SBI PO Level Number Series Questions

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sbi po level number series questions
sbi po level number series questions

SBI PO Level Number Series Questions

Level Number Series Questions for SBI PO Prelims and Mains exam. Download SBI PO Level Number Series questions on with solutions.

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Question 1: What should come in the place of ? in the following series?
12, 72, 240, 600, ?

a) 1270

b) 1260

c) 1290

d) 1296

e) 1236

Instructions

What should come in the place of ? in the following series?

Question 2: 641, 643, 647, 653, 659, 661, ?

a) 663

b) 667

c) 671

d) 673

e) 669

Question 3: What should come in the place of ? in the following series?
12, 84, 21, 77, 28, 68, 33, ?

a) 55

b) 56

c) 57

d) 58

e) 59

Instructions

What should come in the place of ? in the following series?

Question 4: 51, 52, 106, 321, 1288, ?

a) 6445

b) 6420

c) 6325

d) 6540

e) 6550

Question 5: 19, 27, 46, 73, 119, ?

a) 182

b) 172

c) 187

d) 202

e) 192

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Instructions

What should come in the place of ? in the following series?

Question 6: 254, 128, 130, 198, 400, ?

a) 995

b) 985

c) 1050

d) 1025

e) 1005

Question 7: 2196, 2743, 3374, 4095, ?

a) 4912

b) 4913

c) 4914

d) 4911

e) 4915

Question 8: 34, 53 ,91, 148, 224 ?

a) 296

b) 345

c) 262

d) 379

e) 319

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Question 9: 52, 53, 49, 58, 42, 67, ?

a) 35

b) 36

c) 31

d) 103

e) 42

Question 10: 62, 64, 67, 72, 79, 90, 103, ?

a) 118

b) 122

c) 125

d) 120

e) 117

Instructions

Find the missing number in the following series.

Question 11: 2, 6, 12, 20, ?

a) 30

b) 28

c) 32

d) 24

e) 36

Question 12: 6, 24, 60, 120, ?

a) 180

b) 200

c) 210

d) 256

e) 196

Question 13: 10, 7.5, 5.5, 4, 3, ?

a) 1

b) 2.5

c) 1.5

d) 0.5

e) 2.25

Question 14: 5, 7.5, 15, 37.5, ?

a) 75

b) 127.5

c) 112.5

d) 87.5

e) 62.5

Question 15: 1, 8, 9, 64, 25, ?

a) 216

b) 169

c) 81

d) 156

e) 64

Instructions

Find the missing number in the following series.

Question 16: 7, 14, 42, 168, ?

a) 840

b) 560

c) 720

d) 660

e) 600

Question 17: 5, 25, 61, 113, ?

a) 179

b) 200

c) 181

d) 157

e) 191

Question 18: 5, 4, 2, -1, ?

a) -3

b) -5

c) 5

d) -4.5

e) -6

Question 19: 2, 12, 36, 80, ?

a) 120

b) 150

c) 160

d) 100

e) 144

Question 20: 17, 19, 16, 20, 15, ?

a) 21

b) 14

c) 20

d) 18

e) 19

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Answers & Solutions:

1) Answer (B)

$2^4-2^2 = 16 – 4 = 12$
$3^4-3^2 = 81-9 = 72$
$4^4 – 4^2 = 256-16 = 240$
$5^4-5^2 = 625-25=600$
$6^4 – 6^2 = 1296-36= 1260$
Therefore, option B is the right answer.

2) Answer (D)

The given series consists of prime numbers from 641.
663 is divisible by 3.
665 is divisible by 5.
667 is divisible by 23.
669 is divisible by 3.
671 is divisible by 11.
673 is the next prime number after 661. Therefore, option D is the right answer.

3) Answer (C)

The given series is composed of 2 series.
12 ,21, 28, 33
12 + 9 = 21
21 + 7 = 28
28 + 5 = 33

84,77,68,?

84-7 = 77
77-9 = 68
68 – 11 = 57

Therefore, option C is the right answer.

4) Answer (A)

51*1 + 1 = 52
52*2 + 2 = 104+2 = 106
106*3 + 3 = 318+3 = 321
321*4 + 4 = 1284+4 = 1288
1288*5 + 5 = 6440+5 = 6445

Therefore, option A is the right answer.

5) Answer (E)

19 + 27 = 46
46 + 27 = 73
73 + 46 = 119
119 + 73 = 192

Therefore, option E is the right answer.

