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SSC CGL Questions on Remainder

Download SSC CGL Questions on Remainder  PDF based on previous papers very useful for SSC CGL exams. Remainder Questions for SSC exams.

Question 1: A number, when divided by 114, leaves remainder 21. If the same number is divided by 19, then the remainder will be

a) 1

b) 2

c) 7

d) 17

Question 2: A number, when divided by 136, leaves remainder 36. If the same number is divided by 17, the remainder will be

a) 9

b) 7

c) 3

d) 2

Question 3: A positive integer when divided by 425 gives a remainder 45. When the same number is divided by 17, the remainder will be

a) 11

b) 8

c) 9

d) 10

Question 4: When $2^{33}$ is divided by 10, the remainder will be

a) 2

b) 3

c) 4

d) 8

Question 5: A positive integer when divided by 425 gives a remainder 45. When the same number is divided by 17, the remainder will be

a) 11

b) 8

c) 9

d) 10

Question 6: When a number is divided by 56, the remainder will be 29. If the same number is divided by 8, then the remainder will be

a) 6

b) 7

c) 5

d) 3

Question 7: If a perfect square, not divisible by 6, be divided by 6, the remainder will be

a) 1, 3 or 5

b) 1, 2 or 5

c) 1, 3 or 4

d) 1, 2 or 4

Question 8: A number, when divided by 296, gives 75 as the remainder. Ifthesamenumberis divided by 37 then the remainder will be

a) 1

b) 2

c) 19

d) 31

Question 9: The sum of the digits of a two-digit number is $\frac{1}{7}$ of the number. The units digit is 4 less than the tens digit. If the number obtained on reversing its digits is divided by 7, the remainder will be:

a) 4

b) 5

c) 1

d) 6

Question 10: A number is divided by 52, we get 27 as remainder. On dividing the same number by 13, What will be the remainder?

a) 2

b) 7

c) 1

d) None of these

Let the given number be x
Let a be the quotient when x is divided by 114
So $\frac{x}{114}$ = a$\frac{21}{114}$
so x = 114a + 21
when x is divided by 19 it can be written as
$\frac{x}{19} = \frac{114a + 21}{19}$
114 is divisible by 19 and 21 leaves a remainder of 2.

Number will be (136n + 36) where n is quotient
hence when it is divided by 17 remainder for $\frac{136n +36}{17}$ will be 2 as 136 is divisible by 17 and 36=34+2

Let the number be 45.

So, when 45 is divided by 425, the remainder is 45 and quotient is 0.

Now, when 45 is divided by 17, we get

quotient = 2

remainder = 11

$\frac{2^{33}}{10}$ = > $\frac{8^{11}}{10}$ => $\frac{-2^{11}}{10}$

= > $\frac{1024 \times -2}{10}$

= > $\frac{12}{10}$ –> remainder 2

Let the number be 45

So, when 45 is divided by 425 => remainder = 45

Now, when 45 is divided by 17

=> Remainder = 45%17 = 11

When the number is divided by 56, remainder is 29

=> Let the number = 56+29 = 85

Now, if 85 is divided by 8, => $85=8\times 10+5$

Thus, remainder = 5

=> Ans – (C)

=> Number is of the form = $52k+27$
When above number is divided by 13, => $\frac{(52k+27)}{13}$
$\because$ 52 is a multiple of 13, => $27\%13=1$