

c) 56

d) 154

**Question 7: **If the hour hand of a clock moves by $18^\circ$ then by how many degrees does the minute hand move during the same time?

a) 168

b) 216

c) 276

d) 196

**Question 8: **In a week, how many times are the hands of clock at right angles with each other?

a) 308

b) 44

c) 24

d) 154

**Question 9: **At what time between 4 O’Clock and 5 O’Clock, will the minute hand and hour hand of the clock coincide with each other?

a) $04:21\dfrac{9}{11}$

b) $04:20\dfrac{6}{11}$

c) $04:22$

d) $04:21$

**Question 10: **A clock is found to be slow by 5 minutes at 8 AM on Sunday. It started gaining time and was found to be 5 minutes fast at 8 PM on Monday. When was it correct?

a) 8 AM, Monday

b) 2 AM, Monday

c) 6 AM, Monday

d) 8 PM, Monday

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**Answers & Solutions:**

**1) Answer (D)**

Angle between two hands $= \dfrac{11}{2}M – 30H$ where H is hours and M is Minutes

Here, H = 11 and Angle = $0^\circ$

$0^\circ = \dfrac{11}{2}M – 30\times11$

⇒ $\dfrac{11}{2}M = 330$

⇒ $M = \dfrac{660}{11} = 60$

Hence, the required time = $11:60$ which is $12:00$

Hence, Between 11 O’Clock and 12 O’Clock, the minute hand and hour hand will not coincide with each other.

**2) Answer (C)**

Angle between the hands of a clock is given by the formula $\dfrac{11}{2}H – 30M$ or $30M – \dfrac{11}{2}H$ where H is hours and M is minutes.

Here, Given time = 02 : 30, H = 2 and M = 30.

Angle = $\dfrac{11}{2} \times 30 – 30 \times 2 = 165 – 60 – 105^\circ$

**3) Answer (A)**

For the watch to show the correct time again, it should lose 12 hours.

It loses 5 minutes in 1 hour.

⇒ It loses 1 minute in 12 minutes.

⇒ It will lose 12 hours (or 720 minutes) in 720 × 12 minutes = 8640 minutes = 144 hours = 6 days.

⇒Thus, the clock will show the correct time again at 6am on next Sunday.

So , the answer would be option a) 6 a.m. on next Sunday.

**4) Answer (E)**

Total time between sunday at 1 AM to monday at 11 AM =24hours + 10hours = 34 hours

Now total gain in seconds in 34 hours = $\frac{20}{24}$×34= $\frac{85}{3}$

The actual time at which alarm went off is

=10:59:(60-$\frac{85}{3}$)

=10:59:$\frac{95}{3}$

=10:59:32

**5) Answer (B)**

The total angle in a clock is 360°.

The minute hand covers this 360° in 60 minutes. Thus ,for every minute it covers 6°.

The hour hand covers this 360° in 12 hour. Thus ,for every hour it covers 30°.

So, in 8 hour ,the hour hand will cover $8\times30°=240°.$

So, the difference between hour hand and minute hand at 8 p.m will be = $\left(360°-240°\right)=120°.$

So, option B is correct .

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**6) Answer (D)**

AM : 12:00, 1:05, 2:11, 3:16,4:22, 5:27, 6:33, 7:38, 8:44, 9:49, 10:55.

PM: 12:00, 1:05, 2:11, 3:16, 4:22, 5:27, 6:33, 7:38, 8:44, 9:49, 10:55.

So, both the hands coincide with each other for 22 times in a day.

Now,

For 1 day = 22 times.

For 1 week = 22 * 7

= > 154 times.

**7) Answer (B)**

The hour hand of a clock moves by 30 deg when the minute had moved through 360 deg. Hence if the hour hand moves 18 deg, then the minute hand moves by $\frac{360\times18}{30}$ = 216 deg

**8) Answer (A)**

If you switch to a rotating coordinate system in which the hour hand stands still, then the minute hand makes only 11 revolutions, and so it is at right angles with the hour hand **22 times**. In a 24 hour day you get $2\times 22= 44$

so in weekthere are 7 days

so,

$7\times 44= 308 times$

**9) Answer (A)**

Angle between two hands $= \dfrac{11}{2}M – 30H$ where H is hours and M is Minutes

Here, H = 4 and Angle = $0^\circ$

$0^\circ = \dfrac{11}{2}M – 30\times4$

⇒ $\dfrac{11}{2}M = 120$

⇒ $M = \dfrac{240}{11} = 21\dfrac{9}{11}$

Hence, the required time = $04:21\dfrac{9}{11}$

**10) Answer (B)**

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