**Missing number questions for IBPS Clerk PDF**

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**Instructions**

What should come in place of the question mark (?) in the following number series ?

**Question 1: **353 354 351 356 349 ?

a) 348

b) 358

c) 338

d) 385

e) 340

**Question 2: **1 5 13 29 ? 125 253

a) 83

b) 69

c) 61

d) 65

e) 81

**Question 3: **45 57 81 117 165 ?

a) 235

b) 215

c) 205

d) 245

e) 225

**Question 4: **17 18 26 53 117 ? 458

a) 342

b) 142

c) 257

d) 262

e) 242

**Question 5: **$\frac{1}{4}, \frac{1}{2}, \frac{3}{4}, 1, 1\frac{1}{4}, 1\frac{1}{2}, 1 \frac{3}{4}, ?$

a) $2$

b) $4$

c) $6$

d) $1\frac{1}{5}$

e) $1\frac{2}{3}$

**Instructions**

What should come in place of question mark (?) in the following numbers series

**Question 6: **12, 6.5, 7.5, 12.75, 27.5, 71.25, ?

a) 225.5

b) 216.75

c) 275

d) 236.75

e) 249.75

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**Question 7: **16, 24, 36, 54, 81, 121.5 ?

a) 182.25

b) 174.85

c) 190.65

d) 166.55

e) 158.95

**Question 8: **12, 12, 18, 45, 180, 1170, ?

a) 13485

b) 14675

c) 15890

d) 16756

e) 12285

**Question 9: **22, 23, 27, 36, 52, 77, ?

a) 111

b) 109

c) 113

d) 117

e) 115

**Question 10: **16, 14, 24, 66, 256, 1270, ?

a) 8564

b) 5672

c) 4561

d) 7608

e) 6340

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**Instructions**

In each of these question a number series is given.In each series only one number is wrong.Find out the wrong numbers

**Question 11: **3601, 3602, 1803, 604, 154, 36, 12

a) 3602

b) 1803

c) 604

d) 154

e) 36

**Question 12: **4, 12, 42, 196, 1005, 6066, 42511

a) 12

b) 42

c) 1005

d) 196

e) 6066

**Question 13: **2, 8, 12, 20, 30, 42, 56

a) 8

b) 42

c) 30

d) 20

e) 12

**Question 14: **32, 16, 24, 65, 210, 945, 5197.5

a) 945

b) 16

c) 24

d) 210

e) 65

**Question 15: **7, 13, 25, 49, 97, 194, 385

a) 13

b) 49

c) 97

d) 194

e) 25

**Answers & Solutions:**

**1) Answer (B)**

There are two arithmetic progression series,

With 353,351,349… having a difference of -2

and 354, 356… having a difference of 2

Hence, the required term is 358

**2) Answer (C)**

The generalized formula for nth term is, previous term + 2^n

Here the required term is 5th in the series.

Hence, 29 + 2^5 = 61

**3) Answer (E)**

For the series the nth term is ‘last term + 12*(n-1)’

In the series, we are required to find, 6th term.

Hence, 6th term is 165+12*(5) = 225.

**4) Answer (E)**

Here, each sucessive nth term is ‘previous term + (n-1)³’

We are supposed to find 6th term.

Hence, 6th term = 117 + (6-1)^3 = 117 + 125 = 242

**5) Answer (A)**

The given series is Arithmetic Progression with common difference $\frac{1}{4}$.

Hence, the next term will be $1\frac{3}{4}$ + $\frac{1}{4}$ = 2

**6) Answer (B)**

The given series is based on the following sequence,

(12+1)*0.5 = 6.5

(6.5+1)*1 = 7.5

(7.5+1)*1.5=12.75

(12.75+1)*2 = 27.5

(27.5+1)*2.5 = 71.25

(71.25+1)*3 = 216.75

**7) Answer (A)**

Each number in the series is 1.5 times the preceding number.

Hence, 16*1.5 = 24

24*1.5 = 36

36*1.5 = 54

54*1.5=81

81*1.5 = 121.5

So, the next number is 121.5*1.5 = 182.25

**8) Answer (E)**

The ratio between preceding terms of the sequence are in a fibonacci sequence.

For example, 12/12 = 1

18/12 = 1.5

45/18 = 2.5 (which is 1+1.5)

180/45 = 4 (which is 1.5+2.5)

1170/180 = 6.5 (which is 2.5+4)

Hence, the next ratio would be 4+6.5=10.5

And the required number is 1170*10.5 = 12285

**9) Answer (C)**

The difference between consecutive terms of the series is a perfect square.

For example,

23-22 = 1

27-23 = 4

36-27 = 9

52-36 = 16

77-52 = 25

Hence, the next difference between the numbers will be 36 and the required number is 77+36 = 113

**10) Answer (D)**

The given terms are in the following series,

14 = 16*1 – 2*1

24 = 14*2 – 2*2

66 = 24*3 – 2*3

256 = 66*4 – 2*4

1270 = 66*5 – 2*5

Hence, the next term equals 1270*6 – 2*6 = 7608

**11) Answer (D)**

In the given series, nth term is obtained by – (Previous term/(n-1) ) +(n-1).

Hence the 5th term should be (604/4)+4 = 155.

However 5th term is given as 154.

Hence, 154 is wrong term in the given series.

**12) Answer (B)**

In this question, the nth term is obtained by (previous term*n + n^2).

Hence, after 12, the number would be (12*3+9)= 45

Therefore, the correct option is 45.

**13) Answer (A)**

Here the consecutive difference between the terms is incremented by 2 for the series.

Hence, after 2, the number should be 6.

**14) Answer (E)**

Here the sucessive numbers are multiplied by .5,1.5.2.5….

Hence, in place of 65 the number should be 24*2.5=60.

Therefore, the incorrect number for series is 65.

**15) Answer (D)**

Here, in this series, the nth term is (previous term + 6*2^{n-2 })

Hence, in place of 194 the term should be (97+6*2^{4}) = 193

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