Algebra Questions for CMAT 2022 – Download PDF
Download CMAT 2022 Algebra Questions pdf by Cracku. Very Important Algebra Questions for CMAT 2022 based on asked questions in previous exam papers. These questions will help your CMAT preparation. So kindly download the PDF for reference and do more practice.
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Question 1: If
a) 4
b) 0
c) 2
d) -2
Question 2: If
a)
b)
c) 3
d) 2
Question 3: If
a) -6
b) 9
c) 6
d) -9
Question 4: If
a) 105
b) -102
c) -104
d) 103
Question 5: If
a) 2
b) 4
c) 1
d) 3
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Question 6: If a + 3b = 12 and ab = 9, then the value of (a – 3b) is:
a) 9
b) 8
c) 6
d) 4
Question 7: If
a) a = -6 and b = -11
b) a = -11 and b = 6
c) a = 11 and b = -6
d) a = 6 and b = 11
Question 8: If a + b + c + d = 2, then the maximum value of (1 + a)(1 + b)(1 + c)(1 + d) is
a)
b)
c)
d)
Question 9: If
a) 16
b) 196
c) 194
d) 14
Question 10: If x – y = 13 and xy = 25, then the value of
a)
b)
c)
d)
Question 11: 2x — 3y is a factor of:
a)
b)
c)
d)
Question 12: If a and b are two positive real numbers such that a + b = 20 and ab = 4, then the value of
a) 7760
b) 8000
c) 8240
d) 240
Question 13: If x + y = 15 and xy = 14, then the value of x — y is:
a) 13
b) 12
c) 11
d) 14
Question 14: If a = 355, b = 356, c = 357,then find the value of
a) 3204
b) 3206
c) 3202
d) 3208
Question 15: If
a) 36
b) 64
c) 81
d) 100
Question 16: If
a) 344
b) 96
c) 224
d) 152
Question 17: The coefficient of y in the expansion of
a) 150
b) 50
c) -30
d) -150
Question 18: The given table represents the revenue (in ₹ crores) of a company from the sale of four products A, B, C and D in 6 years. Study the table carefully and answer the question that follows. By what percentage is the total revenue of the company from the sale of products A, B and D in 2012 and 2013 more than the total revenue from the sale of product B in 2013 to 2016?(Correct to one decimal place)
a) 44.5
b) 31.2
c) 43.6
d) 45.4
Question 19: If
a) 18
b) 23
c) 31
d) 19
Question 20: Solve the following:
(a + b + c)(ab + bc + ca) – abc = ?
a) (a + b)(b + c)(c – a)
b) (a + b)(b – c)(c + a)
c) (a + b)(b + c)(c + a)
d) (a – b)(b – c)(c – a)
Question 21: If
a) -80
b) -72
c) 72
d) 48
Question 22: If
a)
b)
c) 1
d) 0
Question 23: On simplification,
a) 4
b) 1
c)
d)
Question 24: If
a)
b)
c)
d)
Question 25: For real a, b, c if
a) 3
b) 1
c) 2
d) 0
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Answers & Solutions:
1) Answer (C)
Given,
Hence, the correct answer is Option C
2) Answer (B)
Given,
Hence, the correct answer is Option B
3) Answer (D)
Given,
Hence, the correct answer is Option D
4) Answer (B)
Given,
Hence, the correct answer is Option B
5) Answer (D)
Given,
Hence, the correct answer is Option D
6) Answer (C)
Given,
Hence, the correct answer is Option C
7) Answer (C)
Given,
Let the quotient when
Comparing both sides,
Hence, the correct answer is Option C
8) Answer (D)
Given, a + b + c + d = 2
We know that, AM
Hence, the correct answer is Option D
9) Answer (C)
Given,
Hence, the correct answer is Option C
10) Answer (C)
Given,
Hence, the correct answer is Option C
11) Answer (A)
Hence, the correct answer is Option A
12) Answer (A)
Given,
Hence, the correct answer is Option A
13) Answer (A)
Given,
Hence, the correct answer is Option A
14) Answer (A)
Given,
Hence, the correct answer is Option A
15) Answer (A)
Given,
Hence, the correct answer is Option A
16) Answer (D)
Given,
Hence, the correct answer is Option D
17) Answer (A)
=
The coefficient of y = 150
18) Answer (D)
Total revenue of the company from the sale of products A, B and D in 2012 and 2013 = 98 + 74 + 74 + 94 + 96 + 102 = 538
Total revenue from the sale of product B in 2013 to 2016 = 96 + 92 + 84 + 98 = 370
Required percentage =
19) Answer (D)
=
= 19(121
20) Answer (C)
(a + b + c)(ab + bc + ca) – abc
=
=
=
=
= (b + c)[a(a + b) + c(a + b)]
= (a + b)(b + c)(c + a)
21) Answer (A)
by comparison –
A = -8
B = -8
C = 64
The value of
22) Answer (B)
x + y = 8 —-(1)
y + z = 13 —-(2)
z + x = 17 —-(3)
Eq (1) + (2) + (3),
2(x + y + z) = 8 + 13 + 17
x + y + z = 38/2 = 19 —-(4)
From eq (3) and (4),
x + 13 = 19
x = 6
From eq(3),
z + x = 17
z + 6 = 17
z = 11
From eq(2),
y + z = 13
y + 11 = 13
y = 2
=
= 36/22 = 18/11
23) Answer (A)
=
=
=
24) Answer (D)
It will be zero, if the individual terms will be zero.
So,
So,
Now,
Now substituting the values in the above,
25) Answer (C)
Given,
Multiplying both sides by “2”, it becomes
Sum of squares is zero so each term should be zero
Therefore