# Clocks Questions for IIFT PDF

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## Clocks Questions for IIFT PDF

Download important IIFT Clocks Questions PDF based on previously asked questions in IIFT and other MBA exams. Practice Clocks questions and answers for IIFT exam.

Practice IIFT Mock Tests

Question 1: An antique store has a collection of eight clocks. At a particular moment, the displayed times on seven of the eight clocks were as follows: 1:55 pm, 2:03 pm, 2:11 pm, 2:24 pm, 2:45 pm, 3:19 pm and 4:14 pm. If the displayed times of all eight clocks form a mathematical series, then what was the displayed time on the remaining clock?

a) 1:53 pm

b) 1:58 pm

c) 2:18 pm

d) 3:08 pm

e) 5:08 pm

Question 2: Alarms from 3 different clocks sound after every 2, 4 and 6 hours, respectively. If the clocks are started at the same time, how many times do the alarms ring together in 3 days?

a) 6

b) 3

c) 9

d) 2

Question 3: What would be the smaller of the two angles formed by the hour hand and the minute hand at 4 : 52 p.m.?

a) $162^\circ$

b) $164.5^\circ$

c) $165^\circ$

d) $166^\circ$

Question 4: What is the obtuse angle formed by the hands of a clock when the time in the clock is 2:30?

a) $95^\circ$

b) $120^\circ$

c) $105^\circ$

d) $165^\circ$

Question 5: In Ravi’s clock shop, two clocks were brought for repairs. One clock has the cuckoo coming out every sixteen minutes, while the other one has the cuckoo coming out every eighteen minutes. Both cuckoos come out at 12.00 noon. When will they both come out together again?

a) 2.06 PM

b) 2.08 PM

c) 2.24 PM

d) 2.32 PM

Question 6: The time in a clock is 20 minutes past 2. Find the angle between the hands of the clock.

a) 45 degrees

b) 50 degrees

c) 60 degrees

d) 120 degrees

Question 7: A clock gains five minutes every hour. What will be the angle traversed by the second hand in one minute?

a) 360o

b) 360.5o

c) 390o

d) 380o

Question 8: After 9’O clock at what time between 9 p.m. and 10 p.m. will the hour and minute hands of a clock point in opposite direction?

a) 15 minutes past 9

b) 16 minutes past 9

c) $(\frac{180}{11})$ minutes past 9

d) $(\frac{190}{11})$ minutes past 9

Question 9: The angle between the minute hand and hour hand of a clock when the time is 7:20 is equal to

a) $45^\circ$

b) $90^\circ$

c) $100^\circ$

d) $120^\circ$

Question 10: If a clock is kept on the table in such a way that at 3:10 pm the hour hand points south, after how much time will the minute hand point east?

a) 20 minutes

b) 35 minutes

c) 50 minutes

d) 90 minutes

Let us find out the difference between the times given to figure out the pattern.
The times given are 1:55 pm, 2:03 pm, 2:11 pm, 2:24 pm, 2:45 pm, 3:19 pm and 4:14 pm.
The difference between 2 consecutive times given are  8 minutes, 8 minutes, 13 minutes, 21 minutes, 34 minutes, and 55 minutes.
We can observe that the difference between the times are in the Fibonacci series.
8 + 13 = 21
21 + 13 = 34
34 + 21 = 55

The Fibonacci series is as follows:
1,1,2,3,5,8,13,21,34,55.
But the first difference in the times given is 8.
Therefore, the missing time must be such that it divides the interval of 8 minutes into 3 minutes and 5 minutes.
The missing time should be 1:58 pm and hence, option B is the right answer.

If we take the LCM of 2, 4 and 6 hours then got 12 hours.

In 12 hours alarms ring simultaneously once.

It means 12 hours = 1.

Hence 3 days = 72 hours = 6.

Angle between the hands of a clock is given by the formula $\dfrac{11}{2}H – 30M$ or $30M – \dfrac{11}{2}H$ where H is hours and M is minutes.
Here, Given time = 02 : 30, H = 2 and M = 30.
Angle = $\dfrac{11}{2} \times 30 – 30 \times 2 = 165 – 60 – 105^\circ$

Time after cuckoo comes in first clock = 16 min

Time after cuckoo comes in second clock = 18 min

=> Time after cuckoo will come together in both = L.C.M. (16,18)

= 144 min = 2 : 24 min

=> They will both come out together again = 12 + 2:24 = 2:24 PM

Hour hand will cover 360 degrees in 12 hours. Thus, 1 hour = 30 degrees.
In 2 hour 20 minutes i.e. in 2.33 hours it will cover 2.33*30 = 70 degrees.
Minute hand will cover 360 degrees in 1 hours. Thus, in 20 minutes it will cover 120 degrees.
Thus, the angle between the hour hand and the minute hand at 2 hour twenty minutes = 120-70 = 50 degrees.
Hence, option B is the correct answer.

This clock moves 65 minutes for every 60 minutes.

=> Each hand moves = $\frac{65}{60}$ as far as it should.

A correct second hand moves $360^\circ$ in one minute.

=> This second hand moves = $\frac{65}{60}\times360^\circ=390^\circ$ in one minute.

=> Ans – (C)

Hour hand’s speed is $\frac{1}{2} ^o$ per min.
And minute hand’s speed is $6^o$ per minute
So relative speed of minute hand will be $6^o$ – $\frac{1}{2} ^o$ = $\frac{11}{2}$ per minute
Hence time taken to make an angle of $180^o$ in between will be = $\frac{90}{\frac{11}{2}}$ (As at 9:00 o’clock angle between them is already $90^o$ )
So time will be $\frac{180}{11}$ minutes passed 9

Angle between hour hand and minute hand = |30*H – $\frac{11}{2}$*M|

where, H -> hour and M -> minutes

So, at 7:20 => H = 7 & M = 20

=> Angle = 30*7 – $\frac{11}{2}$*20

= 210-110 = 100°