**Time and Work Questions for SSC-CGL PDF**

Download SSC CGL Time and Work Questions with answers PDF based on previous papers very useful for SSC CGL exams. Very important Time and Work Questions for SSC exams.

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**Question 1: **A and B can do a piece of work in 4 days and C and D in 3 days. In how many days will A, B, C and do it together?

a) $\frac{12}{7}$ days

b) $\frac{7}{12}$ days

c) $\frac{2}{3}$ days

d) $\frac{3}{2}$ days

**Question 2: **A alone can complete a work in 10 days and B alone can complete the same work in 20 days. In how many days both 4 and B together can complete half of the total work?

a) $\frac{40}{3} days$

b) $\frac{20}{3} days$

c) $\frac{10}{3} days$

d) $\frac{25}{3} days$

**Question 3: **P and Q together can complete a work in 20 days. If P alone can complete the same work in 36 days, then in how many days Q alone can complete the same work?

a) 48 days

b) 42 days

c) 45 days

d) 51 days

**Question 4: **Pipe C can fill a tank in 12 hours and pipe D can fill the same tank in 40 hours. In how many hours both pipe C and D together can fill the same tank?

a) $\frac{60}{7} hours$

b) $\frac{60}{11} hours$

c) $\frac{120}{13} hours$

d) $\frac{120}{11} hours$

**Question 5: **M can complete a work in 14 days less than the time taken by L. If both M and L together can complete the same work in 24 days, then in how many days L alone can complete the same work?

a) 35 days

b) 56 days

c) 21 days

d) 42 days

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**Question 6: **If C alone can complete two-third part of a work in 12 days, then in how many days C can complete the whole work?

a) 24 days

b) 15 days

c) 8 days

d) 18 days

**Question 7: **A train is moving at the speed of 20 m/sec. If the length of train is 540 metres, then how much time will it take to cross a pole?

a) 108 seconds

b) 81 seconds

c) 27 seconds

d) 54 seconds

**Question 8: **A train covers a certain distance at a speed of 45 m/s in 15 minutes. How much time it will take to cover the same distance at the speed of 60 m/s?

a) 3.25 minutes

b) 4.75 minutes

c) 6.75 minutes

d) 11.25 minutes

**Question 9: **A 250 metre long train takes 30 seconds to cross a 350 metres long bridge. How much time train will take to cross a 550 metre long bridge?

a) 38 seconds

b) 42 seconds

c) 40 seconds

d) 35 seconds

**Question 10: **A pipe can fill a cistern in 20 minutes whereas the cistern when full can be emptied by a leak in 28 minutes. When both are opened,the time taken to fill the cistern is:

a) 48 min

b) 70 min

c) 80 min

d) 60 min

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**Answers & Solutions:**

**1) Answer (A)**

Time taken for both ‘A’ and ‘B’ to do the work is 4 days

i.e (1/a)+(1/b)=1/4

Time taken for both ‘C’ and ‘D’ to do the same work is 3 days.

(1/c)+(1/d)=1/3

For all of them to complete the work by working together let it take ‘x’ days

(1/x)=(1/a)+(1/b)+(1/c)+(1/d)

(1/x)=(1/4)+(1/3)

(1/x)=(3+4)/(12)

(1/x)=7/12

x=12/7 days

**2) Answer (C)**

Let the total work be 20 units (LCM of 10 and 20)

Efficiency of A = 20/10 = 2 units per day

Efficiency of B = 20/20 = 1 unit per day

Total efficiency of A and B = 3 units per day

Half of the work = 20/2 = 10 units.

Hence, 10 units can be completed by A and B together in $\dfrac{10}{3}$ days.

**3) Answer (C)**

Let the total work be 180 units (LCM of 20 and 36)

Efficiency of P+Q = 180/20 = 9 units per day

Efficiency of P = 180/36 = 5 units per day

Then, Efficiency of Q = 9-5 = 4 units per day

Therefore, Q can do the work together in 180/4 = 45 days

**4) Answer (C)**

Let the total capacity of the tank be 120 units (LCM of 12 and 40)

Efficiency of Pipe C = 120/12 = 10 units per hour

Efficiency of Pipe D = 120/40 = 3 units per hour

Total efficiency of Pipe C and D together = 13 units per hour

Therefore, 120 units of tank can be filled in $\dfrac{120}{13}$ hours

**5) Answer (B)**

Let the number of days taken by L to complete the work be L days

Then, 1 day work of L = $\dfrac{1}{L}$

Number of days taken by M to complete the work = L-14 days

Then, 1 day work of M = $\dfrac{1}{L-14}$

Given, $\dfrac{1}{L} + \dfrac{1}{L-14} = \dfrac{1}{24}$

=> $\dfrac{2L-14}{L^2-14L} = \dfrac{1}{24}$

=> $L^2 – 62L + 336 = 0$

=> $L^2 – 6L-56L+336 = 0$

=> $L(L-6)-56(L-6) = 0$

=> $(L-56)(L-6) = 0$

=> L = 56 or L = 6

Since, M can do the work 14 days less than L, L cannot be 6.

Hence, L can do the work in 56 days.

**6) Answer (D)**

Given, C can complete $\dfrac{2}{3}rd$ part of work in 12 days.

$\dfrac{2}{3} –> 12$

$1 –> ?$

Total work will be completed in $1\times\dfrac{12}{2}\times3 = 18$ days

**7) Answer (C)**

Given that the speed of the train = 20 m/sec

Length of the train = 540 m

Time required to cross a pole is the time time required to cross its length = $\dfrac{540}{20} = 27$ seconds

**8) Answer (D)**

Given, Speed of the train = 45 m/sec

Time taken to cover a certain distance = 15 minutes = 15*60 = 900 seconds

Then, Distance travelled by the train = 45*900 = 40500 m

New speed = 60 m/sec

Then, Time taken to travel 39500 m = $\dfrac{40500}{60} = 675$ seconds = $\dfrac{675}{60} = 11.25$ minutes

**9) Answer (C)**

Length of the train = 250 m

Length of the first bridge = 350 m

Total distance to be travelled to cross the bridge = 250+350 = 600 m

Then, Speed of the train = $\dfrac{600}{30} = 20 m/sec$

Length of the second bridge = 550 m

Total distance = 550+250 = 800 m

Then, Time taken = $\dfrac{800}{20} = 40$ seconds

**10) Answer (B)**

Let the capacity of the cistern be 140 units.

Efficiency of pipe = 140/20 = 7 units per minute

Efficiency of leakage = 140/-28 = -5 units per minute

Then, When both are opened, the cistern can be filled at 2 units per minute.

Therefore, 140 units can be filled in 140/2 = 70 minutes.

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