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# Expected Quant Questions For SBI PO 2019 Set-2

Download SBI PO Expected Quant Questions & Answers PDF for SBI PO Prelims and Mains exam. Very Important SBI PO Expected Quant questions with solutions.

Question 1: In 8 years, Ramesh will be twice as old as Farheen was 8 years ago. If Ramesh is now 16 years older than Farheen, the present age of Farheen is :

a) 32

b) 40

c) 36

d) 44

e) 24

Question 2: Find the approximate value of $\Large\frac{169.87^{2}-13.94^{2}}{183.87}$ $\large+$ $\Large\frac{3211.96}{44.002}$

a) 224

b) 236

c) 239

d) 229

e) None of these

Question 3: The average marks of a class increased by $\large\frac{1}{3}$ when a student’s marks were wrongly entered as 64 instead of 46. The number of students in the class are

a) 54

b) 58

c) 63

d) 57

e) None of these

Instructions

Select the correct option.

Question 4: Quantity 1:A number is increased by 85% and then it is decreased by 15% and result is approximately 357
Quantity 2:A number is increased by 82% and then it is decreased by 12% and the result is approximately 355.5

a) Quantity 1 $\leq$Quantity 2

b) Quantity 1 $\geq$Quantity 2

c) Quantity 1 < Quantity 2

d) Quantity 1 > Quantity 2

e) Quantity 1 = Quantity 2

Instructions

The following table shows the breakup of the marks scored by students of Class X of Sharda Mandir in Maths for 5 years from 2001-2005.

Note: A student can score a maximum of 100 marks.

Question 5: The students scoring below 40 are said to have failed the exam whereas the students scoring in between are 60-90 said to have passed the exam with distinction.
What is the ratio of the number of students that failed and the number of students that got distinction during the given period?

a) 420:313

b) 417:305

c) 323:251

d) 4:3

e) 5:4

Instructions

Each of the question given below is followed by three statements. You have to study the questions and all the three statements given to decide whether any information provided in the statement/s is/are redundant and can be dispensed with while answering the given questions.

Question 6: What is the maximum marks that can be obtained in the examination?

I: Ravi secured 35% of the maximum marks and failed by 7 marks.
II: The difference between marks scored by Ravi and Soham is 12 marks.

III: Soham secured 82 marks which was 5 marks more than the passing marks.

a) Only I

b) Both II and III

c) Both I and II

d) Only II

e) None of these

Instructions

Calculate the quantity I and the quantity II on the basis of the given information then compare them and answer the following questions accordingly.

Question 7: Quantity 1: Volume of a sphere of 20 cm radius.
Quantity 2: Volume of a right circular cone whose height is 60cm and radius of the circular base is 25 cm.

a) Quantity 1 > Quantity 2

b) Quantity 1 $\geq$ Quantity 2

c) Quantity 1 < Quantity 2

d) Quantity 1 $\leq$ Quantity 2

e) Quantity 1 = Quantity 2

Question 8: A shopkeeper wants to buy a rod of certain length such that he can measure 140 cm, 420 cm and 280 cm precisely. What is the maximum possible length of the rod that the shopkeeper can buy?

a) 70 cm

b) 140 cm

c) 35 cm

d) 7 cm

e) 20 cm

Instructions

Calculate the quantity I and the quantity II on the basis of the given information then compare them and answer the following questions accordingly.

Question 9: Quantity 1: Simple interest charged by a bank on a sum of Rs. 1000 at the rate of 22% annum for 2 years.
Quantity 2: Compound interest charged by another bank on a sum of Rs. 1000 at the rate of 20% annum for 2 years compounded annually.

a) Quantity 1 > Quantity 2

b) Quantity 1 $\geq$ Quantity 2

c) Quantity 1 < Quantity 2

d) Quantity 1 $\leq$ Quantity 2

e) Quantity 1 = Quantity 2

Question 10: Three friends, A, B and C invested Rs. 10000 each to start a company. A withdrew his whole invested amount after 4 months. B withdrew half of the invested amount after 6 months. If C got Rs. 1200 as his share of profit after one year, what was A’s share in the profit?

a) Rs. 600

b) Rs. 400

c) Rs. 1000

d) Rs. 500

e) Rs. 800

Question 11: 5 bottles of apple juice and 9 bottles of mango juice together fill 71 glasses. Also, 7 bottles of apple juice and 11 bottles of mango juice together fill 93 glasses. How many glasses can be filled with 3 bottles of apple juice and 4 bottles of mango juice if each bottle of either of the juices fills an integer number of glasses?

