Arithmetic Questions for Railway Exams PDF
Download Top-15 Railway Exams Arithmetic Questions PDF. Railway Exams Arithmetic questions based on asked questions in previous exam papers very important for the Railway exams.
Download Arithmetic Questions for Railway Exams PDF
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Question 1: 36% of 4800 x 0.2% of 1320 =?
a) 4535.52
b) 4551.36
c) 4561.92
d) 4572.48
Question 2: Evaluate :- $\frac{16 \times2^{n+1 }-4\times2^{n}}{16\times 2^{n+2}-2\times2^{n+2}}$
a) $\frac{1}{2}$
b) $0$
c) $4$
d) $\frac{1}{3}$
Question 3: $\sqrt{6400}$ = ?
a) 40
b) 80
c) 60
d) None of these
Question 4: 3251 + 587 + 369 – ? = 3007
a) 1250
b) 1300
c) 1375
d) 1200
Question 5: The square root of 19881 is:
a) 149
b) 129
c) 141
d) 131
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Question 6: Find the square root of 15625 ?
a) 125
b) 145
c) 150
d) 135
Question 7: Which of the following is NOT a perfect square?
a) 1250
b) 16641
c) 2025
d) 9801
Question 8: Select the option that can replace the question mark (?) in the following equation.
$ 2 + 5\div [5+8\div( 1+\frac{1}{3}) – 1] $ = ?
a) $ \frac{1}{2} $
b) $ \frac{5}{2} $
c) $ \frac{3}{2} $
d) 2
Question 9: $ 4 + \frac{1}{6} \times $ [ { $ – 12 \times ( 24 – 13 – 3) $ } $ \div ( 20 – 4) $ ] = ?
a) 4
b) 6
c) 5
d) 3
Question 10: If $ \sqrt{(x-1) +(y+2)} = 7 $ , then find the values of x and y.
a) 12, 16
b) 8, 5
c) 15, 12
d) 50, 47
RRB Group D previous year papers
Question 11: If $x = \left(\sqrt{2} + 1\right)^{\frac{-1}{3}}$, then find the value of $x^3 – \frac{1}{x^3}$.
a) $\sqrt3$
b) -2
c) 0
d) 2
Question 12: If the midvalue of a class is 20 and the width of the class is 5, find the lower and upper limits of the class.
a) 17 – 23
b) 17 – 22
c) 17.5 – 22.5
d) 18 – 22
Question 13: Find the value of $5y \sqrt{y^3 – y^2}$ when $y = 5$
a) 500
b) 250
c) $50\sqrt{2}$
d) 50
Question 14: simplify $\sqrt{25+10\sqrt{6}}+ \sqrt{25-10\sqrt{6}}$?
a) $2\sqrt{15}$
b) $2\sqrt{5}$
c) $\sqrt{50}$
d) $\sqrt{55}$
Question 15: $45-[38-(80\div4-(8-12\div3)\div4)]=?$
a) 25
b) 27
c) 26
d) 28
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Answers & Solutions:
1) Answer (C)
36% of 4800 = 1728
.2% of 1320 = 2.64
So, 36% of 4800 * .2% of 1320 = 1728 *2.64 = 4561.92
2) Answer (A)
$\frac{16 \times2^{n+1 }-4\times2^{n}}{16\times 2^{n+2}-2\times2^{n+2}}$
=$\frac{2^{n}(32-4)}{2^{n+2}(16-2)}$
=$\frac{28}{4(14)}$=$\frac{1}{2}$
3) Answer (B)
$ \sqrt{6400} = \sqrt {80 \times 80} $ = 80
4) Answer (D)
Let’s assume ? = Y.
3251 + 587 + 369 – Y = 3007
4207 – Y = 3007
4207 – 3007 = Y
Y = 1200
5) Answer (C)
$\sqrt{\ 19881}=141$
Hence option ‘C’ is correct.
6) Answer (A)
For finding square root, first obtain the multiple of a number.
15625 = $5\times5\times5\times5\times5\times5$
Now pairing the number and got $5\times5\times5$. Which is equal to 125.
7) Answer (A)
1250 (It is not a perfect square of any number.)
16641 (It is a perfect square of 129.)
2025 (It is a perfect square of 45.)
9801 (It is a perfect square of 99.)
8) Answer (B)
= $ 2 + 5\div [5+8\div( 1+\frac{1}{3}) – 1] $
= $ 2 + 5\div [5+8\div( \frac{4}{3}) – 1] $
= $ 2 + 5\div [5+8 \times \frac{3}{4} – 1] $
= $ 2 + 5\div 10 $
= $ \frac{5}{2} $
Hence, option B is the correct answer.
9) Answer (D)
$ 4 + \frac{1}{6} \times $ [ { $ – 12 \times ( 24 – 13 – 3) $ } $ \div ( 20 – 4) $ ]
=$ 4 + \frac{1}{6} \times $ [ { $ – 12 \times 8 $ } $ \div 16 $ ]
=$ 4 + \frac{1}{6} \times -6$
=4-1
=3
10) Answer (B)
11) Answer (B)
12) Answer (C)
13) Answer (B)
Substituting y=5
Equation becomes
$ 5 \times 5 \sqrt{5^3-5^2} $
$ = 25 \sqrt{125-25} $
$ = 25 \sqrt{100} $
$ = 25 \times 10 $
=250
14) Answer (A)
15) Answer (C)
$45-[38-(80\div4-(8-12\div3)\div4)] = 45 – (38 – (20 – \dfrac{8-4}{4}))$
$= 45 – (38 -(20-\dfrac{4}{4})) = 45-(38-(20-1))$
$= 45-(38-19) = 45-19 = 26$
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