Number System Questions for SSC CHSL Set-2 PDF
Download SSC CHSL Number System Questions with answers Set-2 PDF based on previous papers very useful for SSC CHSL Exams. Top-10 Very Important Questions for SSC Exam
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Question 1: A number x when divided by 289 leaves 18 as the remainder. The same number when divided by 17 leaves y as a remainder. The value of y is
a) 2
b) 3
c) 1
d) 5
Question 2: In the following number series a wrong number is given. Find out that number.
8, 18, 40, 86, 178, 370, 752
a) 178
b) 180
c) 128
d) 156
Question 3: Find the unit digit in the product $(4387)^{245} \times (621)^{72}$.
a) 1
b) 2
c) 5
d) 7
Question 4: When a number is increased by 24, it becomes 110% of itself. What is the number?
a) 288
b) 360
c) 216
d) 240
Question 5: Three consecutive natural numbers are such that the square of the greatest is greater than the product of the other two by 16. The smallest of these numbers is
a) 5
b) 6
c) 7
d) 4
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Question 6: How many numbers are there from 300 to 650 which are completely divisible by both 5 and 7?
a) 8
b) 9
c) 10
d) 12
Question 7: The sum of a non-zero number and twenty times its reciprocal is 9. What is the number?
a) -5
b) 3
c) -3
d) 5
Question 8: If 49 is subtracted from the square of a number, then the result obtained is 576. What is the number?
a) 24
b) 25
c) 23
d) 27
Question 9: $\ 3^{11} + 3^{12} + 3^{13} + 3^{14}\ $ is divisible by _____.
a) 7
b) 8
c) 11
d) 14
Question 10: If $A = 1 – 10 + 3 – 12 + 5 – 14 + 7 + …$ upto 60 terms, then what is the value of $A$?
a) -360
b) -310
c) -240
d) -270
Answers & Solutions:
1) Answer (C)
The number is of the form 289n+18.
Which is equal to 17*(17n+1) +1
So, when the number is divided by 17, the reminder is 1
2) Answer (A)
In the series : 8, 18, 40, 86, 178, 370, 752
The pattern followed is that we multiply the first number by 2 and add 2 to it, for the second number, we multiply by 2 and add 4, for the third, multiply by 2 and 6 and so on…
8 x 2 + 2 = 18
18 x 2 + 4 = 40
40 x 2 + 6 = 86
86 x 2 + 8 = 180
180 x 2 + 10 = 370
370 x 2 + 12 = 752
So, the wrong number is 178.
3) Answer (D)
we need to find unit digit of $(4387)^{245} \times (621)^{72}$
unit digit of ${4387^{245}}$ = unit digit of ${7^1}$ = 7
unit digit of ${621^{72}}$ = 1
and hence 7 x 1 = 7 is the unit digit for the given expression
4) Answer (D)
Let the number be $100x$
According to ques, => $100x + 24 = \frac{110}{100} \times 100x$
=> $100x + 24 = 110x$
=> $110x – 100x = 24$
=> $x = \frac{24}{10} = 2.4$
$\therefore$ Number = $100 \times 2.4 = 240$
=> Ans – (D)
5) Answer (D)
Let the three consecutive natural numbers be $(x-1) , (x) , (x+1)$ where $x \geq 2$
Acc. to ques, => $(x + 1)^2 – [x \times (x – 1)] = 16$
=> $(x^2 + 2x + 1) – (x^2 – x) = 16$
=> $3x + 1 = 16$
=> $x = \frac{15}{3} = 5$
$\therefore$ Smallest number = 5 – 1 = 4
6) Answer (C)
the numbers which are divisible by both 5 and 7 means those must be divisible by 5X7=35
35th multiple after 300 = 315 = 31*9
35th multiple before 650 = 630 = 31*18
so total numbers which are divisible by 35 in between 300 & 650 are = 18-9+1 = 10.
so the answer is option C.
7) Answer (D)
$ x + 20(\frac{1}{x}) = 9$
$\Rightarrow (x^{2}+20) = 9 \times x$
$\Rightarrow x^{2}-9x+20 = 0$
$\Rightarrow(x-4)(x-5)=0$
$\Rightarrow x = 4 or 5$
so the answer is option D.
8) Answer (B)
Let the number be $x$
According to ques,
=> $x^2-49=576$
=> $x^2=576+49=625$
=> $x=\sqrt{625}=25$
=> Ans – (B)
9) Answer (B)
Expression : $\ 3^{11} + 3^{12} + 3^{13} + 3^{14}\ $
= $3^{11}(1+3+3^2+3^3)$
= $3^{11}\times(1+3+9+27)$
= $3^{11}\times(40)$
$\because$ $40$ is divisible by 8, hence the above expression is also divisible by 8
=> Ans – (B)
10) Answer (D)
$A=1-10+3-12+5-14+7+\dots..upto\ 60\ terms\ .$
or, $A=\left(1+3+5+7+…59\right)-\left(10+12+14+….+68\right)\ .$
or, $A=\frac{\left(1+59\right)\times30}{2}-\frac{\left(10+68\right)\times30}{2}\ .$
or, $A=900-1170\ =-270\ .$
D is correct choice.
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