a) 37

b) 41

c) 34

d) 45

e) 32

Question 12: A, B and C can do a piece of work in 20, 25 and 40 days. They started the work together but B left 4 days before completion. In how many days the work is completed?

a) 13$\large\frac{4}{23}$ days

b) 10$\large\frac{2}{23}$ days

c) 12$\large\frac{3}{17}$ days

d) 14$\large\frac{5}{17}$ days

e) None of these

Instructions

One of the numbers in the given series is incorrect. Find the incorrect number in the series

Question 13: 7, 33, 137, 553, 2217, 8871

a) 33

b) 137

c) 553

d) 8871

e) 2217

Question 14: Ravi rolled a dice twice. What is the probability that sum of both the outcome is less than 5?

a) 1/6

b) 1/4

c) 1/3

d) 1/2

e) None of the above.

Question 15: To meet the demand during summer, a milkman mixed water with pure milk in 2:5. Then he sold the same mixture at 20% more than normal price. By what percent his revenue will increase during summers? (Water is available without any cost)

a) 60 percent

b) 50 percent

c) 40 percent

d) 68 percent

e) 63 percent

Instructions

In the following questions 2 quantities X and Y are given. Select the option which best captures the relations between X and Y.

Question 16: 3 dices are thrown.
X is the probability that sum of the number on the faces of the dice is 7.
Y is the probability that sum of the number on the faces of the dice is 14.

a) X>Y

b) X<Y

c) X$\geq$Y

d) X$\leq$Y

e) X=Y or Cannot be determined

Question 17: Ram purchased three variety of barley at Rs. 100 per kg, Rs. 140 per kg and Rs. 180 per kg respectively. In what ratio he should mix these three varieties in that order so that the average cost of the mixture is Rs. 150 per kg?

a) 2 : 4 : 7

b) 1 : 5 : 10

c) 1 : 2 : 3

d) 2 : 5 : 5

e) None of the above

Question 18: Ram takes 30 minutes to reach office from home by car. One day, due to heavy traffic he drove his car at (4/5)th of original speed for (1/3)rd of total distance and remaining distance at (2/5)th of the original speed. Find out the time taken by Ram on that day?

a) 60 minutes

b) 75 minutes

c) 65 minutes

d) 67.5 minutes

e) 62.5 minutes

Instructions

In each of the following questions a question is asked followed by three statements.You have to study the questions and all the given three statements and all the statements and decide whether any information provided in the statement are redundant and can be dispensed with while answering the questions ?

Question 19: What will be the cost of the painting the four walls of a room with length ,width and height is 5,3,8 meters respectively. The room has one window and one door.
I.Cost of painting per square meter is Rs 25
II.Area of window is 2.25 sq m which is half of the area of the door
III.Area of the room is 15 sq meter

a) I only

b) II only

c) III only

d) II or III only

e) All are required to answer the question

Instructions

There are 450 students in a college. Each student has to choose one or more elective out of management, history and physics. Further following information is also known –
1) 75 students selected only management and physics.
2) 84 students selected only management and history.
3) 52 students selected only physics and history.
4) The number of students who selected only history is 137 less the number of students who selected only management.
5) In total 238 students selected management as an elective.
6) In total 240 students selected history as an elective.

Question 20: How many students selected both management and physics as elective?

a) 84

b) 107

c) 75

d) 89

e) 98

Let us assume the present age of Farheen = x years
So present age of Ramesh will be = x + 16 years

Ramesh’s age after 8 years will be = x+16+8 = x+24 years
Farheen’s age 8 years ago = x – 8 years

$\Rightarrow$ x+24 = 2*(x-8)
$\Rightarrow$ x= 40 years

So the present age of Farheen will be 40 years.