6) Answer (E)

254*0.5 + 1 = 127+1=128
128*1 + 2 = 128 + 2 = 130
130*1.5 + 3 = 195+3 = 198
198*2 + 4 = 396+4 = 400
400*2.5 + 5 = 1005

Therefore, option E is the right answer.

7) Answer (A)

$13^3 – 1 = 2197-1 = 2196$
$14^3 – 1 = 2744-1 = 2743$
$15^3 – 1 = 3375-1 = 3374$
$16^3 – 1 = 4096-1 = 4095$
$17^3 – 1 = 4913-1 = 4912$

Therefore, option A is the right answer.

8) Answer (E)

34 + 19 = 53
53 + 38 = 91
91 + 57 = 148
148 + 76 = 224
224 + 95 = 319

Therefore, option E is the right answer.

9) Answer (C)

52 + 1 = 53
53 – 4 = 49
49 + 9 = 58
58 – 16 = 42
42 + 25 = 67
67 – 36 = 31

Therefore, option C is the right answer.

10) Answer (D)

The difference between 2 consecutive terms in the series is a prime number.

62 + 2 = 64
64 + 3 = 67
67 + 5 = 72
72 + 7 = 79
79 + 11 = 90
90 + 13 = 103
103 + 17 = 120

Therefore, option D is the right answer.

11) Answer (A)

First term = $1^2 + 1 = 2$
Second term = $2^2 + 2 = 6$
Third term = $3^2 + 3 = 12$
Fourth term = $4^2 + 4 = 20$
So, fifth term = $5^2 + 5 = 30$
Hence, option A is the correct answer.

12) Answer (C)

First term = $1 * 2 * 3 = 6$
Second term = $2 * 3 * 4 = 24$
Third term = $3 * 4 * 5 = 60$
Fourth term = $4 * 5 * 6 = 120$
So, fifth term = $5 * 6 * 7 = 210$
Hence, option C is the correct answer.

13) Answer (B)

First term = $10$
Second term = $10 – 2.5 = 7.5$
Third term = $7.5 – 2 = 5.5$
Fourth term = $5.5 – 1.5 = 4$
Fifth term = $4 – 1 = 3$
So, sixth term = $3 – 0.5 = 2.5$
Hence, option B is the correct answer.

14) Answer (C)

First term = $5 * 1 = 5$
Second term = $5 * 1.5 = 7.5$
Third term = $7.5 * 2 = 15$
Fourth term = $15 * 2.5 = 37.5$
So, fifth term = $37.5 * 3 = 112.5$
Hence, option C is the correct answer.

15) Answer (A)

First term = $1^2 = 1$
Second term = $2^3 = 8$
Third term = $3^2 = 9$
Fourth term = $4^3 = 64$
Fifth term = $5^2 = 25$
So, sixth term = $6^3 = 216$
Hence, option A is the correct answer.

16) Answer (A)

First term = $7 * 1 = 7$
Second term = $7 * 2 = 14$
Third term = $14 * 3 = 42$
Fourth term = $42 * 4 = 168$
So, fifth term = $168 * 5 = 840$
Hence, option A is the correct answer.

17) Answer (C)

First term = $1^2 + 2^2 = 5$
Second term = $3^2 + 4^2 = 25$
Third term = $5^2 + 6^2 = 61$
Fourth term = $7^2 + 8^2 = 113$
So, fifth term = $9^2 + 10^2 = 181$
Hence, option C is the correct answer.

18) Answer (B)

First term = $3$
Second term = $5 – 1 = 4$
Third term = $4 – 2 = 2$
Fourth term = $2 – 3 = -1$
So, fifth term = $-1 – 4 = -5$
Hence, option B is the correct answer.

19) Answer (B)

First term = $1^2 + 1^3 = 2$
Second term = $2^2 + 2^3 = 12$
Third term = $3^2 + 3^3 = 36$
Fourth term = $4^2 + 4^3 = 80$
So, fifth term = $5^2 + 5^3 = 150$
Hence, option B is the correct answer.

20) Answer (A)

First term = $17$
Second term = $17 + 2 = 19$
Third term = $19 – 3 = 16$
Fourth term = $16 + 4 = 20$
Fifth term = $20 – 5 = 15$
So, sixth term = $15 + 6 = 21$
Hence, option A is the correct answer.

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