Profit and Loss, Discount Questions for SSC-CPO Set-2 PDF

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Question 1: Some fruits are bought at a rate of 11 for ₹100 and an equal number at a rate of 9 for ₹100. If all the fruits are sold at a rate of 10 for ₹100, then what is the gain or loss percent in the entire transaction?

a) Gain, 1%

b) Loss, 5%

c) Gain, 5%

d) Loss, 1%

Question 2: Ramesh purchases 75 articles for ₹ 10800 and sells them at a loss equal to the selling price of 5 articles. What will be the selling price of one article?

a) ₹156

b) ₹135

c) ₹144

d) ₹132

Question 3: After giving a discount of 25%, a shopkeeper earns 40% profit. Marked price is what percent more than the cost price?

a) 80%

b) 75%

c) 86.67%

d) 85%

Question 4: Marked price of an article is 60% more than its cost price. If the article is sold at a profit of 20%, then what will be the discount percentage?

a) 37.5%

b) 17.5%

c) 15%

d) 25%

Question 5: x buys a scooter for ₹ 40,000 and spends ₹ 5,000 on its repair. He sells it for ₹ 54,000. What is the gain percent?

a) 12.50%

b) 20%

c) 25%

d) 15%

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Question 6: An article was bought for ₹ 400 and a repairing charge of ₹ 50 was paid on it. It is sold at a profit of 20%,after a discount of 10% on its marked price. The marked price is:

a) ₹540

b) ₹640

c) ₹580

d) ₹600

Question 7: An article was sold for ₹4,000. Had a discount of 10% was being offered, the profit would have been 20%. The cost price of the article was:

a) ₹3,200

b) ₹3,310

c) ₹3,000

d) ₹3,600

Question 8: A discount of 20% in the price of rice enables X to buy 5 kg more rice for ₹100. What is the reduced price of rice per kg?

a) ₹3

b) ₹2

c) ₹1

d) ₹4

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Question 9: The cost price of 27 articles is same as the selling price of 18 articles. Whatis the profit percent?

a) 40%

b) 50%

c) 30%

d) 25%

Question 10: If 15 apples cost as muchas 6 strawberries, 2 strawberries cost as much as 16 bananas, 6 bananas cost as much as 15 potatoes, then whatis the cost of 1 potato if an apple costs ₹ 20?

a) ₹25

b) ₹22.50

c) ₹2.50

d) ₹2.25

Question 11: If the selling price is tripled, the profit becomes 5 times. What is the profit percent?

a) 100%

b) 200%

c) 50%

d) 150%

Question 12: A cloth piece was purchased for ₹ 700. At what price should it be sold to get a profit of 12.5% after a tailoring charge of ₹ 20 was paid for?

a) ₹760

b) ₹810

c) ₹785

d) ₹840

Question 13: The list price of an article is ₹ 80. A customer pays ₹ 30 for it. He was given 2 successive discounts, one of them being 50%. What was the other discount?

a) 20%

b) 12.50%

c) 30%

d) 25%

Question 14: A trader sold an item at a loss of 20%. Had he sold it for ₹100 more, he would have gained a profit of 5%. What is the cost price of the item?

a) ₹ 250

b) ₹ 200

c) ₹ 25

d) ₹ 400

Question 15: A person bought an item and sold it at a loss of 5%. If he had bought it for 10% less and sold it for ₹ 170 more, he would have had a profit of 20%, Find the cost price of this item. (nearest to  ₹1)

a) ₹1440

b) ₹1308

c) ₹1300

d) ₹1500

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Answers & Solutions:

1) Answer (D)

We know that CP is cost price

SP is selling price

In first condition

CP of 11 toffee=₹10

CP of 1 fruits = ₹ ( $\frac{10}{11}$ )

in second condition

CP of 9  fruits= ₹ 10

CP of fruits = ₹ (  $\frac{10}{9}$ )

therefore, CP of both fruits = ₹ $\frac{10}{11}$+₹ $\frac{10}{9}$

= ₹ $\frac{200}{99}$

so, cp of 1 = $\frac{200}{99}$ ÷2

Cost price = ₹  $\frac{100}{99}$

sp of 1  fruits = ₹ 1(given)

loss=cost price – selling price

= $\frac{100}{99}$ – 1

Loss = ₹  $\frac{1}{99}$

loss percentage = $\frac{loss}{cost price}$×100

loss (%) = $\frac{1÷99}{100÷99}$×100

loss percent=1% loss

=1 percent loss

2) Answer (B)

Given that the Cost Price of 75 articles = Rs.10800
Let the Selling Price of each article = Rs.x
Then, Selling Price of 75 articles = Rs.75x
Selling Price of 5 articles = Rs.5x
=> 10800 – 75x = 5x
=> 80x = 10800
=> x = 135
Therefore, Selling Price of each article = Rs.135

3) Answer (C)

