Most Expected Number Series Questions for IBPS RRB Clerk PDF

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Instructions

Find the wrong number in given series sequence.

Question 1: 1, 4, 15, 64, 325, 1955

a) 15

b) 64

c) 325

d) 1955

e) None of these

Question 2: 6, 12, 21, 33, 49, 66

a) 21

b) 33

c) 49

d) 66

e) None of these

Question 3: 6, 11.5, 19, 28.5, 41

a) 6

b) 11.5

c) 41

d) 28.5

e) None of these

Question 4: 5, 26, 82, 214, 401, 702

a) 26

b) 82

c) 214

d) 401

e) None of these

Question 5: 5,20,73,274,1049

a) 20

b) 73

c) 274

d) 1049

e) None of these

Question 6: Which number comes in the place of the question mark (?)16, 25, 36, 49, 64, ?

a) 121

b) 100

c) 81

d) 144

e) 196

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Question 7: Which number comes in the place of the question mark (?)1, 27, 125, 343, ?

a) 512

b) 1000

c) 729

d) 216

e) 1024

Question 8: Which number comes in the place of the question mark (?)11, 44, 99, 176, ?

a) 274

b) 266

c) 275

d) 265

e) 300

Question 9: Which number comes in the place of the question mark (?)5, 25, 61, 113, ?

a) 144

b) 181

c) 165

d) 200

e) 245

Question 10: Which number comes in the place of the question mark (?)2, 6, 12, 20, 30, ?

a) 50

b) 44

c) 45

d) 42

e) 55

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Instructions

What should come in place of the question mark (?) in the following number series ?

Question 11: 353 354 351 356 349 ?

a) 348

b) 358

c) 338

d) 385

e) 340

Question 12: 1 5 13 29 ? 125 253

a) 83

b) 69

c) 61

d) 65

e) 81

Question 13: 45 57 81 117 165 ?

a) 235

b) 215

c) 205

d) 245

e) 225

Question 14: 17 18 26 53 117 ? 458

a) 342

b) 142

c) 257

d) 262

e) 242

Question 15: $\frac{1}{4}, \frac{1}{2}, \frac{3}{4}, 1, 1\frac{1}{4}, 1\frac{1}{2}, 1 \frac{3}{4}, ?$

a) $2$

b) $4$

c) $6$

d) $1\frac{1}{5}$

e) $1\frac{2}{3}$

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Answers & Solutions:

1) Answer (D)

4 = 1*2+2 ; 15 = 4*3+3 ; 64 = 15*4+4 ; 325 = 64*5+5 ; 1956 = 325*6+6

The nth term is of the form,

$T_n=(T_{n-1}\times n)+n$

The last term does not follow the pattern and is thus the wrong number in the sequence.

2) Answer (C)

6+6 = 12
12+9 = 21
21+12 = 33
33+15 = 48
48+18 = 66.
Hence, 49 is wrong number and it should be 48.

3) Answer (C)

1.5*2 + 3 = 6

2.5*3 + 4 = 11.5

3.5*4 + 5 = 19

4.5*5 + 6 = 28.5

5.5*6 + 7 = 40

4) Answer (C)

1*2+3=5 ; 4*5+6 = 26 ; 8*9+10 = 82 ; 13*14+15 = 212 ; 19*20 + 21 =401 ; 26*27 +28 = 702
All the numbers except 214 are following a pattern of $n\times (n+1) + (n+2)$. Hence, 214 is wrong number.

5) Answer (C)

1^2 + 4= 5 ; 2^2 + 16 = 20 ; 3^2 + 64 = 73 ; 4^2 + 256 = 272 ; 5^2 + 1024 = 1049

6) Answer (C)

$4^2 = 16$ ; $5^2=25$ ; $6^2 = 36$ ; $7^2=49$ ; $8^2 = 64$ ; $9^2 = 81$

7) Answer (C)

$1^3 = 1$ ; $3^3 = 27$ ; $5^3 = 125$ ; $7^3=343$ ; $9^3 = 729$

8) Answer (C)

$1 \times11 = 11$ ; $2 \times 22=44$ ; $3 \times 33=99$ ; $4 \times 44=176$ ; $5 \times 55=275$

9) Answer (B)

$1^2 + 2^2 = 5 $; $3^2 + 4^2 = 25$ ; $5^2 +6^2 = 61$ , $7^2 + 8^2 = 113$ ; $9^2 + 10^2 = 181$

10) Answer (D)

2+4=6 ; 6+6 = 12 ; 12+8 = 20 ; 20+10=30 ; 30+12 = 42

11) Answer (B)

There are two arithmetic progression series,

With 353,351,349… having a difference of -2

and 354, 356… having a difference of 2

Hence, the required term is 358

12) Answer (C)

The generalized formula for nth term is, previous term + 2^n

Here the required term is 5th in the series.

Hence, 29 + 2^5 = 61

13) Answer (E)

For the series the nth term is ‘last term + 12*(n-1)’

In the series, we are required to find, 6th term.

Hence, 6th term is 165+12*(5) = 225.

14) Answer (E)

Here, each sucessive nth term is ‘previous term + (n-1)³’

We are supposed to find 6th term.

Hence, 6th term = 117 + (6-1)^3 = 117 + 125 = 242

15) Answer (A)

The given series is Arithmetic Progression with common difference $\frac{1}{4}$.

Hence, the next term will be $1\frac{3}{4}$ + $\frac{1}{4}$ = 2

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