Time and Distance Questions for Bank Exams PDF:
Time and Distance Questions And Answers for Banking exams of IBPS, SBI PO & Clerk, RBI with solutions. Practice questions on time and distance based on previous papers for bank exams.
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Question 1:Â A train covers 480 km in 8 hours. The speed of a car is 5/6th of the train and the speed of a bike is 4/5th of a car. Find the distance covered by a bike in 9 hours.
b) 360 km
c) 400 km
d) 440 km
a) 72 km/hr
b) 60 km/hr
c) 68 km/hr
d) cannot determined
e) None of these
Question 3: A boat takes 2 hours to travel from point A to B in still water .To find out it’s speed up-stream ,which of the following information is needed.
i. Distance between point A and B
Ii.Time taken to travel down stream from B to A
iii. Speed of the stream of the water
iv. Effective speed of Boat while traveling Downstream from B to A
a) All are required
b) Even these we cannot found the answer
c) Only i,iii, and either ii or iv
d) Only i and iii
e) None of these
a) 12 hours
b) 20 hours
c) 18 hours
d) 15 hours
e) 24 hours
a) 210 m
b) 175 m
c) 150 m
d) 160 m
e) 140 m
a) 10:15:30
b) 10:17:48
c) 10:19:20
d) 10:18:15
e) 10:16:12
a) 20 seconds
b) 25 seconds
c) 36 seconds
d) 40 seconds
e) 50 seconds
a) 4 km
b) 8 km
c) 12 km
d) 16 km
e) They will meet at B.
a) 5 hour 30 minutes
b) 5 hour 15 minutes
c) 5 hour 12 minutes
d) 5 hour 7.5 minutes
e) 5 hour 20 minutes
a) 3:4
b) 3:7
c) 4:7
d) 5:9
e) 4:9
Speed of car = (5/6)*60 = 50 kmph.
Speed of bike = (4/5)*50 = 40 kmph.
Distance travelled by bike in 9 hours = 40*9 = 360 km.
Let speed of bus = $s$ km/hr
Distance covered = 2924 km
Time taken = 43 hours
Using speed = distance/time
=> $s=\frac{2924}{43}=68$ km/hr
=> Ans – (C)
Time taken by boat to travel from point A to B in still water = 2 hours
To find the upstream speed, we definitely need the speed of stream, thus statement (iii) is mandatory.
Also, the distance between points A and B or the speed of boat in still water is needed.
Thus, statements (i) and (iii) are required to find the upstream speed of the boat.
=> Ans – (D).
Hence, 9x = 18
=> x = 2
Now while coming back the speed of the stream has doubled. So it has become 4. He will now be rowing upstream. So effective speed will be 16 – 4 = 12
Hence, required time = 180/12 = 15 hours
Thus, we can say that the ratio of the speeds of all three people will be 25:20:17
Hence, the ratio of the speeds of Raman and Sumit is 25:17.
Hence, in the time that Raman travels 500 m, Sumit will travel 340 m. Thus, Raman will beat Sumit by 160 m.
So the inlet pipe fills 5 litres per minutes and outlet pipe empties 3 litres per minute. For the first 5 minutes only inlet pipe is operating. Hence, it will fill 25 litres. For the next 8 minutes, only 2 litres is being filled per minute. Hence, at 10:13, 41 litres water will be there in the tank. Now 19 litres can be filled by the inlet pipe in 4 minutes and 48 seconds. Thus, the tank will be completely filled at 10:17:48.
Let the length of first train be 2l. So the length of second train will be l.
Speed of second train = 90*.8 = 72 km/hr = 20 m/s
Hence, total distance travelled in 20 s = 45*20 = 900 m
3l = 900 m
=> l = 300 m
Hence, the length of first train is 600 m.
Time taken to cross a platform of length 300 m = 900 / 25 = 36 seconds.
Hence, option C is the correct answer.
It has been given that P and Q meet for the first time 12km from A. Therefore, their speeds are in the ratio 12:8 or 3:2.
After they meet for the first time, they have to cover 40 km together. Therefore, both P and Q will travel twice as much distance as they travelled before the first meeting point. P will have to cover 24 km. In total, P would have covered 12 km (before the first meeting) + 24 km (After the first meeting)= 36 km. Therefore, P will be 4 km shy of A. The meeting point is located 20 – 4 km = 16 km from B. Therefore, option D is the right answer.
Let the distance between the starting point and the movie hall be ‘d’.
A drops B at the movie hall. By this time, A would have covered a distance of ‘d’.
Then, A returns and meets C. Let the distance of the point at which A and C meet be ‘t’ from the movie hall.
Then, A and C reach the movie hall.
Total distance walked by C = d-t.
Total distance travelled by A = d + t +t = d + 2t.
It has been given that d+2t = 1.8d
=> t = 0.4d
By the time A covered a distance of d+t, C covered a distance of d-t.
A covered 1.4d in the time C covered 0.6d.
Therefore, the ratio of the speeds is 0.6d:1.4d = 3:7.
Therefore, option B is the right answer.
After 3 hours, A would have travelled 3*18 = 54 km.
B would have travelled 3*12 = 36 km.
B must cover the 54 – 36 = 18 km using relative speed.
B will travel the next 2 hours at 24 kmph.
Therefore, after 5 hours, A would have covered 5*18 = 90 km.
B would have covered 3*12 + 2*24 = 36+48 = 84 km.
Now, B will start traveling at 48 kmph.
In an hour, B will travel 48-18 = 30 km more than A.
B has to travel only 6 kms more than A. B can accomplish this in 60/5 = 12 minutes.
Therefore, B will overtake A after 5 hour 12 minutes. Therefore, option C is the right answer.
