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# Divisibility Questions for SSC CGL PDF

Download SSC CGL Divisibility Questions & answers PDF. Top 10 SSC CGL questions based on asked questions in previous exam papers very important for the SSC exam.

Question 1: Simplify : $5 – 6.5 \div 13 + 2.3 \times 0.8 + 0.4$

a) 6.83

b) 6.74

c) 7.38

d) 5.38

Question 2: Simplify: $8+3-\left(\frac{5}{2}\times\frac{1}{3}\right) of \frac{12}{5}+\frac{4}{3}\times\frac{3}{8}$

a) 9.5

b) 10

c) 9

d) 19

Question 3: $\frac{4}{7} of \frac{8}{9} \div \frac{8}{7} \times 180 of \frac{1}{9} = ?$

a) $\frac{20}{9}$

b) $\frac{9}{20}$

c) $\frac{80}{9}$

d) $\frac{9}{80}$

Question 4: What value should come in place of the question mark (?) in the following questions?
$31 \div 3 \times 15 = ?$

a) 180

b) 140

c) 165

d) 155

Question 5: What is the value of $\left[22\frac{3}{4}\div\frac{14}{3}of\left(8-\frac{1}{5}+4-2\div\frac{1}{2}\right)\right]$?

a) $\frac{3}{7}$

b) $\frac{91}{213}$

c) $\frac{5}{8}$

d) $\frac{91}{199}$

Question 6: The value of:
$4 \div 2 + 3 \times 6 – 7$ is:

a) 13

b) 14

c) 11

d) 12

Question 7: The value of $24 \div 4 \times (3 + 3) \div 2$ is:

a) 22

b) 24

c) 20

d) 18

Question 8: Find the value of:
$(11 + 4) – 9 \times 1 \div 3$ of $4$

a) $\frac{75}{4}$

b) $\frac{57}{4}$

c) $5$

d) $3$

Question 9: $11^2 + 11^4 \div 11^3 of 11 – 11$= ?

a) 111

b) 121

c) 131

d) 101

Question 10: What approximate value should come in place of the question mark (?) in the following questions?
$21 + 68 \div 17 = ?$

a) 25

b) 35

c) 40

d) 10

=$5 – 6.5 \div 13 + 2.3 \times 0.8 + 0.4$
=$5 – 0.5 + 2.3 \times 0.8 + 0.4$
=$5 – 0.5 + 1.84 + 0.4$
=$4.5 1.84 + 0.4$
=6.74

=$8+3-\left(\frac{5}{2}\times\frac{1}{3}\right) of \frac{12}{5}+\frac{4}{3}\times\frac{3}{8}$
=$8+3-2+\frac{4}{3}\times\frac{3}{8}$
=$8+3-2+\frac{1}{2}$
=9.5

By using BODMAS we have
=$(32/63)\div(8/7)\times20$
=$(32/63)\times(7/8)\times20$
=$(4/9)\times20$
=80/9

By applying BODMAS we have
$(31/3)\times 15$
=$31\times 5$
=155

$\left[22\frac{3}{4}\div\frac{14}{3}of\left(8-\frac{1}{5}+4-2\div\frac{1}{2}\right)\right] = \dfrac{91}{4} \times \dfrac{3}{14} \times \dfrac{5}{39} = \dfrac{5}{8}$

$4 \div 2 + 3 \times 6 – 7 = 2+18-7 = 13$

$24 \div 4 \times (3 + 3) \div 2 = \dfrac{24}{4} \times \dfrac{6}{2} = 18$

$(11 + 4) – 9 \times 1 \div 3$ of $4 = 15-9\times\dfrac{1}{3\times4} = 15-\dfrac{3}{4} = \dfrac{57}{4}$

By simplifying we get 121+1-11

=122-11
=111

=$21+(68\div17)$