$\Large\frac{169.87^{2}-13.94^{2}}{183.87}$ $\large+$ $\Large\frac{3211.96}{44.002}\simeq \frac{170^{2}-14^{2}}{184}$ $\large+$ $\Large\frac{3212}{44}$

$= \Large\frac{(170+14)(170-14)}{184}$ $+$ $73$

$= \Large\frac{184\times156}{184}$ $+$ $73$

$= 156+73 = 229$

Let the number of students be ‘x’

Given that the average is increased by $\Large\frac{1}{3}$ due to the increase of $18$ marks ( $64$ $-$ $46$ $=$ $18$ marks )

Actual increase in marks $=$ $\Large\frac{1}{3}$ $\times$ x

$\Rightarrow$ $\Large\frac{1}{3}$ $\times$ x $=$ $18$

$\therefore$ Number of students(x) $=$ $54$

In Q1 we have x*1.85*0.85=357
x=357/(1.85*0.85)
x=227
In Q2 we have x*1.82*0.88=355.5
x=355.5/(1.82*0.88)
x=220
Therefore Q1>Q2

Number of students scoring in between 0-20 = Total students appeared – Number of students scoring above 20
Number of students scoring in between 20-40 = Number of students scoring above 20 – Number of students scoring above 40
Number of students scoring in between 40-60 = Number of students scoring above 40 – Number of students scoring above 60
Number of students scoring in between 60-80 = Number of students scoring above 60 – Number of students scoring above 80
Number of students scoring in between 80-90 = Number of students scoring above 80 – Number of students scoring above 90
Number of students scoring in between 90-100 = Number of students scoring above 90

Thus, the required ratio = 2085:1525 = 417:305
Hence, option B is the correct answer.

let the maximum marks be ‘x’.

Ravi = 0.35x

passing marks = 0.35x + 7

Passing marks is also equal to 82 – 5 = 77 marks

Thus, 0.35x + 7 = 77

x = 200

Thus statements I and III both are required to answer the question.

Using statement II alone or with any other statement we cannot find the answer.

Hence, option D is right answer.

Volume of the sphere of 20 cm radius = $\dfrac{4\pi}{3}\times 20^3$ = $\dfrac{32000\pi}{3}$
Volume of right-circular cone whose height is 20cm and radius of circular base is 15 cm.= $\dfrac{\pi}{3}\times 25^2*60$ = $12500\pi$
Hence, we can say that Quantity 1 < Quantity 2. Option C is the correct answer.

The lengths 140 cm, 280 cm and 420 cm should be the multiples of the length of the rod. The maximum possible length of the rod will be equal to the HCF of these 3 numbers.

140 = 2*70
280 = 4*70
420 = 6*70

As we can see, the HCF is 2*70 = 140 cm.
Therefore, option B is the right answer.

Simple interest paid to bank = 1000*.22*2 = Rs. 440
Compound interest paid to bank = $1000(1 + \dfrac{20}{100})^2 – 1000$ = Rs. 440
Hence, we can say that Quantity 1 = Quantity 2. Option E is the correct answer.

Monthly average of A = $\dfrac{10000 * 4}{12}$ = Rs. $\dfrac{10000}{3}$

Monthly average of C = $\dfrac{10000 * 12}{12}$ Rs. 10000

So, monthly average of A is $\frac{1}{3}$ of the monthly average of C

So, A’s profit = $\frac{1}{3}$ of C’s profit = Rs. 400

Hence, option B is the correct answer.

Let 1 bottle of apple juice fill ‘a’ glasses and 1 bottle of mango juice fill ‘m’ glasses.
We have 5a + 9m = 71 and 7a + 11m = 93.
Solving we get a = 7 and m = 4.
So 3 bottles of apple juice and 4 bottles of mango juice will fill = 7*3 + 4*4 = 37 glasses
Hence, option A is the right choice.

A can do the work in 20 days

B can do the work in 25 days

C can do the work in 40 days

Total work = LCM of 20,25,40 $=$ 200 units

Efficiency of A $=$ $\Large\frac{200}{20}$ $=$ 10 units/day

Efficiency of B $=$ $\Large\frac{200}{25}$ $=$ 8 units/day

Efficiency of C $=$ $\Large\frac{200}{40}$ $=$ 5 units/day

Let the number of days required to complete the work be ‘X’ days

Total work done by A in X days $=$ 10 $\times$ X $=$ 10X units

Total work done by C in X days $=$ 5 \times X $=$ 5X days

B left 4 days before completion

Total work done by B in (X – 4) days $=$ 8(X – 4) $=$ (8X – 32) units

$\therefore$ 10X + 5X + 8X – 32 $=$ 200

23X – 32 $=$ 200

$\therefore$ X $=$ $\Large\frac{232}{23}$ $=$ 10$\Large\frac{2}{23}$ days

7*4+5 = 28+5 = 33
33*4+5 = 132+5 = 137
137*4+5 = 548+5 = 553
553*4+5 = 2212+5 = 2217
2217*4+5 = 8868+5 = 8873
Hence, 8871 must be replaced by 8873

