# Number Series questions for SSC CHSL

0
6079

## Number Series questions and answers for SSC CHSL:

You can practice SSC CHSL English question papers

Instructions: In each of the following questions. a series is given, with one term missing. Choose the correct alternative from the given ones that will complete the series.

Question 1: 325, 259. 204, 160, 127, 105, ?

a) 94
b) 96
c) 98
d) 100

Question 2: AZBY, CXDW, EVFU, ?

a) SHTG
b) GXHW
c) GTHS
d) STHO

Question 3: 3, 5, 9, 17, ?

a) 42
b) 26
c) 65
d) 33

Question 4: 4, 6, 10, 16, 24, ?

a) 40
b) 28
c) 30
d) 34

Question 5: 0, 7, 26, 63, ?

a) 123
b) 87
c) 96
d) 124

Question 6: 0, ? , 8 27, 64, 125

a) 5
b) 4
c) 2
d) 1

Question 7: 1, 5, 25, 125, ? , ? , ?

a) 245, 485, 965
b) 225, 325, 425
c) 625.3225, 15605
d) 625, 3125, 15625

Question 8: 2, 2, 4, 6, ?, 10, 8, 14, 10

a) 6
b) 5
c) 8
d) 7

Question 9: 3, 11, 38, 102, 227,?

a) 245
b) 487
c) 474
d) 443

Question 10: 3,15, 8, 24, 15, 35, ? , 48, 35

a) 24
b) 46
c) 26
d) 25

Solutions for Number Series for SSC CHSL:

Solutions:

here the given pattern is 325, 259. 204, 160, 127, 105, ?
and so let the missing number be y
here we can see that
259 – 325 = -66
204 – 259 = -55
160 – 204 = -44
127 – 160 = -33
105 – 127 = -22
here we can see that every time the difference is reducing by -11
so , y – 105 = -11
y = 94

AZBY:
A is the first letter in the alphabetical series. It is followed by the first letter from the last, Z.
B is the second letter in the alphabetical series. It is followed by the second last letter, Y.
The next term starts with ‘C’, the letter following B.
CXDW:
C is the third letter from the start and X is the third letter from the end.
D is the fourth letter from the start and W is the fourth letter from the end.
The next term starts with ‘E’, the letter following D.
EVFU:
E is the fifth letter from the start and V is the fifth letter from the end.
F is the sixth letter from the start and U is the sixth letter from the end.
G is the seventh letter from the start. The seventh letter from the end is T.
H is the eighth letter from the start. The eighth letter from the end is S.
Therefore, the next term must be GTHS. Hence, option C is the right answer.

here the given pattern is 3, 5, 9, 17, ?
let the missing term be y
we can see that
5 – 3 = 2^1
9 -5 = 4 = 2^2
17 – 9 = 8 = 2^3
as we can see that every time the difference between consecutive terms is getting increased by power of 2 and hence , y – 17 = 2^4 = 16
y = 33

here the given pattern is 4, 6, 10, 16, 24, ?
let the missing term be y
6 – 4 = 2
10 – 6 = 4
16 – 10 = 6
24 – 16 = 8
as we can see that every time the difference is getting increased by 2 so
y – 24 = 10
y = 34

let the missing term be y
here the given series is 0, 7, 26, 63, y
as we can see that :
0 = 0^2 -1
7 = 2^3 – 1
26 = 3^3 – 1
63 = 4^3 – 1
as we can see that all number are equal to cub of consecutive whole numbers minus 1 and hence , y = 5^3 – 1= 124

here the given pattern is 0, ? , 8 27, 64, 125
let the missing term be y
as we can see that every patern is a cube of consecutive whole number starting from 0
0 = 0^3
8 = 2^3
64 = 4^3
125 = 5^3
so the missing term is , y = 1 ^ 3 = 1

we have been give a series as 1, 5, 25, 125, ? , ? , ?
here we can see that every term is a power of 5
1 = 5 ^ 0
5 = 5 ^ 1
25 = 5 ^ 2
125 = 5 ^ 3
so the next term will also be power of 5 and the terms are 5 ^ 4, 5 ^ 5 , 5^6 i,e 625, 3125, 15625

here the given pattern is 2, 2, 4, 6, ?, 10, 8, 14, 10
let the missing term be y
here 2 series are present
1st series : 2, 4, y, 8, 10
2nd series: 2, 6, 10, 14
as we can see that the missing term is a part of 1st series
and in 1st series difference between consecutive terms is 2
so 4-2 = y-4
y = 6

here the given series is 3, 11, 38, 102, 227,?
let the missing term be y
we can see that
11 – 3 = 8 = 2^3
38 – 11 = 27 = 3^3
102 – 38 = 64 = 4^3
227 – 102 = 125 = 5^3
hence y – 227 = 6^3 = 216
y = 216 + 227 = 443