Divisibility Questions for SSC CGL PDF
Download SSC CGL Divisibility Questions & answers PDF. Top 10 SSC CGL questions based on asked questions in previous exam papers very important for the SSC exam.
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Question 1: Simplify : $5 – 6.5 \div 13 + 2.3 \times 0.8 + 0.4$
a) 6.83
b) 6.74
c) 7.38
d) 5.38
Question 2: Simplify: $8+3-\left(\frac{5}{2}\times\frac{1}{3}\right) of \frac{12}{5}+\frac{4}{3}\times\frac{3}{8}$
a) 9.5
b) 10
c) 9
d) 19
Question 3: $\frac{4}{7} of \frac{8}{9} \div \frac{8}{7} \times 180 of \frac{1}{9} = ?$
a) $\frac{20}{9}$
b) $\frac{9}{20}$
c) $\frac{80}{9}$
d) $\frac{9}{80}$
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Question 4: What value should come in place of the question mark (?) in the following questions?
$31 \div 3 \times 15 = ?$
a) 180
b) 140
c) 165
d) 155
Question 5: What is the value of $\left[22\frac{3}{4}\div\frac{14}{3}of\left(8-\frac{1}{5}+4-2\div\frac{1}{2}\right)\right]$?
a) $\frac{3}{7}$
b) $\frac{91}{213}$
c) $\frac{5}{8}$
d) $\frac{91}{199}$
Question 6: The value of:
$4 \div 2 + 3 \times 6 – 7$ is:
a) 13
b) 14
c) 11
d) 12
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Question 7: The value of $24 \div 4 \times (3 + 3) \div 2$ is:
a) 22
b) 24
c) 20
d) 18
Question 8: Find the value of:
$(11 + 4) – 9 \times 1 \div 3$ of $4$
a) $\frac{75}{4}$
b) $\frac{57}{4}$
c) $5$
d) $3$
Question 9: $11^2 + 11^4 \div 11^3 of 11 – 11 $= ?
a) 111
b) 121
c) 131
d) 101
Question 10: What approximate value should come in place of the question mark (?) in the following questions?
$21 + 68 \div 17 = ? $
a) 25
b) 35
c) 40
d) 10
Answers & Solutions:
1) Answer (B)
=$5 – 6.5 \div 13 + 2.3 \times 0.8 + 0.4$
=$5 – 0.5 + 2.3 \times 0.8 + 0.4$
=$5 – 0.5 + 1.84 + 0.4$
=$4.5 1.84 + 0.4$
=6.74
2) Answer (A)
=$8+3-\left(\frac{5}{2}\times\frac{1}{3}\right) of \frac{12}{5}+\frac{4}{3}\times\frac{3}{8}$
=$8+3-2+\frac{4}{3}\times\frac{3}{8}$
=$8+3-2+\frac{1}{2}$
=9.5
3) Answer (C)
By using BODMAS we have
=$(32/63)\div(8/7)\times20$
=$(32/63)\times(7/8)\times20$
=$(4/9)\times20$
=80/9
4) Answer (D)
By applying BODMAS we have
$(31/3)\times 15$
=$31\times 5$
=155
5) Answer (C)
$\left[22\frac{3}{4}\div\frac{14}{3}of\left(8-\frac{1}{5}+4-2\div\frac{1}{2}\right)\right] = \dfrac{91}{4} \times \dfrac{3}{14} \times \dfrac{5}{39} = \dfrac{5}{8}$
6) Answer (A)
$4 \div 2 + 3 \times 6 – 7 = 2+18-7 = 13$
7) Answer (D)
$24 \div 4 \times (3 + 3) \div 2 = \dfrac{24}{4} \times \dfrac{6}{2} = 18$
8) Answer (B)
$(11 + 4) – 9 \times 1 \div 3$ of $4 = 15-9\times\dfrac{1}{3\times4} = 15-\dfrac{3}{4} = \dfrac{57}{4}$
9) Answer (A)
By simplifying we get 121+1-11
=122-11
=111
10) Answer (A)
By applying BODMAS we have
=$21+(68\div17)$
=21+4
=25
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