Let the Marked Price be Rs.100x
Discount = 25% of Rs.100x = Rs.25x
Selling Price = Rs.100x – Rs.25x = Rs.75x
Cost Price = $75x\times\dfrac{100}{140} = \dfrac{Rs.375x}{7}$

Required percentage = $\dfrac{100x – \dfrac{375x}{7}}{\dfrac{375x}{7}}\times100 = \dfrac{325}{375}\times100 = 86.67$%

4) Answer (D)

Let the Cost Price be Rs.100x
Then, Marked Price = 160% of 100x = Rs.160x
Given, Profit = 20%
Selling Price = 120% of Rs.100x = Rs.120x
Discount percentage = $\dfrac{160x – 120x}{160x} \times 100 = \dfrac{40x}{160x}\times100 = 25$%

5) Answer (B)

Total Cost Price of the scooter = Rs.40000+Rs.5000 = Rs.45000
Selling Price = Rs.54000
Gain percent = $\dfrac{54000-45000}{45000}\times100 = \dfrac{9000}{45000}\times100 = 20$%

6) Answer (D)

Total Cost Price = Rs.400+Rs.50 = Rs.450
Selling Price = $Rs.450 \times \dfrac{120}{100} = Rs.540$
Discount = 10%
Then, Marked Price = $540 \times \dfrac{100}{90} = Rs.600$

7) Answer (C)

Selling Price of the article = Rs.4000
Let the marked price of the article be Rs.100x
100x = Rs.4000
x = Rs.40
Selling price after 10% discount = 90% of Rs.100x = Rs.90x
Profit = 20%
Then, Cost Price = $90x \times \dfrac{100}{120} = Rs.75x = Rs.75*40 = Rs.300$

8) Answer (D)

X can buy 5 kg more rice for Rs.100
Then, X can buy 1 kg more rice for Rs.20
Then, Reduced price = $Rs.20 \times \dfrac{20}{100} = Rs.4$

9) Answer (B)

27 CP = 18 SP
$\dfrac{SP}{CP} = \dfrac{27}{18} = \dfrac{3}{2}$
Subtracting 1 from both sides
=> $\dfrac{SP}{CP} – 1 = \dfrac{3}{2} – 1$
=> $\dfrac{SP-CP}{CP} = \dfrac{3-2}{2} = \dfrac{1}{2}$
Multiplying 100 on both sides
=> $\dfrac{SP-CP}{CP} \times 100 = \dfrac{1}{2}\times 100 = 50$%

10) Answer (C)

15A = 6S => A : S = 6 : 15
2S = 16B => S : B = 16 : 2
6B = 15P => B : P = 15 : 6
where A = Apples, S = Straw berries, B = Bananas and P = Potatoes
Multiplying A : S by 16 and S : B by 15,
A : S = 96 : 240 and S : B = 240 : 30
Hence, A : S : B = 96 : 240 : 30
Multiplying B : P by 2,
B : P = 30 : 12
Then, A : S : B : P = 96 : 240 : 30 : 12
Let the cost of Apples, Straw berries, Bananas and Potatoes be Rs.96x, Rs,240x, Rs.30x and Rs.12x respectively.
Given, Rs.96x = 20 => x = $\dfrac{20}{96} = \dfrac{5}{24}$
Therefore, Cost of 1 potato =  12x = $12\times \dfrac{5}{24} = Rs.2.5$

11) Answer (A)

Let the Cost Price be Rs.100 and Selling Price be Rs.x
Then, Profit = Rs.(x – 100)
New Selling Price = Rs.3x
Then, New profit = Rs,(3x-100)
Given, 3x-100 = 5(x-100) => 2x = 400 => x = 200
Hence, Selling Price = Rs.200
Profit percentage = $\dfrac{200-100}{100}\times100 = 100$%

12) Answer (B)

Total Effective Cost Price = Rs.700+Rs.20 = Rs.720
Required Profit = 12.5% = $\dfrac{1}{8}$
Therefore, Required Selling Price = $Rs.720 + \dfrac{1}{8} \times 720 = Rs.720+90 = Rs.810$

13) Answer (D)

Given, Marked Price = Rs.80
Selling Price = Rs.30
Discount = Rs.80-Rs.30 = Rs.50
One discount = 50%
50% of 80 = Rs.40
Let the other discount be x%
$40 \times \dfrac{100-x}{100} = 30$
=> 200-2x = 150 => 2x = 50 => x = 25
Therefore, The other discount = 25%

14) Answer (D)

Let the Cost Price be Rs.100x
Loss = 20%
Selling Price = 80% of 100x = Rs.80x
Profit = 5%
Selling Price = 105% of 100x = Rs.105x
Given, Rs.105x – Rs.80x = Rs.100
Rs.25x = Rs.100
=> x = 4
Therefore, Cost Price = Rs.100x = Rs.100*4 = Rs.400

15) Answer (B)

let CP=x
SP=0.95x
New CP=0.9*x
New SP=0.95x+170
profit=20%
0.95x+170=1.2(0.9x)
0.13x=170
x=1307.6
x=Rs 1308

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