Simplification Questions For SSC CPO
SSC CPO Simplification Questions and Answers download PDF, based on previous year question paper of SSC CPO exam. 20 Very important Simplification Questions for SSC CPO.
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Free 18000 Solved Questions: SSC Study Material
Question 1: What is the value of $10 – [6 – 4 – (2\div 1 – 2)]$?
a) 10
b) 12
c) 14
d) 8
Question 2: What is the value of $\left[22\frac{3}{4}\div\frac{14}{3}of\left(8-\frac{1}{5}+4-2\div\frac{1}{2}\right)\right]$?
a) $\frac{3}{7}$
b) $\frac{91}{213}$
c) $\frac{5}{8}$
d) $\frac{91}{199}$
Question 3: What is the value of:
$8 \times 3 \div 6 + 7 – 4 \times 2 \div 4 + 8 – 10 = ?$
a) 6
b) 5
c) 7
d) 4
Question 4: The value of:
$4 \div 2 + 3 \times 6 – 7$ is:
a) 13
b) 14
c) 11
d) 12
Question 5: The value of $24 \div 4 \times (3 + 3) \div 2$ is:
a) 22
b) 24
c) 20
d) 18
Question 6: The value of $64 \div 2 \times (9 \div 3) \times 3 \div 9 – 32$ is:
a) 1
b) 0
c) -1
d) 2
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Question 7: Find the value of:
$(11 + 4) – 9 \times 1 \div 3$ of $4$
a) $\frac{75}{4}$
b) $\frac{57}{4}$
c) $5$
d) $3$
Question 8: Find the value of:
$(7 \times 6 + 5 – 15) \div 4 + 6 \div 3 – 4 + 18 \div 3$
a) 12
b) 14
c) 16
d) 18
Question 9: $11^2 + 11^4 \div 11^3 of 11 – 11 $= ?
a) 111
b) 121
c) 131
d) 101
Question 10: $\frac{4}{7} of \frac{8}{9} \div \frac{8}{7} \times 180 of \frac{1}{9} = ?$
a) $\frac{20}{9}$
b) $\frac{9}{20}$
c) $\frac{80}{9}$
d) $\frac{9}{80}$
Question 11: The value of the following expression.
$(47 \times 588) \div (28 \times 120) = ?$
a) 6.284
b) 8.285
c) 7.625
d) 8.225
Question 12: Find the value of the following expression.
$51 \div 3 \times 15 = ?$
a) 140
b) 255
c) 130
d) 100
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Question 13: Simplify: $8+3-\left(\frac{5}{2}\times\frac{1}{3}\right) of \frac{12}{5}+\frac{4}{3}\times\frac{3}{8}$
a) 9.5
b) 10
c) 9
d) 19
Question 14: Simplify: $8.65-[4+0.5\ of\ (8.8-2.3\times3.5)]$
a) 4.725
b) 4.275
c) 3.275
d) 4.527
Question 15: The value of $[9.5 \div (0.6 \times 0.75 + 0.8 \div 16) + 0.75] \div (0.03 \div 0.6 of 0.01)$ lies between:
a) 2 and 3
b) 1 and 2
c) 0 and 1
d) 3 and 4
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Answers & Solutions:
1) Answer (D)
$10 – [6 – 4 – (2\div 1 – 2)] = 10 – [2 – (2 – 2)] = 10 – [2 – 0] = 10-2 = 8$
2) Answer (C)
$\left[22\frac{3}{4}\div\frac{14}{3}of\left(8-\frac{1}{5}+4-2\div\frac{1}{2}\right)\right] = \dfrac{91}{4} \times \dfrac{3}{14} \times \dfrac{5}{39} = \dfrac{5}{8}$
3) Answer (C)
$8 \times 3 \div 6 + 7 – 4 \times 2 \div 4 + 8 – 10 = 8 \times \dfrac{3}{6} + 7 – (4 \times \dfrac{2}{4}) + 8 – 10 = 4+7-2+8-10 = 7$
4) Answer (A)
$4 \div 2 + 3 \times 6 – 7 = 2+18-7 = 13$
5) Answer (D)
$24 \div 4 \times (3 + 3) \div 2 = \dfrac{24}{4} \times \dfrac{6}{2} = 18$
6) Answer (B)
$64 \div 2 \times (9 \div 3) \times 3 \div 9 – 32 = \dfrac{64}{2} \times 3 \times \dfrac{3}{9} – 32 = 32-32 = 0$
7) Answer (B)
$(11 + 4) – 9 \times 1 \div 3$ of $4 = 15-9\times\dfrac{1}{3\times4} = 15-\dfrac{3}{4} = \dfrac{57}{4}$
8) Answer (A)
$(7 \times 6 + 5 – 15) \div 4 + 6 \div 3 – 4 + 18 \div 3 = \dfrac{32}{4} + \dfrac{6}{3} – 4 + \dfrac{18}{3} = 8 + 2 – 4 + 6 = 12$
9) Answer (A)
By simplifying we get 121+1-11
=122-11
=111
10) Answer (C)
By using BODMAS we have
=$(32/63)\div(8/7)\times20$
=$(32/63)\times(7/8)\times20$
=$(4/9)\times20$
=80/9
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11) Answer (D)
By Applying BODMAS we have 47*21/120
=47*7/40
=329/40
=8.225
12) Answer (B)
By simplification we get 17*15=255
13) Answer (A)
=$8+3-\left(\frac{5}{2}\times\frac{1}{3}\right) of \frac{12}{5}+\frac{4}{3}\times\frac{3}{8}$
=$8+3-2+\frac{4}{3}\times\frac{3}{8}$
=$8+3-2+\frac{1}{2}$
=9.5
14) Answer (B)
=$8.65-[4+0.5\ of\ (8.8-2.3\times3.5)]$
=$8.65-[4+0.5\ of\ (8.8-8.05)]$
=$8.65-[4+0.5\ of\ (0.75)]$
=$8.65-[35/8]$
=8.65-4.375
=4.275
15) Answer (D)
=$[9.5 \div (0.6 \times 0.75 + 0.8 \div 16) + 0.75] \div (0.03 \div 0.6 of 0.01)$
=$[9.5 \div (0.6 \times 0.75 + 0.05) + 0.75] \div (5)$
=$[9.5 \div (0.45 + 0.05) + 0.75] \div (5)$
=$[19+0.75] \div (5)$
=(19.75/5)
=3.95