When a dice is rolled we get outcome from (1,2,3,4,5,6) so favourable cases (Sum = 2,3,4)
Favourable cases = (1,1) (1,2) (2,1) (1,3) (3,1) (2,2)
Total cases = 6*6 = 36
So probability $= \frac{ \text{Favourable cases}}{\text{Total cases}}$
$= \frac{6}{36} =\frac{1}{6}$

Let us assume that on a normal day he sells milk at x rupee per litre and he sells y litre of milk
So revenue generated on normal day = x*y = xy

He mixed water with milk in ratio of 2:5 so net quantity = $\frac{2+5}{5} * y$ = 1.4y
New selling price during summer = 1.2x rupees per litre

So revenue generated in summers = 1.4y * 1.2x = 1.68xy
Hence we can say that revenue will go up by 68 percent.

7 = 1 + 1 + 5 = 2 + 2 + 3 = 3 + 3 + 1 = 1 + 2 + 4
Thus, the probability that sum of the number on the faces of the dice is 7 = (3C1+3C1+3C1+3!)/216 = 15/216 = X
10 = 6 + 3 + 1 = 6 + 2 + 2 = 5 + 3 + 2 = 4 + 4 + 2 = 4 + 3 + 3 = 1 + 4 + 5
Thus, the probability that sum of the number on the faces of the dice is 14 = (3C1+3C1+3C1+3!)/216 = 15/216 = Y
Hence, X=Y
Hence, option E is the correct answer.

Let us check the options.
Option (A): Average cost price of the mixture = $\dfrac{200+560+1260}{2+4+7}$ = Rs. 155.38
Option (B): Average cost price of the mixture = $\dfrac{100+700+1800}{1+5+10}$ = Rs. 162.50
Option (C): Average cost price of the mixture = $\dfrac{100+280+540}{1+2+3}$ = Rs. 153.33
Option (D): Average cost price of the mixture = $\dfrac{200+700+900}{2+5+5}$ = Rs. 150
Therefore, option D is the correct answer.

Let the distance between Ram’s office and home = 150d
Then his original speed = $\frac{150d}{30}$ = 5d

Distance that Ram covered at (1/3)rd of original distance = $\frac{150d}{3}$ = 50d
(4/5)th of original speed = $\frac{4}{5} * 5d$ = 4d
Time taken by Ram to cover this distance = $\frac{50d}{4d} = 12.5$minutes

Remaining distance = 150d – 50d = 100d
(2/5)th of original speed = $\frac{2}{5}*5d$ = 2d
Time taken by Ram to cover the remaining distance = $\frac{100d}{2d}$ = 50 minutes

Hence total time taken by Ram = 12.5 + 50 = 62.5 minutes

Length = 5 m , Breadth = 3 m and Height = 8 m

To find the cost of painting the walls of the room, we should know the cost of painting and the area of door and window.

Area of 4 walls (Curved Surface Area of cuboid) = $2h(l+b)$

= $(2 \times 8)(5+3) = 16 \times 8 = 128$ $m^2$

From I & II : Cost = Rs 25 per square meter

Area of window = $2.25$ $m^2$

and Area of door = $2 \times 2.25 = 4.5$ $m^2$

Thus, area to be painted = $128 – 2.25 – 4.5 = 121.25$ $m^2$

$\therefore$ Cost of painting 4 walls = $25 \times 121.25 = Rs$ $3031.25$

Thus, statement III is redundant.

=> Ans – (C)

Let ‘x’ be the number of students who took all the three electives and ‘y’ be the number of students who took only management as an elective.
We get following venn diagram –

Considering students who took management as an elective we have,

y + x + 84 + 75 = 238

x + y = 79

Considering students who took history as an elective we have,

137 – y + x + 84 + 52 = 240

y – x = 33

Adding both the equation we get,

2y = 112

y = 56

So, x = 23

So, number of students who took all the three electives = 23

Number of students who took only management = 56

Number of students who took only history = 137 – 56 = 81

So, the number of students who took only physics = 450 – 240 – 56 – 75 = 79

Thus, we get following venn diagram –

Number of students who selected both management and physics as elective = 75 + 23 = 98
Hence, option E is the correct choice.

We hope this Expected Quant Question & Answers PDF of SBI PO is very Useful for preparation of SBI PO Exams.