# Averages Questions for RBI Exam

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RBI Assistant exam prelims consists of 35 questions from numerical ability section. From this quant section 1 or 2 questions will be asked in the exam. We are providing a set of solved questions on averages for RBI exam. This solved questions and answers will be useful for other banking exams like SBI, IBPS (PO and clerk) exams.

Averages Questions for RBI Exam:

Question 1:

The average weight of 15 girls was recorded as 54 kg. If the weight of the teacher was added the average increased by 2 kg What was the teacherâ€™s weight ?

a) 75 kg
b) 95 kg
c) 78 kg
d) 86 kg
e) None of these

Question 2:

The average of four consecutive numbers A,B,C and D respectively is 56.5 What is the product of A and C ?

a) 3363
b) 3306
c) 3192
d) 3080
e) None of these

Question 3:

A, B, C and D are four consecutive even numbers respectively and their average is 65. What is the product of A and D ?

a) 3968
b) 4216
c) 4092
d) 4352
e) None of these

Question 4:

The sum of five numbers is 555. The average of first two numbers is 75 and the third number of 115. What is the average of last two numbers ?

a) 145
b) 290
c) 265
d) 150
e) None of these

Question 5:

In a one-day cricket match the captain of one of the teams scored 30 runs more than the average runs scored by the remaining six batsmen of that team who batted in the match. If the total runs scored by all the batsman of that team were 310, how many runs did the captain score ?

a) 60
b) 70
c) 50
d) Cannot be determined
e) None of these

Answers and Solutions for Averages Questions for RBI Exam:

Solutions:

The average weight of 15 girls is 54 kgs.
Therefore, total weight = 810
Now, after adding teachers weight the average increase to 56 kgs
Let teachers weight be x.
(810+x)/16 = 56
x= 86
The teachers weight is 86 kgs.
The correct option is option D.

Let A = x
B= x+1
C= x+2
D=x+3
Now, average = 56.5
(A+B+C+D)/4 = 56.5
4x +6 = 56.5*4
4x +6 = 226
4x = 220
x = 55
Therefore A,B,C and D are 55,56,57 and 58 respectively.
Product of A and C = 55*57 = 3135

As, A is the smallest even number of the four,
B = A+2
C = B+2 = A+4
D = C+2 = A+6
Hence, their sum is A + (A+2) + (A+4) + (A+6) = 4A + 12
And their average is (4A+12)/4 = A + 3
This equals 65.
So, A = 62 and D = A+6 = 68
Their product equals 62*68 = 4216

Let the five numbers be A,B,C,D and E.
So, A+B+C+D+E = 555
A+B = 75*2 = 150
C = 115
Hence, D+E = 555-150-115 = 290 and their average equals 145