Number Series Questions For SSC MTS
Download Top-20 SSC MTS Number Series Questions PDF. Numerical Series questions based on asked questions in previous year exam papers very important for the SSC MTS exam.
Download Number Series Questions For SSC MTS
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Instructions
In the following question, select the missing number from the given series.
Question 1: 4,4,8,12,16,36,32,?
a) 96
b) 108
c) 114
d) 128
Question 2: 2,6,12,20,30,?
a) 40
b) 36
c) 28
d) 42
Question 3: -1,3,15,35,63,?
a) 87
b) 99
c) 92
d) 77
Question 4: 3,6,24,192,3072,?
a) 99212
b) 98208
c) 98304
d) 96484
Question 5: 0,1,5,14,30,55,?
a) 84
b) 91
c) 104
d) 74
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Question 6: 0,3,8,15,24,?
a) 26
b) 48
c) 35
d) 29
Question 7: 0,7,26,63,124,?
a) 342
b) 215
c) 224
d) 142
Question 8: 3,4,12,39,103,?
a) 244
b) 256
c) 228
d) 262
Question 9: 4,4,6,12,30,?
a) 65.8
b) 75
c) 66.67
d) 90
Question 10: 2,2,4,16,128,?
a) 2048
b) 2196
c) 1248
d) 1684
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Question 11: 11,39,525,749,981,?
a) 1024
b) 729
c) 8476
d) 11121
Question 12: A series is given, with one number missing. Choose the correct alternative from the given ones that will complete the series.
3888, -1296, 432, ? , 48, -16
a) 72
b) 144
c) 48
d) 75
Question 13: A series is given, with one number missing. Choose the correct alternative from the given ones that will complete the series.
1440, -720, 360, ? , 90, -45
a) 72
b) 180
c) 48
d) 75
Question 14: A series is given, with one number missing. Choose the correct alternative from the given ones that will complete the series.
480, -240, 120, ? , 30, -15
a) -72
b) -60
c) -48
d) -75
Instructions
A series is given, with one term missing. Choose the correct alternative from the given ones that will complete the series.
Question 15: 91,97,107,121,?
a) 137
b) 139
c) 135
d) 133
Question 16: 21,23,31,63,?
a) 127
b) 191
c) 95
d) 193
Question 17: 3,7,12,18,?
a) 25
b) 24
c) 26
d) 27
Question 18: 12,12,6,2,?
a) 1
b) 0.5
c) 0.25
d) 0.66
Question 19: 2,10,30,68,?
a) 120
b) 130
c) 110
d) 140
Question 20: -1,0,7,26,?
a) 57
b) 60
c) 63
d) 66
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Answers & Solutions:
1) Answer (B)
Given series is a double series.
4,8,16,32,…. and 4,12,36,….
In the first series,
4*2 = 8
8*2 = 16
16*2 = 32
In the second series,
4*3 = 12
12*3 = 36
Similarly next number should be
36*3 = 108.
2) Answer (D)
1*2 = 2
2*3 = 6
3*4 = 12
4*5 = 20
5*6 = 30
Similarly next number should be
6*7 = 42
3) Answer (B)
$0^2 -1 = 0-1 = -1$
$2^2 -1 = 4-1 = 3$
$4^2 – 1 = 16-1 = 15$
$8^2-1 = 64-1 = 63$
Similarly Next number should be
$10^2-1 = 100-1 = 99$
4) Answer (C)
3*2 = 6
6*4 = 24
24*8 = 192
192*16 = 3072
Similarly Next number should be
3072*32 = 98304
5) Answer (B)
$0+1^2 = 0+1 = 1$
$1+2^2 = 1+4 = 5$
$5+3^2 = 5+9 = 14$
$14+4^2 = 14+16 = 30$
$30+5^2 = 30+25 = 55$
Similarly Next number should be
$55+6^2 = 55+36 = 91$
6) Answer (C)
$1^2-1 = 1-1 = 0$
$2^2-1 = 4-1 = 3$
$3^2-1 = 9-1 =8$
$4^2-1 =16-1 = 15$
$5^2-1 = 25-1 = 24$
Similarly Next number should be
$6^2-1 = 36-1 = 35$
7) Answer (B)
$1^3-1 = 1-1 = 0$
$2^3-1 = 8-1 = 7$
$3^3-1 = 27-1 = 26$
$4^3-1 = 64-1 = 63$
$5^3-1 = 125-1 = 124$
Similarly, Next number should be
$6^3-1 = 216-1 = 215$
8) Answer (C)
$3+1^3 = 3+1 = 4$
$4+2^3 = 4+8 = 12$
$12+3^3 = 12+27 = 39$
$39+4^3 = 39+64 = 103$
Similarly, Next number should be
$103+5^3 = 103+125 = 228$
9) Answer (D)
4*1 = 4
4*1.5 = 6
6*2 = 12
12*2.5 = 30
Hence, Next number should be
30*3 = 90.
10) Answer (A)
2*1 = 2
2*2 = 4
4*4 = 16
16*8 = 128
Hence, Next number should be
128*16 = 2048
11) Answer (D)
The given series is in the form of $[x][x^2]$
$11 → [1][1^2]$
1+2 = 3
$39 → [3][3^2]$
3+2 = 5
$525 → [5][5^2]$
Similarly, Next number should be
9+2 = 11
$[11][11^2] = [11][121] = 11121$
12) Answer (B)
The pattern is that each number is divided by -2
$3888\div-3 = -1296$
$-1296\div-3 = 432$
$432\div−3 = -144$
$-144\div−3 = 48$
$48\div-3 = -16$
=> Ans – (B)
13) Answer (B)
The pattern is that each number is divided by -2
$1440\div-2 = -720$
$-720\div-2 = 360$
$360\div−2 = -180$
$-180\div−2 = 90$
$90\div-2 = -45$
=> Ans – (B)
14) Answer (B)
The pattern is that each number is divided by -2
$480\div-2 = -240$
$-240\div-2 = 120$
$120\div−2 = -60$
$-60\div−2 = 30$
$30\div-2 = -15$
=> ans B
15) Answer (B)
In this series next term is obtained by adding 6,10,14,18…respectively i.e
91+6=97
97+10=107
107+14=121
121+18=139
16) Answer (B)
In this series next term is obtained by adding odd powers of 2 to the previous term i.e 21+2=23
23+8=31
31+32=63
63+128=191
17) Answer (A)
In this series next term is obtained by adding natural number starting from 4 i.e
3+4=7
7+5=12
12+6=18
18+7=25
18) Answer (B)
In this series next term is obtained by dividing with natural numbers starting from 1 i.e 12/1=12
12/2=6
6/3=2
2/4=0.5
19) Answer (B)
In this series each term is n^{3}+n starting from n=1 i.e for n=1 we have 2
For n=2 we have 10
For n=3 we have 30
For n=4 we have 68
For n=5 we have 130
20) Answer (C)
In this each term follows the trend of $n^{3}-1$ starting from n=0 i.e
0-1=-1
1-1=0
8-1=7
27-1=26
64-1=63
