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# SSC CGL & CHSL Quant Number System Asked Questions

Download SSC CGL& CHSL Quant Number System askeds questions with answers PDF based on previous papers very useful for SSC CGL exams. 10 Very important Quant Number System questions for SSC exams.

Question 1: What is that least digit that must be added to the product 5786 × 5784 to make it a perfect square?

a) 1

b) 6

c) 5

d) 4

Question 2: Sum of four times a fraction and 7 times its reciprocal is 16. What is the fraction?

a) 2/7

b) 7/2

c) 4/7

d) 7/4

Question 3: Which of the following is NOT prime number?

a) 251

b) 571

c) 331

d) 341

Question 4: If 169 is subtracted from the square of a number, then the result obtained is 7056. What is the number?

a) 75

b) 78

c) 85

d) 87

Question 5: What is the remainder when 2468 is divided by 37?

a) 26

b) 36

c) 18

d) 14

Question 6: What is the average of all numbers between 8 and 74 which are divisible by 7?

a) 40

b) 41

c) 42

d) 43

Question 7: Sum of twice a fraction and its reciprocal is 17/6. What is the fraction?

a) 4/3

b) 5/4

c) 3/4

d) 4/5

Question 8: When a number is increased by 120, it becomes 130% of itself. What is the number?

a) 400

b) 520

c) 460

d) 580

Question 9: The sum of a fraction and 3 times its reciprocal is 19/4. What is the fraction?

a) 3/4

b) 4/3

c) 5/4

d) 4/5

Question 10: What least number must be added to 329, so that the sum is completely divisible by 7?

a) 1

b) 0

c) 2

d) 3

Expression : 5786 × 5784

= $(5785+1)\times(5785-1)$

Let $5785=x$

=> $(x+1)(x-1)=x^2-1$

Clearly to make above term a perfect square, we need to add 1

=> $x^2-1+1=x^2$

=> Ans – (A)

Let that fraction be $\frac{1}{x}$

$4(\frac{1}{x}) + 7x = 16$

$\Rightarrow (4+7x^{2}) = 16 \times x$

$\Rightarrow 7x^{2}-16x+4 = 0$

$\Rightarrow(x-\frac{14}{7})(x-\frac{2}{7})=0$

$\Rightarrow(x-2)(x-\frac{2}{7})=0$

$\Rightarrow x = 2 or 2/7$

$\Rightarrow \text{fraction} = \frac{1}{x} = 1/2 \text(or) 7/2$

so the answer is option B.

Prime factors of 341 = 11 and 31

Hence, among the given numbers, 341 is not prime.

=> Ans – (D)

Let the number be $x$

According to ques,

=> $x^2-169=7056$

=> $x^2=7056+169=7225$

=> $x=\sqrt{7225}=85$

=> Ans – (C)

37*66 = 2442 is the least nearest multiple of 37.

The remainder when 2468 is divided by 37 = 2468 – 2442 = 26

so the answer is option A.

The numbers between 8 and 74 which are divisible by 7 are 14, 21, 28, 35, 42, 49, 56, 63, 70.

sum = 378

average = 378/9 = 42.

SHORTCUT:

average = 7*(average of 2, 3, 4, 5, 6, 7, 8, 9, 10) = 7*(6) = 42.

so the answer is option C.

Let that fraction be $\frac{1}{x}$

$2 \times \frac{1}{x} + x = \frac{17}{6}$

$\Rightarrow (2+x^{2}) = \frac{17}{6} \times x$

$\Rightarrow 6x^{2}-17x+12 = 0$

$\Rightarrow(x-\frac{8}{6})(x-\frac{9}{6})=0$

$\Rightarrow x = 4/3 or 3/2$

$\Rightarrow \text{fraction} = \frac{1}{x} = 3/4 \text(or) 2/3$

so the answer is option C.

$X+120=1.3X$

$0.3X=120$

$X=400$

so the answer is option A.

Let that fraction be $\frac{1}{x}$

$\frac{1}{x} + 3x = \frac{19}{4}$

$\Rightarrow (1+3x^{2}) = \frac{19}{4} \times x$

$\Rightarrow 12x^{2}-19x+4 = 0$

$\Rightarrow(x-\frac{16}{12})(x-\frac{3}{12})=0$

$\Rightarrow(x-\frac{4}{3})(x-\frac{1}{4})=0$

$\Rightarrow x = 4/3 or 1/4$

$\Rightarrow \text{fraction} = \frac{1}{x} = 3/4 \text(or) 4$

so the answer is option A.

$\frac{329}{7}=47$